Q1 MHT CET 2026 · 13 MAY · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
When an electron in hydrogen atom revolves in a stationary orbit, it
(a) does not radiate light though its velocity changes (b) does not radiate light and velocity remains unchanged (c) radiates light but its velocity is unchanged (d) radiates light with the change of energy Show answer and solution
Answer: (a)
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Q2 MHT CET 2026 · 20 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Which of the following is an integral multiple of h 2 π \frac{h}{2\pi} 2 π h in Bohr's model of an hydrogen atom?
(a) Radius of an atom (b) Kinetic energy (c) Potential energy (d) Angular momentum Show answer and solution
Answer: (d)
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Q3 MHT CET 2026 · 18 APR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The angular momentum of the electron in the third Bohr orbit of a hydrogen atom is 'l l l ' so its angular momentum in the fourth Bohr orbit is
(a) 4 l 4l 4 l (b) ( 5 4 ) l \left(\frac{5}{4}\right)l ( 4 5 ) l (c) ( 4 3 ) l \left(\frac{4}{3}\right)l ( 3 4 ) l (d) ( 3 2 ) l \left(\frac{3}{2}\right)l ( 2 3 ) l Show answer and solution
Answer: (c)
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Q4 MHT CET 2026 · 15 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
In the hydrogen atom, radii of the first four Bohr orbits are related as
(a) 1 : 2 : 3 : 4 1 : 2 : 3 : 4 1 : 2 : 3 : 4 (b) 1 2 : 1 3 : 1 4 \frac{1}{2} : \frac{1}{3} : \frac{1}{4} 2 1 : 3 1 : 4 1 (c) 1 : 4 : 9 : 16 1 : 4 : 9 : 16 1 : 4 : 9 : 16 (d) 1 4 : 1 9 : 1 16 \frac{1}{4} : \frac{1}{9} : \frac{1}{16} 4 1 : 9 1 : 16 1 Show answer and solution
Answer: (c)
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Q5 MHT CET 2026 · 11 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
In Bohr's theory of hydrogen atom, 'r' is the radius of the orbit, 'V' is the speed of electron and E is the total energy of the electron. Out of the following which physical quantity is inversely proportional to principal quantum number?
(a) 1 V r \frac{1}{Vr} V r 1 (b) V r Vr V r (c) V 2 r V^2 r V 2 r (d) V r 2 Vr^2 V r 2 Show answer and solution
Answer: (a)
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Q6 MHT CET 2026 · 19 MAY · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The de Broglie wavelength of an electron moving in the n t h n^{th} n t h Bohr orbit of radius 'r r r ' is
(a) n π r n\pi r nπ r (b) n r π \frac{nr}{\pi} π n r (c) 2 π r n \frac{2\pi r}{n} n 2 π r (d) n r 2 π \frac{nr}{2\pi} 2 π n r Show answer and solution
Answer: (c)
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Q7 MHT CET 2026 · 19 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The de-Broglie wavelength of an electron moving in the n t h n^{th} n t h Bohr orbit of radius 'r' is
(a) n π r n\pi r nπ r (b) n r π \frac{nr}{\pi} π n r (c) 2 π r n \frac{2\pi r}{n} n 2 π r (d) n r 2 π \frac{nr}{2\pi} 2 π n r Show answer and solution
Answer: (c)
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Q8 MHT CET 2026 · 18 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The de Broglie wavelength of the electron in the ground state is λ 1 \lambda_1 λ 1 and that in the n = 3 n = 3 n = 3 level is λ 3 \lambda_3 λ 3 then λ 3 \lambda_3 λ 3 is given by
(a) λ 1 3 \frac{\lambda_1}{3} 3 λ 1 (b) λ 1 2 \frac{\lambda_1}{2} 2 λ 1 (c) 2 λ 1 2\lambda_1 2 λ 1 (d) 3 λ 1 3\lambda_1 3 λ 1 Show answer and solution
Answer: (d)
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Q9 MHT CET 2026 · 15 APR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
When the electron orbiting in hydrogen atom in its ground state moves to the third excited state, the de-Broglie wavelength associated with it
(a) will decrease (b) will increase (c) will remain same (d) will be zero Show answer and solution
Answer: (b)
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Q10 MHT CET 2026 · 19 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The magnetic moment of electron due to orbital motion is proportional to
(n n n = principal quantum number)
(a) n n n (b) n 2 n^2 n 2 (c) 1 n \frac{1}{n} n 1 (d) 1 n 2 \frac{1}{n^2} n 2 1 Show answer and solution
