When vector A = 2i + 3j + 2k is subtracted from vector B, it gives a vector equal to 2j. Then the magnitude of vector B will be: (a) 3 (b) √(33) (c) √(6) (d) √(5)

Answer: (b). B - A = 2j ⇒ B = A + 2j = 2i + 5j + 2k |B| = √(4 + 25 + 4) = √(33) So the answer is (b) √(33).

When vector A = 2i + 3j + 2k is subtracted from vector B, it gives a… | JEE Main 2023 (11 Apr, Shift 2)

Q12JEE Main 2023 · 11 APR · SHIFT 2Easy

Vector Basics, Unit Vectors & Components

When vector $\vec{A} = 2\hat{i} + 3\hat{j} + 2\hat{k}$ is subtracted from vector $\vec{B}$ , it gives a vector equal to $2\hat{j}$ . Then the magnitude of vector $\vec{B}$ will be:

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Answer: (b)

$\vec{B} - \vec{A} = 2\hat{j} \Rightarrow \vec{B} = \vec{A} + 2\hat{j} = 2\hat{i} + 5\hat{j} + 2\hat{k}$
$|\vec{B}| = \sqrt{4 + 25 + 4} = \sqrt{33}$
So the answer is (b) $\sqrt{33}$ .

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