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JEE Main 2023 (10 Apr, Shift 2) · Young's Modulus & Elongation

Young's Modulus & Elongation question from JEE Main 2023 (10 Apr, Shift 2)

Q14JEE Main 2023 · 10 APR · SHIFT 2Easy

Young's Modulus & Elongation

Young's moduli of the material of wires A and B are in the ratio of $1 : 4$ , while its area of cross sections are in the ratio of $1 : 3$ . If the same amount of load is applied to both the wires, the amount of elongation produced in the wires $A$ and $B$ will be in the ratio of

[Assume length of wires A and B are same]

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Answer: (c)

Same load and length: $\Delta L = \frac{FL}{AY} \propto \frac{1}{AY}$
$\frac{\Delta L_A}{\Delta L_B} = \frac{A_B Y_B}{A_A Y_A} = \frac{3 \times 4}{1 \times 1} = 12$
So the answer is (c) $12 : 1$ .

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