Answer: (a)
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Q11 MHT CET 2026 · 17 APR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The orbital magnetic moment ( m o r b ) (m_{orb}) ( m or b ) of a revolving electron around the nucleus varies with the principal quantum number (n n n ) as
(a) m o r b ∝ n 2 m_{orb} \propto n^2 m or b ∝ n 2 (b) m o r b ∝ n m_{orb} \propto n m or b ∝ n (c) m o r b ∝ 1 n 2 m_{orb} \propto \frac{1}{n^2} m or b ∝ n 2 1 (d) m o r b ∝ 1 n m_{orb} \propto \frac{1}{n} m or b ∝ n 1 Show answer and solution
Answer: (b)
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Q12 MHT CET 2026 · 16 APR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The force acting on the electron in hydrogen atom (Bohr's theory) is related to the principal quantum number n as
(a) n 4 n^4 n 4 (b) n − 4 n^{-4} n − 4 (c) n 2 n^2 n 2 (d) n − 2 n^{-2} n − 2 Show answer and solution
Answer: (b)
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Q13 MHT CET 2026 · 20 APR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The angular momentum of an electron in Bohr's hydrogen atom having energy ( − 0.544 ) (-0.544) ( − 0.544 ) eV is (h h h = Planck's constant)
(a) h π \frac{h}{\pi} π h (b) 3 h π \frac{3h}{\pi} π 3 h (c) 5 h 2 π \frac{5h}{2\pi} 2 π 5 h (d) 7 h 2 π \frac{7h}{2\pi} 2 π 7 h Show answer and solution
Answer: (c)
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Q14 JEE Main 2026 · 21 JAN · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The energy of an electron in an orbit of the Bohr's atom is − 0.04 E 0 -0.04E_0 − 0.04 E 0 eV where E 0 E_0 E 0 is the ground state energy. If L L L is the angular momentum of the electron in this orbit and h h h is the Planck's constant, then
2 π L h \frac{2\pi L}{h} h 2 π L is ________:
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Answer: (c)
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Q15 MHT CET 2026 · 18 APR · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
If the difference between ( n + 1 ) t h (n+1)^{th} ( n + 1 ) t h Bohr radius and n t h n^{th} n t h Bohr radius is given by ( n − 1 ) t h (n-1)^{th} ( n − 1 ) t h Bohr radius, then the value of n is
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Answer: (a)
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Q16 MHT CET 2026 · 18 APR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The triply ionized beryllium (Be+ + + ^{+++} +++ ) has the same electron orbital radius as that of the ground state of hydrogen. Hence, the energy state of triply ionized beryllium is (Given Z = 4 Z = 4 Z = 4 for beryllium)
(a) n = 4 n = 4 n = 4 (b) n = 3 n = 3 n = 3 (c) n = 2 n = 2 n = 2 (d) n = 1 n = 1 n = 1 Show answer and solution
Answer: (c)
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Q17 NEET 2026 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
In the first excited state of hydrogen atom, the energy of its electron is -3.4 eV. The radial distance of the electron from the hydrogen nucleus in this case is approximately:
(Take 1 eV = 1.6 × 1 0 − 19 J , e = 1.6 × 1 0 − 19 C 1\text{ eV} = 1.6 \times 10^{-19}\text{ J},\ e = 1.6 \times 10^{-19}\text{ C} 1 eV = 1.6 × 1 0 − 19 J , e = 1.6 × 1 0 − 19 C and 1 4 π ε 0 = 9 × 1 0 9 N m 2 / C 2 \frac{1}{4\pi\varepsilon_0} = 9 \times 10^{9}\text{ N m}^2/\text{C}^2 4 π ε 0 1 = 9 × 1 0 9 N m 2 / C 2 )
(a) 2.1 × 1 0 − 9 m 2.1 \times 10^{-9}\text{ m} 2.1 × 1 0 − 9 m (b) 2.1 × 1 0 − 8 m 2.1 \times 10^{-8}\text{ m} 2.1 × 1 0 − 8 m (c) 2.1 × 1 0 − 10 m 2.1 \times 10^{-10}\text{ m} 2.1 × 1 0 − 10 m (d) 2.1 × 1 0 − 11 m 2.1 \times 10^{-11}\text{ m} 2.1 × 1 0 − 11 m Show answer and solution
Answer: (c)
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Q18 JEE Main 2026 · 24 JAN · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Two electrons are moving in orbits of two hydrogen like atoms with speeds 3 × 1 0 5 m/s 3 \times 10^{5}\text{ m/s} 3 × 1 0 5 m/s and 2.5 × 1 0 5 m/s 2.5 \times 10^{5}\text{ m/s} 2.5 × 1 0 5 m/s respectively. If the radii of these orbits are nearly same then the possible order of energy states are ______ respectively.
