With resistance x in the left gap and resistance 9 Ω in right gap of a meter bridge, the balance point is obtained at 40 cm from left end. In what way and to which resistance 3 Ω resistance be connected to obtain the balance point at 50 cm from the left end? (a) In series with 9 Ω (b) Parallel to x Ω (c) In series with x Ω (d) Parallel to 9 Ω

Answer: (c). x/9 = 40/60 ⇒ x = 6 Ω Balance at 50 cm needs equal gap resistances. 6 + 3 = 9: put 3 Ω in series with x. So the answer is (c) in series with x Ω.

With resistance x in the left gap and resistance 9 Ω in right gap of… | MHT CET 2026 (15 May, Shift 1)

Q8MHT CET 2026 · 15 MAY · SHIFT 1Medium

Wheatstone Bridge & Metre Bridge

With resistance $x$ in the left gap and resistance $9\ \Omega$ in right gap of a meter bridge, the balance point is obtained at $40$ cm from left end. In what way and to which resistance $3\ \Omega$ resistance be connected to obtain the balance point at $50$ cm from the left end?

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Answer: (c)

$\dfrac{x}{9} = \dfrac{40}{60} \Rightarrow x = 6\ \Omega$
Balance at 50 cm needs equal gap resistances.
$6 + 3 = 9$ : put $3\ \Omega$ in series with $x$ .
So the answer is (c) in series with $x\ \Omega$ .

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Wheatstone Bridge & Metre Bridge question from MHT CET 2026 (15 May, Shift 1)

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