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JEE Main 2024 (6 Apr, Shift 2) · Kinetic Energy & Momentum

Kinetic Energy & Momentum question from JEE Main 2024 (6 Apr, Shift 2)

Q5JEE Main 2024 · 6 APR · SHIFT 2Easy

Kinetic Energy & Momentum

When kinetic energy of a body becomes 36 times of its original value, the percentage increase in the momentum of the body will be:

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Answer: (b)

  1. p=2mKp = \sqrt{2mK}, so p∝Kp \propto \sqrt{K}.
  2. K′=36K⇒p′=6pK' = 36K \Rightarrow p' = 6p
  3. Increase =6p−pp×100=500%= \frac{6p - p}{p} \times 100 = 500\%, so the answer is (b).
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