(a) 8 and 10 (b) 10 and 12 (c) 9 and 8 (d) 6 and 5 Show answer and solution
Answer: (d)
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Q19 MHT CET 2026 · 14 MAY · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
In hydrogenth atom, an electron jumps from higher orbit to lower orbit so that radius of the lower orbit is ( 1 4 ) \left(\frac{1}{4}\right) ( 4 1 ) of radius of higher orbit. If speed of electron in higher orbit was V, then speed in lower orbit is
(a) V 4 \frac{V}{4} 4 V (b) V 2 \frac{V}{2} 2 V (c) V V V (d) 2 V 2V 2 V Show answer and solution
Answer: (d)
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Q20 NEET 2026 · RE-NEET Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Consider that an electron is revolving in an excited state of Hydrogen atom with velocity 25.6 × 1 0 5 m s − 1 \sqrt{25.6} \times 10^{5}\text{ m s}^{-1} 25.6 × 1 0 5 m s − 1 . The radius of the orbit is x × 1 0 − 9 m x \times 10^{-9}\text{ m} x × 1 0 − 9 m . The value of x x x is:
[Take the mass of electron to the 9 × 1 0 − 31 kg 9 \times 10^{-31}\text{ kg} 9 × 1 0 − 31 kg , charge of electron = − 1.6 × 1 0 − 19 C = -1.6 \times 10^{-19}\text{ C} = − 1.6 × 1 0 − 19 C and 1 4 π ε 0 = 9 × 1 0 9 N m 2 C − 2 \frac{1}{4\pi\varepsilon_0} = 9 \times 10^{9}\text{ N m}^2\text{C}^{-2} 4 π ε 0 1 = 9 × 1 0 9 N m 2 C − 2 ]
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Answer: (a)
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Q21 MHT CET 2026 · 19 MAY · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The moment of inertia of the electron moving in the second Bohr orbit of a hydrogen atom is [m m m = mass of electron, h h h = Planck's constant, e e e = charge on electron, ε 0 \varepsilon_0 ε 0 = permittivity of free space]
(a) ε 0 2 h 4 8 π 2 m e 4 \frac{\varepsilon_0^2 h^4}{8\pi^2 m e^4} 8 π 2 m e 4 ε 0 2 h 4 (b) 16 ε 0 2 h 4 π 2 m e 4 \frac{16\varepsilon_0^2 h^4}{\pi^2 m e^4} π 2 m e 4 16 ε 0 2 h 4 (c) 2 ε 0 2 h 4 π 2 m e 4 \frac{2\varepsilon_0^2 h^4}{\pi^2 m e^4} π 2 m e 4 2 ε 0 2 h 4 (d) 4 ε 0 2 h 2 m π 2 e 4 \frac{4\varepsilon_0^2 h^2 m}{\pi^2 e^4} π 2 e 4 4 ε 0 2 h 2 m Show answer and solution
Answer: (b)
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Q22 MHT CET 2026 · 16 APR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Using Bohr's atomic model, the orbital period of electron in hydrogen atom in the n n n th orbit is (ϵ 0 \epsilon_0 ϵ 0 =permittivity of free space, h=Planck's constant, m = mass of electron, e = electronic charge)
(a) 4 ϵ 0 2 n 3 h 3 m e 4 \frac{4\epsilon_0^2 n^3 h^3}{m e^4} m e 4 4 ϵ 0 2 n 3 h 3 (b) 2 ϵ 0 2 n 2 h 3 m e 2 \frac{2\epsilon_0^2 n^2 h^3}{m e^2} m e 2 2 ϵ 0 2 n 2 h 3 (c) 4 ϵ 0 2 n 2 h 3 m e 2 \frac{4\epsilon_0^2 n^2 h^3}{m e^2} m e 2 4 ϵ 0 2 n 2 h 3 (d) 2 ϵ 0 n 3 h 3 m e 4 \frac{2\epsilon_0 n^3 h^3}{m e^4} m e 4 2 ϵ 0 n 3 h 3 Show answer and solution
Answer: (a)
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Q23 MHT CET 2026 · 11 APR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The number of revolutions per second made by an electron in the first Bohr orbit of hydrogen atom is (h h h = Planck's constant, m m m is the mass of electron and r r r is the radius of the orbit.)
(a) h / 4 π 2 m r 2 h/4\pi^2 m r^2 h /4 π 2 m r 2 (b) h / 4 π 2 m r h/4\pi^2 m r h /4 π 2 m r (c) h / 4 π m r h/4\pi m r h /4 πm r (d) h / 4 π 2 m 2 r 2 h/4\pi^2 m^2 r^2 h /4 π 2 m 2 r 2 Show answer and solution
Answer: (a)
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Q24 MHT CET 2026 · 12 MAY · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Assuming the atom is in the ground state, the expression for the magnetic field at a point nucleus in hydrogen atom due to circular motion of electron is (μ 0 \mu_0 μ 0 = permeability of free space, ϵ 0 \epsilon_0 ϵ 0 = permittivity of free space, m m m = mass of electron, e e e = electronic charge)
(a) μ 0 e 2 m 2 8 ϵ 0 h 2 \frac{\mu_0 e^2 m^2}{8\epsilon_0 h^2} 8 ϵ 0 h 2 μ 0 e 2 m 2 (b) μ 0 e 7 π m 2 8 ϵ 0 3 h 5 \frac{\mu_0 e^7 \pi m^2}{8\epsilon_0^3 h^5} 8 ϵ 0 3 h 5 μ 0 e 7 π m 2 (c) μ 0 e 5 π m 6 ϵ 0 2 h 2 \frac{\mu_0 e^5 \pi m}{6\epsilon_0^2 h^2} 6 ϵ 0 2 h 2 μ 0 e 5 πm (d) μ 0 e 2 π m 2 8 ϵ 0 h 2 \frac{\mu_0 e^2 \pi m^2}{8\epsilon_0 h^2} 8 ϵ 0 h 2 μ 0 e 2 π m 2 Show answer and solution
Answer: (b)
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Q25 MHT CET 2026 · 13 APR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
An electron is revolving in a circular orbit of radius 'r' in hydrogen atom. Using Bohr's theory, the angular momentum of the electron is
(M = magnetic dipole moment, m = mass of electron)
(a) m M e \frac{mM}{e} e m M (b) e m M \frac{e}{mM} m M e (c) 2 m M e \frac{2mM}{e} e 2 m M (d) e 2 m M \frac{e}{2mM} 2 m M e Show answer and solution
Answer: (c)
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Q26 JEE Main 2026 · 2 APR · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Using Bohr’s model, calculate the ratio of the magnetic fields generated due to the motion of the electrons in the 2nd and 4th orbits of hydrogen atom ________.
Numerical answer type. Work it out, then open the answer.
