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MHT CET 2025 (22 Apr, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2025 (22 Apr, Shift 2)

Q40MHT CET 2025 · 22 APR · SHIFT 2Medium

Matter Waves: de Broglie Wavelength

When the electron orbiting in hydrogen atom goes from one orbit to another orbit (principal quantum number =n= n ), the de-Broglie wavelength ( λ\lambda) associated with it is related to nn as

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Answer: (d)

  1. Bohr condition: 2πrn=nλ⇒λ=2πrnn2\pi r_n = n\lambda \Rightarrow \lambda = \dfrac{2\pi r_n}{n}.
  2. rn∝n2r_n \propto n^2, so λ∝n2n=n\lambda \propto \dfrac{n^2}{n} = n (equivalently v∝1/nv \propto 1/n).
  3. So the answer is (d) λ∝n\lambda \propto n.
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