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JEE Main 2005 (AIEEE) · Beats

Beats question from JEE Main 2005 (AIEEE)

Q71JEE Main 2005 · AIEEEEasy

Beats

When two tuning forks (fork $1$ and fork $2$ ) are sounded simultaneously, $4$ beats per second are heated. Now, some tape is attached on the prong of the fork $2$ When the tuning forks are sounded again, $6$ beats per second are heard. If the frequency of fork $1$ is $200\text{ Hz}$ , then what was the original frequency of fork $2$ ?

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Answer: (d)

4 beats with 200 Hz, so $n_2 = 204$ or $196\text{ Hz}$ .
Tape (loading) lowers $n_2$ , and the beats rise from 4 to 6.
Beats rise only if $n_2$ moves away from 200, so $n_2 < 200$ : $196 \to 194\text{ Hz}$ gives 6 beats.
So the answer is (d) $196\text{ Hz}$ .

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