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NEET 2016 (Phase 1) · Atomic Models & Alpha-Particle Scattering

Atomic Models & Alpha-Particle Scattering question from NEET 2016 (Phase 1)

Q12NEET 2016 · PHASE 1Easy

Atomic Models & Alpha-Particle Scattering

When an $\alpha$ -particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach from the nucleus depends on m as

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Answer: (c)

At closest approach all KE becomes PE: $\frac{1}{2}mv^2 = \dfrac{k(2e)(Ze)}{r_0}$ .
$r_0 = \dfrac{4kZe^2}{mv^2}$ , so for fixed $v$ , $r_0 \propto \dfrac{1}{m}$ .
So the answer is (c) $\frac{1}{m}$ .

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