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JEE Main 2025 (3 Apr, Shift 2) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from JEE Main 2025 (3 Apr, Shift 2)

Q27JEE Main 2025 · 3 APR · SHIFT 2Medium

Superposition, Coherence & Intensity

Width of one of the two slits in a Young's double slit interference experiment is half of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is:

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Answer: (d)

  1. Intensity ∝\propto width: I1:I2=2:1I_1 : I_2 = 2 : 1, amplitudes 2:1\sqrt{2} : 1.
  2. ImaxImin=(2+1)2(2−1)2=3+223−22\frac{I_{max}}{I_{min}} = \frac{(\sqrt{2}+1)^2}{(\sqrt{2}-1)^2} = \frac{3+2\sqrt{2}}{3-2\sqrt{2}}
  3. So the answer is (d) (3+22):(3−22)(3+2\sqrt{2}) : (3-2\sqrt{2}).
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