Student Login

Home›Chapters›Current Electricity PYQs›Kirchhoff's Laws & Measuring Instruments›Question 173

JEE Main 2017 · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2017

Q173JEE Main 2017Easy

Kirchhoff's Laws & Measuring Instruments

When a current of 5 mA is passed through a galvanometer having a coil of resistance 15 $\Omega$ , it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 0 – 10V is:

Show answer and solution

Answer: (b)

Series resistance $R = \frac{V}{I_g} - G$ .
$R = \frac{10}{5 \times 10^{-3}} - 15 = 2000 - 15 = 1985\ \Omega = 1.985 \times 10^3\ \Omega$
So the answer is (b).

Report a mistake

More questions on Kirchhoff's Laws & Measuring Instruments

In the given circuit, the current in each resistance is:JEE Main 2017
A galvanometer having a coil resistance of 100 Ω gives a full scale deflection, when a…JEE Main 2016
The potential difference (VA - VB) between the points A and B in the given figure isNEET 2016 (Phase 2)
A galvanometer has a 50 division scale. Battery has no internal resistance. It is found…JEE Main 2016 (10 Apr, Shift 1)
A 50 Ω resistance is connected to a battery of 5 V. A galvanometer of resistance 100 Ω is…JEE Main 2016 (9 Apr, Shift 1)
In the circuit shown, the current in the 1 Ω resistor is:JEE Main 2015
In the electric network shown, when no current flows through the 4 Ω resistor in the arm…JEE Main 2015 (11 Apr, Shift 1)
A, B and C are voltmeters of resistance R, 1.5 R and 3R respectively as shown in the…NEET 2015 (AIPMT, Cancelled Paper)