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Answer: 32
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Q27 MHT CET 2026 · 13 APR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The ratio of centripetal acceleration for an electron revolving in 3rd and 5th Bohr orbit of hydrogen atom is
(a) 25 : 9 25 : 9 25 : 9 (b) 125 : 27 125 : 27 125 : 27 (c) 625 : 81 625 : 81 625 : 81 (d) 5 : 3 5 : 3 5 : 3 Show answer and solution
Answer: (c)
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Q28 MHT CET 2026 · 13 MAY · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Using Bohr's quantisation condition, what is the rotational kinetic energy in the second orbit for a diatomic molecule (I = moment of inertia of diatomic molecule, h = Planck's constant)
(a) h 2 I π 2 \frac{h}{2I\pi^2} 2 I π 2 h (b) h 2 2 I π 2 \frac{h^2}{2I\pi^2} 2 I π 2 h 2 (c) h 2 2 I 2 π 2 \frac{h^2}{2I^2\pi^2} 2 I 2 π 2 h 2 (d) h 2 I 2 π \frac{h}{2I^2\pi} 2 I 2 π h Show answer and solution
Answer: (b)
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Q29 MHT CET 2026 · 14 MAY · SHIFT 1 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
Bohr model is applied to a particle of mass m m m and charge q q q is moving in a plane under the influence of a transverse magnetic field B B B . The energy of the charged particle in n t h n^{th} n t h level will be (h h h = Planck's constant)
(a) 2 n h q B π m \frac{2nhqB}{\pi m} πm 2 nh qB (b) n h q B 2 π m \frac{nhqB}{2\pi m} 2 πm nh qB (c) n h q B 4 π m \frac{nhqB}{4\pi m} 4 πm nh qB (d) n h q B π m \frac{nhqB}{\pi m} πm nh qB Show answer and solution
Answer: (c)
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Q30 MHT CET 2026 · 11 APR · SHIFT 2 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
Bohr model is applied to a particle of mass 'm' and charge 'q' moving in a plane under the influence of a transverse magnetic field B. The energy of the charged particle in the n t h n^{th} n t h level will be (h=Planck's constant)
(a) 2 n h q B π m \frac{2nhqB}{\pi m} πm 2 nh qB (b) n h q B π m \frac{nhqB}{\pi m} πm nh qB (c) n h q B 2 π m \frac{nhqB}{2\pi m} 2 πm nh qB (d) n h q B 4 π m \frac{nhqB}{4\pi m} 4 πm nh qB Show answer and solution
Answer: (d)
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Q31 JEE Main 2025 · 4 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Given below are two statements:
Statement (I): The dimensions of Planck's constant and angular momentum are same. Statement (II): In Bohr's model electron revolve around the nucleus only in those orbits for which angular momentum is integral multiple of Planck's constant.
In the light of the above statements, choose the most appropriate answer from the options given below:
(a) Both Statement I and Statement II are correct (b) Statement I is correct but Statement II is incorrect (c) Both Statement I and Statement II are incorrect (d) Statement I is incorrect but Statement II is correct Show answer and solution
Answer: (b)
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Q32 JEE Main 2025 · 3 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Given below are two statements: one is labelled as Assertion A \textbf{Assertion A} Assertion A and the other is labelled as Reason R \textbf{R} R
Assertion A: The Bohr model is applicable to hydrogen and hydrogen-like atoms only. Reason R \textbf{R} R : The formulation of Bohr model does not include repulsive force between electrons. In the light of the above statements, choose the correct answer from the options given below
(a) A \textbf{A} A is true but R \textbf{R} R is false(b) Both A \textbf{A} A and R \textbf{R} R are true and R \textbf{R} R is the correct explanation of A \textbf{A} A (c) A \textbf{A} A is false but R \textbf{R} R is true(d) Both A \textbf{A} A and R \textbf{R} R are true but R \textbf{R} R is NOT the correct explanation of A \textbf{A} A Show answer and solution
Answer: (b)
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Q33 JEE Main 2025 · 4 APR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Considering the Bohr model of hydrogen like atoms, the ratio of the radius of 5 5 5 th orbit of the electron in Li 2 + \text{Li}^{2+} Li 2 + and He + \text{He}^{+} He + is
(a) 3 2 \frac{3}{2} 2 3 (b) 2 3 \frac{2}{3} 3 2 (c) 4 9 \frac{4}{9} 9 4 (d) 9 4 \frac{9}{4} 4 9 Show answer and solution
Answer: (b)
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Q34 JEE Main 2025 · 2 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Assuming the validity of Bohr's atomic model for hydrogen like ions the radius of Li + + \text{Li}^{++} Li ++ ion in its ground state is given by 1 X a 0 \frac{1}{X}a_0 X 1 a 0 , where X = X = X = __________ (Where a 0 a_0 a 0 is the first Bohr's radius.)
