When a hydrogen atom is raised from the ground state to the excited state (a) potential energy increases and K.E. decreases. (b) potential energy decreases and K.E. increases. (c) both K.E. and potential energy will increase. (d) both K.E. and potential energy decreases.

Answer: (a). KE = (ke²)/(2r) and PE = -ke²/r. In an excited state r is larger: KE falls, PE becomes less negative (increases). So the answer is (a) potential energy increases and K.E. decreases.

When a hydrogen atom is raised from the ground state to the excited… | MHT CET 2024 (9 May, Shift 1)

Q13MHT CET 2024 · 9 MAY · SHIFT 1Easy

Energy of the Electron & Energy Levels

When a hydrogen atom is raised from the ground state to the excited state

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Answer: (a)

$KE = \frac{ke^2}{2r}$ and $PE = -\frac{ke^2}{r}$ .
In an excited state $r$ is larger: KE falls, PE becomes less negative (increases).
So the answer is (a) potential energy increases and K.E. decreases.

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