When an electron is accelerated through a potential ' V ', the de-Broglie wavelength associated with it is ' 4λ '. When the accelerating potential is increased to 4 V, its wavelength will be (a) (λ)/(4) (b) (λ)/(2) (c) λ (d) 2λ

Answer: (d). λ ∝ 1/√(V). At V the wavelength is 4λ; at 4V it is (4λ)/(√(4)) = 2λ. So the answer is (d) 2λ.

When an electron is accelerated through a potential ' V ', the… | MHT CET 2023 (12 May, Shift 2)

Q64MHT CET 2023 · 12 MAY · SHIFT 2Easy

Matter Waves: de Broglie Wavelength

When an electron is accelerated through a potential ' $V$ ', the de-Broglie wavelength associated with it is ' $4\lambda$ '. When the accelerating potential is increased to $4\ \mathrm{V}$ , its wavelength will be

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Answer: (d)

$\lambda \propto \dfrac{1}{\sqrt{V}}$ .
At $V$ the wavelength is $4\lambda$ ; at $4V$ it is $\dfrac{4\lambda}{\sqrt{4}} = 2\lambda$ .
So the answer is (d) $2\lambda$ .

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