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Answer: (d)
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Q35 MHT CET 2025 · 19 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The frequency of revolution of an electron in the n n n th orbit of hydrogen atom is
(a) directly proportional to n 2 n^2 n 2 (b) inversely proportional to n 2 n^2 n 2 (c) directly proportional to n 3 n^3 n 3 (d) inversely proportional to n 3 n^3 n 3 Show answer and solution
Answer: (d)
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Q36 JEE Main 2025 · 28 JAN · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The frequency of revolution of the electron in Bohr's orbit varies with n, the principal quantum number as:
(a) 1 n 4 \frac{1}{n^4} n 4 1 (b) 1 n 2 \frac{1}{n^2} n 2 1 (c) 1 n 3 \frac{1}{n^3} n 3 1 (d) 1 n \frac{1}{n} n 1 Show answer and solution
Answer: (c)
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Q37 MHT CET 2025 · 26 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The magnetic moment of electron due to orbital motion is proportional to ( n = n = n = principal quantum number)
(a) n (b) n 2 n^2 n 2 (c) 1 n \frac{1}{n} n 1 (d) 1 n 2 \frac{1}{n^2} n 2 1 Show answer and solution
Answer: (a)
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Q38 MHT CET 2025 · 25 APR · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
In hydrogen atom in its ground state, the first Bohr orbit has radius ' r 1 r_1 r 1 '. When the atom is raised to one of its excited states, the electrons orbital velocity becomes one-third. The radius of that orbit is
(a) 2 r 1 2r_1 2 r 1 (b) 3 r 1 3r_1 3 r 1 (c) 4 r 1 4r_1 4 r 1 (d) 9 r 1 9r_1 9 r 1 Show answer and solution
Answer: (d)
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Q39 MHT CET 2025 · 20 APR · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The ratio of angular momentum of an electron in n n n th orbit of hydrogen atom to the velocity of electron in n n n th orbit is proportional to
(a) n 2 n^2 n 2 (b) 1 n 2 \frac{1}{n^2} n 2 1 (c) n 3 n^3 n 3 (d) 1 n 3 \frac{1}{n^3} n 3 1 Show answer and solution
Answer: (a)
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Q40 MHT CET 2025 · 21 APR · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Using Bohr's quantization condition, the rotational kinetic energy in the third orbit for a diatomic molecule is ( h = h = h = Planck's constant, I = I = I = moment of inertia of diatomic molecule)
(a) 9 h 2 8 π 2 I \frac{9h^2}{8\pi^2 I} 8 π 2 I 9 h 2 (b) 3 h 2 8 π 2 I \frac{3h^2}{8\pi^2 I} 8 π 2 I 3 h 2 (c) 6 h 2 8 π I \frac{6h^2}{8\pi I} 8 π I 6 h 2 (d) 12 h 2 7 π 2 I \frac{12h^2}{7\pi^2 I} 7 π 2 I 12 h 2 Show answer and solution
Answer: (a)
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Q41 NEET 2025 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
A particle of mass m m m is moving around the origin with a constant force F F F pulling it towards the origin. If Bohr model is used to describe its motion, the radius of the n n n th orbit and the particle's speed v v v in the orbit depend on n n n as
(a) r ∝ n 2 / 3 ; v ∝ n 1 / 3 r \propto n^{2/3};\ v \propto n^{1/3} r ∝ n 2/3 ; v ∝ n 1/3 (b) r ∝ n 4 / 3 ; v ∝ n − 1 / 3 r \propto n^{4/3};\ v \propto n^{-1/3} r ∝ n 4/3 ; v ∝ n − 1/3 (c) r ∝ n 1 / 3 ; v ∝ n 1 / 3 r \propto n^{1/3};\ v \propto n^{1/3} r ∝ n 1/3 ; v ∝ n 1/3 (d) r ∝ n 1 / 3 ; v ∝ n 2 / 3 r \propto n^{1/3};\ v \propto n^{2/3} r ∝ n 1/3 ; v ∝ n 2/3 Show answer and solution
Answer: (a)
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Q42 MHT CET 2024 · 11 MAY · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The angular momentum of the electron in the third Bohr orbit of hydrogen atom is ' l l l '. Its angular momentum in the fourth Bohr orbit is
(a) 4 l 4l 4 l (b) 4 3 l \frac{4}{3}l 3 4 l (c) 5 4 l \frac{5}{4}l 4 5 l (d) 3 2 l \frac{3}{2}l 2 3 l Show answer and solution
Answer: (b)
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Q43 JEE Main 2024 · 4 APR · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
According to Bohr's theory, the moment of momentum of an electron revolving in 4 4 4 th orbit of hydrogen atom is:
(a) 2 h π 2\frac{h}{\pi} 2 π h (b) h 2 π \frac{h}{2\pi} 2 π h (c) h π \frac{h}{\pi} π h (d) 8 h π 8\frac{h}{\pi} 8 π h Show answer and solution
Answer: (a)
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Q44 MHT CET 2024 · 3 MAY · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The ratio of the radius of the first Bohr orbit to that of the second Bohr orbit of the orbital electron is
(a) 4 : 1 4 : 1 4 : 1 (b) 2 : 1 2 : 1 2 : 1 (c) 1 : 4 1 : 4 1 : 4 (d) 1 : 2 1 : 2 1 : 2 Show answer and solution
Answer: (c)
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Q45 MHT CET 2024 · 2 MAY · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The radius of innermost orbit of hydrogen atom is 5.3 × 1 0 − 11 m 5.3 \times 10^{-11}\text{ m} 5.3 × 1 0 − 11 m . The radius of fourth allowed orbit of hydrogen atom is
(a) 8.48 A ˚ \mathring{A} A ˚ (b) 2.12 A ˚ \mathring{A} A ˚ (c) 4.77 A ˚ \mathring{A} A ˚ (d) 0.53 A ˚ \mathring{A} A ˚ Show answer and solution
Answer: (a)
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Q46 JEE Main 2024 · 27 JAN · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The radius of third stationary orbit of electron for Bohr's atom is R. The radius of fourth stationary orbit will be:
(a) 4 3 R \frac{4}{3}R 3 4 R (b) 16 9 R \frac{16}{9}R 9 16 R (c) 3 4 R \frac{3}{4}R 4 3 R (d) 9 16 R \frac{9}{16}R 16 9 R Show answer and solution
Answer: (b)
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Q47 MHT CET 2024 · 10 MAY · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
