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MHT CET 2019 (3 May, Shift 1) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from MHT CET 2019 (3 May, Shift 1)

Q132MHT CET 2019 · 3 MAY · SHIFT 1Medium

Photoelectric Effect: Einstein's Equation

When certain metal surface is illuminated with a light of wavelength λ\lambda, the stopping potential is VV, When the same surface is illuminated by light of wavelength 2λ2\lambda, the stopping potential is (V3)\left(\frac{V}{3}\right). The threshold wavelength for the surface is

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Answer: (c)

  1. Einstein: hcλ=ϕ+eVs\frac{hc}{\lambda} = \phi + eV_s; write A=hcλA = \frac{hc}{\lambda}.
  2. A−ϕ=eVA - \phi = eV and A2−ϕ=eV3\frac{A}{2} - \phi = \frac{eV}{3}
  3. A−ϕ=3A2−3ϕ⇒ϕ=A4A - \phi = \frac{3A}{2} - 3\phi \Rightarrow \phi = \frac{A}{4}
  4. λ0=4λ\lambda_0 = 4\lambda
  5. So the answer is (c) 4λ4\lambda.
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