When a current of 1 A is passed through a coil of 100 turns, the flux associated with it is 2.5 × 10⁻⁵ Wb/ turn. The self inductance of the coil in millihenry is (a) 40 (b) 25 (c) 4 (d) 2.5

Answer: (d). L = (Nφ)/(I) L = 100 × 2.5×10⁻⁵1 = 2.5×10⁻³ H L = 2.5 mH, so the answer is (d).

When a current of 1 A is passed through a coil of 100 turns, the flux… | MHT CET 2023 (11 May, Shift 1)

Q53MHT CET 2023 · 11 MAY · SHIFT 1Easy

Self-Inductance & Energy

When a current of $1\text{ A}$ is passed through a coil of 100 turns, the flux associated with it is $2.5 \times 10^{-5}\text{ Wb/}$ turn. The self inductance of the coil in millihenry is

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Answer: (d)

$L = \frac{N\phi}{I}$
$L = \frac{100 \times 2.5\times10^{-5}}{1} = 2.5\times10^{-3}\text{ H}$
$L = 2.5\text{ mH}$ , so the answer is (d).

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