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MHT CET 2025 (21 Apr, Shift 2) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from MHT CET 2025 (21 Apr, Shift 2)

Q43MHT CET 2025 · 21 APR · SHIFT 2Medium

Photoelectric Effect: Einstein's Equation

When a light of wavelength λ\lambda falls on the emitter of a photocell, maximum speed of emitted photoelectrons is V. If the incident wavelength is changed to 2λ3\frac{2\lambda}{3}, maximum speed of emitted photoelectrons will be:

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Answer: (d)

  1. 12mV2=hcλ−ϕ\frac{1}{2}mV^2 = \frac{hc}{\lambda} - \phi
  2. At 2λ3\frac{2\lambda}{3}: 12mV′2=1.5hcλ−ϕ=1.5(hcλ−ϕ)+0.5ϕ\frac{1}{2}mV'^2 = 1.5\frac{hc}{\lambda} - \phi = 1.5\left(\frac{hc}{\lambda} - \phi\right) + 0.5\phi
  3. So V′2>1.5V2⇒V′>V(1.5)1/2V'^2 > 1.5V^2 \Rightarrow V' > V(1.5)^{1/2}
  4. None of the options says 'greater than'; the nearest is (d) 32 V\sqrt{\frac{3}{2}}\,V (exact only if ϕ\phi is neglected).
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