In the Bohr model of hydrogen atom, the centripetal force is furnished by the coulomb attraction between the proton and the electron. If ' r 0 r_0 r 0 ' is the radius of the ground state orbit, ' m m m ' is the mass, ' e ' is the charge on the electron and ' ε 0 \varepsilon_0 ε 0 ' is the permittivity of vacuum, the speed of the electron is
(a) zero (b) e ε 0 r 0 m \frac{e}{\sqrt{\varepsilon_0 r_0 m}} ε 0 r 0 m e (c) e 4 π ε 0 r 0 m \frac{e}{\sqrt{4\pi\varepsilon_0 r_0 m}} 4 π ε 0 r 0 m e (d) 4 π ε 0 r 0 m e \frac{\sqrt{4\pi\varepsilon_0 r_0 m}}{e} e 4 π ε 0 r 0 m Show answer and solution
Answer: (c)
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Q48 MHT CET 2024 · 9 MAY · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
In hydrogen atom, if V n V_n V n and V p V_p V p are orbital velocities in n n n th and p p p th orbit respectively, then the ratio V p : V n V_p : V_n V p : V n is
(a) p : n p : n p : n (b) n : p n : p n : p (c) p 2 : n 2 p^2 : n^2 p 2 : n 2 (d) n 2 : p 2 n^2 : p^2 n 2 : p 2 Show answer and solution
Answer: (b)
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Q49 MHT CET 2024 · 16 MAY · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
When an electron orbiting in hydrogen atom in its ground state jumps to higher excited state, the de- Broglie wavelength associated with it
(a) will become zero. (b) will remain same. (c) will decrease. (d) will increase. Show answer and solution
Answer: (d)
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Q50 MHT CET 2024 · 15 MAY · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The ratio of the areas of the electron orbits for the second excited state to the first excited state for the hydrogen atom is
(a) 3 : 2 3 : 2 3 : 2 (b) 9 : 4 9 : 4 9 : 4 (c) 16 : 81 16 : 81 16 : 81 (d) 81 : 16 81 : 16 81 : 16 Show answer and solution
Answer: (d)
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Q51 MHT CET 2024 · 11 MAY · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
In a hydrogen atom in its ground state, the first Bohr orbit has radius r 1 r_1 r 1 . The electron's orbital speed becomes one-third when the atom is raised to one of its excited states. The radius of the orbit in that excited state is
(a) 3 r 1 3r_1 3 r 1 (b) 4 r 1 4r_1 4 r 1 (c) 9 r 1 9r_1 9 r 1 (d) 16 r 1 16r_1 16 r 1 Show answer and solution
Answer: (c)
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Q52 JEE Main 2024 · 5 APR · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The angular momentum of an electron in a hydrogen atom is proportional to: (Where r r r is the radius of orbit of electron)
(a) 1 r \frac{1}{r} r 1 (b) 1 r \frac{1}{\sqrt{r}} r 1 (c) r \sqrt{r} r (d) r Show answer and solution
Answer: (c)
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Q53 MHT CET 2024 · 10 MAY · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Radius of first orbit in H -atom is ' a 0 a_0 a 0 ' Then, de-Broglie wavelength of electron in the third orbit is
(a) 3 π a 0 3\pi a_0 3 π a 0 (b) 6 π a 0 6\pi a_0 6 π a 0 (c) 9 π a 0 9\pi a_0 9 π a 0 (d) 12 π a 0 12\pi a_0 12 π a 0 Show answer and solution
Answer: (b)
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Q54 MHT CET 2024 · 10 MAY · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Using Bohr's model, the orbital period of electron in hydrogen atom in n n n th orbit is ( m = m = m = mass of electron, h = h = h = Planck's constant, e = e = e = electronic charge, ε 0 = \varepsilon_0 = ε 0 = permittivity of free space)
(a) 2 ε 0 2 n 2 h 2 m e 4 \frac{2\varepsilon_0^2 n^2 h^2}{m e^4} m e 4 2 ε 0 2 n 2 h 2 (b) 4 ε 0 2 n 2 h 2 m e 2 \frac{4\varepsilon_0^2 n^2 h^2}{m e^2} m e 2 4 ε 0 2 n 2 h 2 (c) 4 ε 0 2 n 3 h 3 m e 4 \frac{4\varepsilon_0^2 n^3 h^3}{m e^4} m e 4 4 ε 0 2 n 3 h 3 (d) 4 ε 0 n 2 h 2 π m e 2 \frac{4\varepsilon_0 n^2 h^2}{\pi m e^2} πm e 2 4 ε 0 n 2 h 2 Show answer and solution
Answer: (c)
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Q55 JEE Main 2024 · 30 JAN · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
An electron revolving in n n n th Bohr orbit has magnetic moment μ n \mu_n μ n . If μ n ∝ n x \mu_n \propto n^x μ n ∝ n x , the value of x x x is
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Answer: (d)
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Q56 MHT CET 2024 · 15 MAY · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Acceleration of an electron in the first Bohr's orbit is proportional to (m = m = m = mass of electron, r = r = r = radius of the orbit, h = h = h = Planck's constant)
(a) m 3 r 3 h 2 \frac{m^3 r^3}{h^2} h 2 m 3 r 3 (b) h 2 m 2 r 3 \frac{h^2}{m^2 r^3} m 2 r 3 h 2 (c) h 2 m r 3 \frac{h^2}{m r^3} m r 3 h 2 (d) m r 3 h 2 \frac{m r^3}{h^2} h 2 m r 3 Show answer and solution
Answer: (b)
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Q57 MHT CET 2024 · 3 MAY · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
A diatomic molecule has moment of inertia ' I ', By applying Bohr's quantization condition, its rotational energy in the n n n th level is [ n ≥ 1 ] [n \geq 1] [ n ≥ 1 ] [h= Planck's constant]
(a) 1 n 2 ( h 2 8 π 2 I ) \frac{1}{n^2}\left(\frac{h^2}{8\pi^2 I}\right) n 2 1 ( 8 π 2 I h 2 ) (b) 1 n ( h 2 8 π 2 I ) \frac{1}{n}\left(\frac{h^2}{8\pi^2 I}\right) n 1 ( 8 π 2 I h 2 ) (c) n ( h 2 8 π 2 I ) n\left(\frac{h^2}{8\pi^2 I}\right) n ( 8 π 2 I h 2 ) (d) n 2 ( h 2 8 π 2 I ) n^2\left(\frac{h^2}{8\pi^2 I}\right) n 2 ( 8 π 2 I h 2 ) Show answer and solution
Answer: (d)
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Q58 MHT CET 2023 · 13 MAY · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
When an electron is excited from its 4 th orbit to 5 th stationary orbit, the change in the angular momentum of electron is approximately.
