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MHT CET 2025 (26 Apr, Shift 1) · Mutual Inductance

Mutual Inductance question from MHT CET 2025 (26 Apr, Shift 1)

Q18MHT CET 2025 · 26 APR · SHIFT 1Easy

Mutual Inductance

When magnetic flux changes from 6.5×10−2 Wb6.5 \times 10^{-2}\text{ Wb} to 11×10−2 Wb11 \times 10^{-2}\text{ Wb} and the change in current is 0.03 A, the coefficient of mutual inductance will be

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Answer: (c)

  1. M=ΔΦΔIM = \dfrac{\Delta\Phi}{\Delta I}
  2. M=(11−6.5)×10−20.03=4.5×10−23×10−2=1.5M = \dfrac{(11 - 6.5)\times 10^{-2}}{0.03} = \dfrac{4.5\times 10^{-2}}{3\times 10^{-2}} = 1.5 H
  3. So the answer is (c) 1.5 H.
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