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JEE Main 2019 (9 Jan, Shift 1) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2019 (9 Jan, Shift 1)

Q161JEE Main 2019 · 9 JAN · SHIFT 1Medium

Kirchhoff's Laws & Measuring Instruments

When the switch S, in the circuit shown, is closed, then the value of current i will be:

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Answer: (b)

With S closed, C connects to ground through $2\ \Omega$ . Let $V_C = V$ .
KCL at C: $\frac{20 - V}{2} + \frac{10 - V}{4} = \frac{V}{2}$
Multiply by 4: $40 - 2V + 10 - V = 2V \Rightarrow V = 10\text{ V}$
$i = \frac{10}{2} = 5\text{ A}$
So the answer is (b) 5A.

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