Physics Circle home Student Login

Home›Chapters›Work, Energy and Power PYQs›Spring & Elastic Energy›Question 31

NEET 2003 (AIPMT) · Spring & Elastic Energy

Spring & Elastic Energy question from NEET 2003 (AIPMT)

Q31NEET 2003 · AIPMTEasy

Spring & Elastic Energy

When a long spring is stretched by 2 cm, its potential energy is U. If the spring is stretched by 10 cm, the potential energy stored in it will be

Show answer and solution

Answer: (d)

  1. U=12kx2⇒U∝x2U = \frac{1}{2}kx^2 \Rightarrow U \propto x^2.
  2. U′U=(102)2=25\frac{U'}{U} = \left(\frac{10}{2}\right)^2 = 25
  3. So the answer is (d) 25U25U.
Report a mistake

More questions on Spring & Elastic Energy