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MHT CET 2025 (23 Apr, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2025 (23 Apr, Shift 1)

Q22MHT CET 2025 · 23 APR · SHIFT 1Easy

Self-Inductance & Energy

When a current in the conducting coil is changed from 5 A in one direction to 5 A in opposite direction in 0.5 second, an average induced e.m.f in the coil is 2 V. The selfinductance of the coil is

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Answer: (d)

  1. ∣e∣=LΔIΔt|e| = L\frac{\Delta I}{\Delta t}, with ΔI=5−(−5)=10 A\Delta I = 5 - (-5) = 10\text{ A}.
  2. 2=L×100.5=20L2 = L \times \frac{10}{0.5} = 20L
  3. L=0.1 H=100 mHL = 0.1\text{ H} = 100\text{ mH}
  4. So the answer is (d) 100 mH.
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