Resonance, Bandwidth & Q Factor question from MHT CET 2024 (15 May, Shift 2)

Answer: (b)

1. As $\nu \to 0$, $X_C = \dfrac{1}{2\pi\nu C}$ is very large, so $Z$ is large.
2. At $\nu_0$, $X_L = X_C$ and $Z = R$ (minimum, not zero).
3. For large $\nu$, $X_L = 2\pi\nu L$ is large, so $Z$ rises again.
4. Graph B shows high $Z$, a dip to a non-zero minimum, then high $Z$. So the answer is (b) B.