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MHT CET 2025 (25 Apr, Shift 2) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from MHT CET 2025 (25 Apr, Shift 2)

Q25MHT CET 2025 · 25 APR · SHIFT 2Medium

Angle of Contact & Capillarity

When one end of a capillary tube is dipped in water, the height of water column is ' hh '. The upward force of 105 dyne due to surface tension is balanced by the force due to the weight of water column. The inner circumference of the capillary tube is

(Surface tension of water =7×10−2 N/m= 7 \times 10^{-2}\text{ N/m})

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Answer: (a)

  1. Upward force F=T×LF = T \times L (θ=0\theta = 0).
  2. L=105×10−57×10−2=1.5×10−2 mL = \frac{105\times10^{-5}}{7\times10^{-2}} = 1.5\times10^{-2}\text{ m}
  3. So the answer is (a) 1.5 cm1.5\text{ cm}.
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