When a rubber ball is taken to a depth of __________m in deep sea, its volume decreases by 0.5%. (The bulk modulus of rubber = 9.8 × 108 Nm ⁻², Density of sea water = 103 kgm ⁻³, g = 9.8 m/s2) Numerical answer type. Work it out, then open the answer.

Answer: 500. (Δ V)/(V) = (ρ g h)/(B) ⇒ h = (B (Δ V/V))/(ρ g) h = 9.8 × 10⁸ × 0.00510³ × 9.8 = 4.9 × 10⁶9.8 × 10³ h = 500 m

When a rubber ball is taken to a depth of __________m in deep sea… | JEE Main 2021 (31 Aug, Shift 1)

Q19JEE Main 2021 · 31 AUG · SHIFT 1Medium

Density, Compressibility & Pascal's Law

When a rubber ball is taken to a depth of __________m in deep sea, its volume decreases by 0.5%. (The bulk modulus of rubber = 9.8 $\times$ 108 Nm ${}^{-2}$ , Density of sea water = 103 kgm ${}^{-3}$ , g = 9.8 m/s2)

Numerical answer type. Work it out, then open the answer.

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Answer: 500

$\dfrac{\Delta V}{V} = \dfrac{\rho g h}{B} \Rightarrow h = \dfrac{B\,(\Delta V/V)}{\rho g}$
$h = \dfrac{9.8 \times 10^{8} \times 0.005}{10^{3} \times 9.8} = \dfrac{4.9 \times 10^{6}}{9.8 \times 10^{3}}$
$h = 500$ m

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