When an electron does transition from n = 4 to n = 2, then emitted line spectrum will be (a) first line of Lyman series (b) second line of Balmer series (c) first line of Balmer series (d) second line of Paschen series.

Answer: (b). Ending on n = 2 gives the Balmer series. 3 → 2 is the first line, so 4 → 2 is the second line. So the answer is (b) second line of Balmer series.

When an electron does transition from n = 4 to n = 2, then emitted… | NEET 2000 (AIPMT)

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Hydrogen Spectrum & Spectral Series

When an electron does transition from n = 4 to n = 2, then emitted line spectrum will be

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Answer: (b)

Ending on $n = 2$ gives the Balmer series.
$3 \to 2$ is the first line, so $4 \to 2$ is the second line.
So the answer is (b) second line of Balmer series.

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Hydrogen Spectrum & Spectral Series question from NEET 2000 (AIPMT)

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