When a dipole placed parallel to electric field is rotating through πc, the work done is W. The work done in rotating the dipole through (π/3)c is ( cos 0° = 1, cos 60° = 1/2, cos 180° = -1) (a) W/4 (b) W/2 (c) W (d) 2W

Answer: (a). Work from the parallel position: Wθ = pE(1 - cos θ). θ = π: W = pE(1 + 1) = 2pE θ = π/3: W' = pE(1 - 1/2) = pE/2 = W/4 So the answer is (a) W/4.

When a dipole placed parallel to electric field is rotating through… | MHT CET 2026 (18 Apr, Shift 1)

Q10MHT CET 2026 · 18 APR · SHIFT 1Medium

Electric Dipole

When a dipole placed parallel to electric field is rotating through $\pi^c$ , the work done is W. The work done in rotating the dipole through $\left(\frac{\pi}{3}\right)^c$ is

( $\cos 0^\circ = 1,\ \cos 60^\circ = \frac{1}{2},\ \cos 180^\circ = -1$ )

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Answer: (a)

Work from the parallel position: $W_\theta = pE(1 - \cos\theta)$ .
$\theta = \pi$ : $W = pE(1 + 1) = 2pE$
$\theta = \frac{\pi}{3}$ : $W' = pE\left(1 - \frac{1}{2}\right) = \frac{pE}{2} = \frac{W}{4}$
So the answer is (a) $\frac{W}{4}$ .

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Electric Dipole question from MHT CET 2026 (18 Apr, Shift 1)

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