(Planck's constant = h = 6.63 × 1 0 − 34 J-s = h = 6.63 \times 10^{-34}\text{ J-s} = h = 6.63 × 1 0 − 34 J-s )
(a) 2 × 1 0 − 34 J-s 2 \times 10^{-34}\text{ J-s} 2 × 1 0 − 34 J-s (b) 6.63 × 1 0 − 34 J-s 6.63 \times 10^{-34}\text{ J-s} 6.63 × 1 0 − 34 J-s (c) 1 × 1 0 − 34 J-s 1 \times 10^{-34}\text{ J-s} 1 × 1 0 − 34 J-s (d) 3.14 × 1 0 − 34 J-s 3.14 \times 10^{-34}\text{ J-s} 3.14 × 1 0 − 34 J-s Show answer and solution
Answer: (c)
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Q59 JEE Main 2023 · 10 APR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The angular momentum for the electron in Bohr's orbit is L. If the electron is assumed to revolve in second orbit of hydrogen atom, then the change in angular momentum will be
(a) L (b) L 2 \frac{L}{2} 2 L (c) zero (d) 2 L Show answer and solution
Answer: (a)
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Q60 NEET 2023 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The radius of inner most orbit of hydrogen atom is 5.3 × 1 0 − 11 m 5.3 \times 10^{-11}\text{ m} 5.3 × 1 0 − 11 m . What is the radius of third allowed orbit of hydrogen atom?
(a) 1.06 A ˚ \mathring{A} A ˚ (b) 1.59 A ˚ \mathring{A} A ˚ (c) 4.77 A ˚ \mathring{A} A ˚ (d) 0.53 A ˚ \mathring{A} A ˚ Show answer and solution
Answer: (c)
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Q61 JEE Main 2023 · 31 JAN · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The radius of electron's second stationary orbit in Bohr's atom is R. The radius of 3rd orbit will be
(a) 2.25R (b) 3 R 3R 3 R (c) R 3 \frac{R}{3} 3 R (d) 9 R 9R 9 R Show answer and solution
Answer: (a)
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Q62 JEE Main 2023 · 6 APR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The radius of fifth orbit of the Li + + \text{Li}^{++} Li ++ is __________ × 1 0 − 12 m \times 10^{-12}\text{ m} × 1 0 − 12 m .
Take: radius of hydrogen atom = 0.51 A ˚ = 0.51\ \mathring{A} = 0.51 A ˚
Numerical answer type. Work it out, then open the answer.
