When the number of turns in a coil is doubled without any change in the length of the coil, its self- inductance (a) becomes 4 times. (b) becomes 2 times. (c) gets halved. (d) remains unchanged.

Answer: (a). L = (μ₀ N² A)/(l) ∝ N² for fixed l and A. N' = 2N ⇒ L' = 4L So the answer is (a) becomes 4 times.

When the number of turns in a coil is doubled without any change in… | MHT CET 2024 (11 May, Shift 1)

Q40MHT CET 2024 · 11 MAY · SHIFT 1Easy

Self-Inductance & Energy

When the number of turns in a coil is doubled without any change in the length of the coil, its self- inductance

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Answer: (a)

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