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MHT CET 2026 (17 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (17 Apr, Shift 1)

Q4MHT CET 2026 · 17 APR · SHIFT 1Easy

Thermal Radiation: Black Body, Stefan & Wien

'xx' joule of heat is incident on a body. Out of it, the total heat reflected and transmitted by it is 'yy' joule. The absorption coefficient of the body is

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Answer: (b)

  1. Heat absorbed =x−y= x - y (rest is reflected or transmitted).
  2. a=absorbedincident=x−yxa = \dfrac{\text{absorbed}}{\text{incident}} = \dfrac{x-y}{x}
  3. So the answer is (b).
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