Physics Circle home Student Login

Home›Chapters›Alternating Current PYQs›RL and RC Series Circuits›Question 31

JEE Main 2024 (6 Apr, Shift 1) · RL and RC Series Circuits

RL and RC Series Circuits question from JEE Main 2024 (6 Apr, Shift 1)

Q31JEE Main 2024 · 6 APR · SHIFT 1Medium

RL and RC Series Circuits

When a dc voltage of 100 V100\text{ V} is applied to an inductor, a dc current of 5 A5\text{ A} flows through it. When an ac voltage of 200 V200\text{ V} peak value is connected to inductor, its inductive reactance is found to be 203 Ω20\sqrt{3}\ \Omega. The power dissipated in the circuit is _________ W.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 250

  1. DC gives resistance: R=1005=20 ΩR = \frac{100}{5} = 20\ \Omega.
  2. Z=202+(203)2=40 ΩZ = \sqrt{20^2 + (20\sqrt{3})^2} = 40\ \Omega
  3. Irms=V0/2Z=200402=52 AI_{rms} = \frac{V_0/\sqrt{2}}{Z} = \frac{200}{40\sqrt{2}} = \frac{5}{\sqrt{2}}\text{ A}
  4. P=Irms2R=252×20=250 WP = I_{rms}^2 R = \frac{25}{2} \times 20 = 250\text{ W}
Report a mistake

More questions on RL and RC Series Circuits