Electrical Power & Heating Effect question from JEE Main 2013 (23 Apr, Shift 1)

Answer: (b)

1. Upper branch $P + Q = 6\ \Omega$, lower branch $R + S = 3\ \Omega$; currents split $i : 2i$.
2. $H_P = 2i^2$, $H_Q = 4i^2$.
3. $H_R = (2i)^2 \times 1 = 4i^2$, $H_S = (2i)^2 \times 2 = 8i^2$.
4. So the answer is (b) S.