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MHT CET 2026 (20 Apr, Shift 1) · RL and RC Series Circuits

RL and RC Series Circuits question from MHT CET 2026 (20 Apr, Shift 1)

Q6MHT CET 2026 · 20 APR · SHIFT 1Medium

RL and RC Series Circuits

When an inductance 'LL' and resistor 'RR' are connected in series to 2525V, 5050 Hz supply, a current of 0.50.5 A flows in the circuit. The current lags behind in phase from applied voltage by (π3)\left(\frac{\pi}{3}\right) radian. The value of R is (cos⁡60∘=12)\left(\cos 60^\circ = \frac{1}{2}\right)

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Answer: (b)

  1. Z=VI=250.5=50 ΩZ = \frac{V}{I} = \frac{25}{0.5} = 50\ \Omega
  2. cos⁡ϕ=RZ⇒R=Zcos⁡60∘=50×12=25 Ω\cos\phi = \frac{R}{Z} \Rightarrow R = Z\cos 60^\circ = 50 \times \frac{1}{2} = 25\ \Omega
  3. So the answer is (b) 25 Ω25\ \Omega.
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