Physics Circle home Student Login

Home›Chapters›Alternating Current PYQs›Series LCR Circuit›Question 41

MHT CET 2023 (10 May, Shift 2) · Series LCR Circuit

Series LCR Circuit question from MHT CET 2023 (10 May, Shift 2)

Q41MHT CET 2023 · 10 MAY · SHIFT 2Medium

Series LCR Circuit

With an alternating voltage source of frequency 'ff', inductor 'LL', capacitor 'CC' and resistance 'RR' are connected in series. The voltage leads the current by 45∘45^\circ. The value of 'LL' is (tan⁡45∘=1)(\tan 45^\circ = 1)

Show answer and solution

Answer: (a)

  1. Voltage leads by 45∘45^\circ: XL−XC=Rtan⁡45∘=RX_L - X_C = R\tan 45^\circ = R.
  2. 2πfL=12πfC+R=1+2πfCR2πfC2\pi fL = \dfrac{1}{2\pi fC} + R = \dfrac{1 + 2\pi fCR}{2\pi fC}
  3. L=1+2πfCR4π2f2CL = \dfrac{1 + 2\pi fCR}{4\pi^2f^2C}
  4. So the answer is (a).
Report a mistake

More questions on Series LCR Circuit