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NEET 2024 · Radioactive Decays: Alpha, Beta, Gamma

Radioactive Decays: Alpha, Beta, Gamma question from NEET 2024

Q8NEET 2024Easy

Radioactive Decays: Alpha, Beta, Gamma

82290X→αY→e+Z→β−P→e−Q{}^{290}_{82}X \xrightarrow{\alpha} Y \xrightarrow{e^{+}} Z \xrightarrow{\beta^{-}} P \xrightarrow{e^{-}} Q

In the nuclear emission stated above, the mass number and atomic number of the product QQ respectively, are

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Answer: (d)

  1. α\alpha: (290,82)→(286,80)(290, 82) \to (286, 80)
  2. e+e^+: ZZ falls by 1: (286,79)(286, 79)
  3. β−\beta^-: ZZ rises by 1: (286,80)(286, 80); e−e^- again: (286,81)(286, 81)
  4. So the answer is (d) 286, 81.
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