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NEET 2010 (AIPMT, Mains) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from NEET 2010 (AIPMT, Mains)

Q70NEET 2010 · AIPMT · MAINSEasy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

When monochromatic radiation of intensity $I$ falls on a metal surface, the number of photoelectrons and their maximum kinetic energy are N and T respectively. If the intensity of radiation is 2 $I$ , the number of emitted electrons and their maximum kinetic energy are respectively

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Answer: (b)

Number of photoelectrons $\propto$ intensity: $I \to 2I$ gives $N \to 2N$ .
$K_{max} = h\nu - \phi$ is independent of intensity: $T$ stays $T$ .
So the answer is (b) $2N$ and $T$ .

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