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NEET 1993 (AIPMT) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from NEET 1993 (AIPMT)

Q172NEET 1993 · AIPMTEasy

Photoelectric Effect: Einstein's Equation

When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters?

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Answer: (b)

  1. Taking each wavelength as threshold, ϕ=hcλ0∝1λ0\phi = \dfrac{hc}{\lambda_0} \propto \dfrac{1}{\lambda_0}
  2. ϕ1ϕ2=600300=2\dfrac{\phi_1}{\phi_2} = \dfrac{600}{300} = 2
  3. So the answer is (b) 2:12:1.
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