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NEET 2004 (AIPMT) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from NEET 2004 (AIPMT)

Q84NEET 2004 · AIPMTEasy

Velocity & Acceleration in SHM

Which one of the following statements is true for the speed v and the acceleration a of a particle executing simple harmonic motion?

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Answer: (d)

  1. v=ωA2−x2v = \omega\sqrt{A^2 - x^2} and a=−ω2xa = -\omega^2 x.
  2. At the mean position x=0x = 0: vv is maximum and a=0a = 0.
  3. At the extreme x=±Ax = \pm A: v=0v = 0 and ∣a∣|a| is maximum.
  4. So the answer is (d): when vv is maximum, aa is zero.
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