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JEE Main 2022 (25 Jul, Shift 2) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from JEE Main 2022 (25 Jul, Shift 2)

Q41JEE Main 2022 · 25 JUL · SHIFT 2Medium

Transitions, Photon Emission & Excitation

xx+4\frac{x}{x+4} is the ratio of energies of photons produced due to transition of an electron of hydrogen atom from its

(i) third permitted energy level to the second level and

(ii) the highest permitted energy level to the second permitted level.

The value of x will be ____________.

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. E∝(1nf2−1ni2)E \propto \left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right)
  2. (i) 3→23\to2: 14−19=536\frac{1}{4} - \frac{1}{9} = \frac{5}{36}; (ii) ∞→2\infty\to2: 14=936\frac{1}{4} = \frac{9}{36}
  3. Ratio =59=xx+4= \frac{5}{9} = \frac{x}{x+4}
  4. So x=5x = 5.
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