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JEE Main 2022 (26 Jul, Shift 1) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from JEE Main 2022 (26 Jul, Shift 1)

Q49JEE Main 2022 · 26 JUL · SHIFT 1Easy

Velocity & Acceleration in SHM

When a particle executes Simple Harmonic Motion, the nature of graph of velocity as a function of displacement will be:

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Answer: (b)

  1. v=ωA2−x2⇒v2=ω2(A2−x2)v = \omega\sqrt{A^2 - x^2} \Rightarrow v^2 = \omega^2(A^2 - x^2).
  2. x2A2+v2ω2A2=1\frac{x^2}{A^2} + \frac{v^2}{\omega^2A^2} = 1, an ellipse with semi-axes AA and ωA\omega A.
  3. So the answer is (b) Elliptical.
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