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JEE Main 2026 (22 Jan, Shift 2) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from JEE Main 2026 (22 Jan, Shift 2)

Q10JEE Main 2026 · 22 JAN · SHIFT 2Medium

Angle of Contact & Capillarity

When a part of a straight capillary tube is placed vertically in a liquid, the liquid raises upto certain height hh. If the inner radius of the capillary tube, density of the liquid and surface tension of the liquid decrease by 1%1\% each, then the height of the liquid in the tube will change by ‾ %\underline{\qquad}\ \%.

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Answer: (b)

  1. h=2Tcos⁡θrρg⇒Δhh=ΔTT−Δrr−Δρρh = \frac{2T\cos\theta}{r\rho g} \Rightarrow \frac{\Delta h}{h} = \frac{\Delta T}{T} - \frac{\Delta r}{r} - \frac{\Delta \rho}{\rho}
  2. Δhh=(−1)−(−1)−(−1)=+1%\frac{\Delta h}{h} = (-1) - (-1) - (-1) = +1\%
  3. So the answer is (b) +1%+1\%.
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