When the heat is given to a gas in an Isothermal process, then there will be (a) external work done. (b) rise in temperature. (c) increase in internal energy. (d) external work done and also rise in temperature.

Answer: (a). Isothermal: Δ T = 0, so Δ U = 0. First law: Q = Δ U + W = W; all heat goes into external work. No rise in temperature and no change in U. So the answer is (a) external work done.

When the heat is given to a gas in an Isothermal process, then there… | MHT CET 2025 (19 Apr, Shift 1)

Q61MHT CET 2025 · 19 APR · SHIFT 1Easy

Thermodynamic Processes

When the heat is given to a gas in an Isothermal process, then there will be

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Answer: (a)

Isothermal: $\Delta T = 0$ , so $\Delta U = 0$ .
First law: $Q = \Delta U + W = W$ ; all heat goes into external work.
No rise in temperature and no change in $U$ .
So the answer is (a) external work done.

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