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NEET 2016 (Phase 1) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from NEET 2016 (Phase 1)

Q141NEET 2016 · PHASE 1Medium

Photoelectric Effect: Einstein's Equation

When a metallic surface is illuminated with radiation of wavelength λ\lambda, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 λ\lambda, the stopping potential is V4\frac{V}{4}. The threshold wavelength for the metallic surface is

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Answer: (b)

  1. Einstein: hcλ=ϕ+eVs\frac{hc}{\lambda} = \phi + eV_s; write A=hcλA = \frac{hc}{\lambda}.
  2. A−ϕ=eVA - \phi = eV and A2−ϕ=eV4\frac{A}{2} - \phi = \frac{eV}{4}
  3. A−ϕ=4(A2−ϕ)=2A−4ϕ⇒ϕ=A3A - \phi = 4\left(\frac{A}{2} - \phi\right) = 2A - 4\phi \Rightarrow \phi = \frac{A}{3}
  4. λ0=hcϕ=3λ\lambda_0 = \frac{hc}{\phi} = 3\lambda
  5. So the answer is (b) 3λ3\lambda.
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