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MHT CET 2023 (13 May, Shift 2) · Beats

Beats question from MHT CET 2023 (13 May, Shift 2)

Q42MHT CET 2023 · 13 MAY · SHIFT 2Medium

Beats

When two tuning forks are sounded together, 5 beats per second are heard. One of the forks is in unison with 0.97 m0.97\text{ m} length of sonometer wire and the other is in unison with 0.96 m0.96\text{ m} length of the same wire. The frequencies of the two tuning forks are

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Answer: (d)

  1. f∝1Lf \propto \dfrac{1}{L}: f1×0.97=f2×0.96f_1 \times 0.97 = f_2 \times 0.96, with f2−f1=5f_2 - f_1 = 5.
  2. f1(0.970.96−1)=5⇒f1=5×0.960.01=480 Hzf_1\left(\dfrac{0.97}{0.96} - 1\right) = 5 \Rightarrow f_1 = \dfrac{5 \times 0.96}{0.01} = 480\text{ Hz}
  3. f2=485 Hzf_2 = 485\text{ Hz}
  4. So the answer is (d) 480 Hz, 485 Hz.
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