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MHT CET 2026 (19 May, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2026 (19 May, Shift 1)

Q4MHT CET 2026 · 19 MAY · SHIFT 1Easy

Thermodynamic Processes

When the temperature of 4 moles of a gas was increased from $70^\circ$ C to $90^\circ$ C, at constant volume, the change in internal energy was $60$ J. The total heat capacity of the gas at constant volume is

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Answer: (c)

At constant volume, $\Delta U = C_V^{total}\,\Delta T$ .
$\Delta T = 90 - 70 = 20$ K
$C_V^{total} = \frac{60}{20} = 3$ J/K
So the answer is (c) $3$ J/K.

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