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JEE Main 2013 (9 Apr, Shift 1) · Nuclear Fission & Fusion

Nuclear Fission & Fusion question from JEE Main 2013 (9 Apr, Shift 1)

Q25JEE Main 2013 · 9 APR · SHIFT 1Easy

Nuclear Fission & Fusion

When Uranium is bombarded with neutrons, it undergoes fission. The fission reaction can be written as:

92U235+0n1→56Ba141+36Kr92+3x+Q{}_{92}U^{235} + {}_{0}n^{1} \rightarrow {}_{56}Ba^{141} + {}_{36}Kr^{92} + 3x + Q(energy) where three particles named x are produced and energy Q is released. What is the name of the particle x?

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Answer: (c)

  1. AA: 236=141+92+3Ax⇒Ax=1236 = 141 + 92 + 3A_x \Rightarrow A_x = 1
  2. ZZ: 92=56+36+3Zx⇒Zx=092 = 56 + 36 + 3Z_x \Rightarrow Z_x = 0
  3. So the answer is (c) neutron.
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