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JEE Main 2020 (3 Sep, Shift 1) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from JEE Main 2020 (3 Sep, Shift 1)

Q124JEE Main 2020 · 3 SEP · SHIFT 1Medium

Photoelectric Effect: Einstein's Equation

When the wavelength of radiation falling on a metal is changed from 500 nm to 200 nm, the maximum kinetic energy of the photoelectrons becomes three times larger. The work function of the metal is close to:

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Answer: (c)

  1. Photon energies (hc=1240hc = 1240 eV nm): 1240500=2.48\frac{1240}{500} = 2.48 eV, 1240200=6.2\frac{1240}{200} = 6.2 eV.
  2. 3(2.48−ϕ)=6.2−ϕ⇒7.44−3ϕ=6.2−ϕ3(2.48 - \phi) = 6.2 - \phi \Rightarrow 7.44 - 3\phi = 6.2 - \phi
  3. 2ϕ=1.24⇒ϕ≈0.622\phi = 1.24 \Rightarrow \phi \approx 0.62 eV
  4. So the answer is (c) 0.61 eV.
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