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MHT CET 2025 (26 Apr, Shift 2) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from MHT CET 2025 (26 Apr, Shift 2)

Q24MHT CET 2025 · 26 APR · SHIFT 2Medium

Angle of Contact & Capillarity

When one end of the capillary is dipped in water, the height of water column is ' hh '. The upward force of 108 dyne due to surface tension is balanced by the force due to the weight of water column. The inner circumference of the capillary is (surface tension of water =7.2×10−2 N/m= 7.2 \times 10^{-2}\text{ N/m})

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Answer: (d)

  1. Upward force F=T×LF = T \times L (θ=0\theta = 0).
  2. L=108×10−57.2×10−2=1.5×10−2 mL = \frac{108\times10^{-5}}{7.2\times10^{-2}} = 1.5\times10^{-2}\text{ m}
  3. So the answer is (d) 1.5 cm1.5\text{ cm}.
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