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Answer: 425
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Q63 MHT CET 2023 · 10 MAY · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The ratio of the velocity of the electron in the first Bohr orbit to that in the second Bohr orbit of hydrogen atom is
(a) 8 : 1 8 : 1 8 : 1 (b) 2 : 1 2 : 1 2 : 1 (c) 4 : 1 4 : 1 4 : 1 (d) 1 : 4 1 : 4 1 : 4 Show answer and solution
Answer: (b)
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Q64 JEE Main 2023 · 30 JAN · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Speed of an electron in Bohr's 7 7 7 th orbit for Hydrogen atom is 3.6 × 1 0 6 m/s 3.6 \times 10^{6}\text{ m/s} 3.6 × 1 0 6 m/s . The corresponding speed of the electron in 3 3 3 rd orbit, in m/s \text{m/s} m/s is:
(a) ( 1.8 × 1 0 6 ) (1.8 \times 10^{6}) ( 1.8 × 1 0 6 ) (b) ( 7.5 × 1 0 6 ) (7.5 \times 10^{6}) ( 7.5 × 1 0 6 ) (c) ( 8.4 × 1 0 6 ) (8.4 \times 10^{6}) ( 8.4 × 1 0 6 ) (d) ( 3.6 × 1 0 6 ) (3.6 \times 10^{6}) ( 3.6 × 1 0 6 ) Show answer and solution
Answer: (c)
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Q65 MHT CET 2023 · 9 MAY · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
For an electron moving in the n n n th Bohr orbit the deBroglie wavelength of an electron is
(a) n π r n\pi r nπ r (b) π r n \frac{\pi r}{n} n π r (c) n r 2 π \frac{nr}{2\pi} 2 π n r (d) 2 π r n \frac{2\pi r}{n} n 2 π r Show answer and solution
Answer: (d)
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Q66 MHT CET 2023 · 14 MAY · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Magnetic field at the centre of the hydrogen atom due to motion of electron in n n n th orbit is proportional to
(a) n 4 n^4 n 4 (b) n − 3 n^{-3} n − 3 (c) n 3 n^3 n 3 (d) n − 5 n^{-5} n − 5 Show answer and solution
Answer: (d)
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Q67 MHT CET 2023 · 11 MAY · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The orbital magnetic moment associated with orbiting electron of charge 'e e e ' is
(a) inversely proportional to angular momentum (b) directly proportional to mass of electron (c) directly proportional to angular momentum (d) inversely proportional to charge on electron Show answer and solution
Answer: (c)
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Q68 MHT CET 2023 · 9 MAY · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The force acting on the electron in hydrogen atom (Bohr' theory) is related to the principle quantum number 'n n n ' as
(a) n 4 n^4 n 4 (b) n − 4 n^{-4} n − 4 (c) n 2 n^2 n 2 (d) n − 2 n^{-2} n − 2 Show answer and solution
Answer: (b)
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Q69 JEE Main 2023 · 1 FEB · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
A light of energy 12.75 eV 12.75\text{ eV} 12.75 eV is incident on a hydrogen atom in its ground state. The atom absorbs the radiation and reaches to one of its excited states. The angular momentum of the atom in the excited state is x π × 1 0 − 17 eVs \frac{x}{\pi} \times 10^{-17}\text{ eVs} π x × 1 0 − 17 eVs . The value of x x x is ___________ (use h = 4.14 × 1 0 − 15 eVs , c = 3 × 1 0 8 ms − 1 h = 4.14 \times 10^{-15}\text{ eVs},\ c = 3 \times 10^{8}\text{ ms}^{-1} h = 4.14 × 1 0 − 15 eVs , c = 3 × 1 0 8 ms − 1 ).
Numerical answer type. Work it out, then open the answer.
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Answer: 828
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Q70 JEE Main 2023 · 13 APR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The radius of 2 2 2 nd orbit of He + \text{He}^{+} He + of Bohr's model is r 1 r_1 r 1 and that of fourth orbit of Be 3 + \text{Be}^{3+} Be 3 + is represented as r 2 r_2 r 2 . Now the ratio r 2 r 1 \frac{r_2}{r_1} r 1 r 2 is x : 1 x : 1 x : 1 . The value of x x x is ___________.
Numerical answer type. Work it out, then open the answer.
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Answer: 2
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Q71 JEE Main 2023 · 6 APR · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Experimentally it is found that 12.8 eV 12.8\text{ eV} 12.8 eV energy is required to separate a hydrogen atom into a proton and an electron. So the orbital radius of the electron in a hydrogen atom is 9 x × 1 0 − 10 m \frac{9}{x} \times 10^{-10}\text{ m} x 9 × 1 0 − 10 m . The value of the x x x is __________.
( 1 eV = 1.6 × 1 0 − 19 J , 1 4 π ϵ 0 = 9 × 1 0 9 Nm 2 / C 2 \Bigg(1\text{ eV} = 1.6 \times 10^{-19}\text{ J},\ \frac{1}{4\pi\epsilon_0} = 9 \times 10^{9}\text{ Nm}^2/\text{C}^2 ( 1 eV = 1.6 × 1 0 − 19 J , 4 π ϵ 0 1 = 9 × 1 0 9 Nm 2 / C 2 and electronic charge = 1.6 × 1 0 − 19 C ) = 1.6 \times 10^{-19}\text{ C}\Bigg) = 1.6 × 1 0 − 19 C )
Numerical answer type. Work it out, then open the answer.
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Answer: 16
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Q72 MHT CET 2023 · 11 MAY · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
An electron in the hydrogen atom jumps from the first excited state to the ground state. What will be the percentage change in the speed of electron?
(a) 25% (b) 50% (c) 75% (d) 100% Show answer and solution
Answer: (b)
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Q73 MHT CET 2023 · 14 MAY · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
If the radius of the first Bohr orbit is 'r r r ' then the de-Broglie wavelength of the electron in the 4 4 4 th orbit will be
(a) 4 π r 4\pi r 4 π r (b) 6 π r 6\pi r 6 π r (c) 8 π r 8\pi r 8 π r (d) π r 4 \frac{\pi r}{4} 4 π r Show answer and solution
Answer: (c)
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Q74 MHT CET 2023 · 11 MAY · SHIFT 2 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
Bohr model is applied to a particle of mass 'm m m ' and charge 'q q q ' moving in a plane under the influence of a transverse magnetic field 'B B B '. The energy of the charged particle in the n n n th leve will be [ h = [h = [ h = Planck's constant ] ] ]
(a) n h q B 4 π m \frac{nhqB}{4\pi m} 4 πm nh qB (b) n h q B 2 π m \frac{nhqB}{2\pi m} 2 πm nh qB (c) n h q B π m \frac{nhqB}{\pi m} πm nh qB nhqB(d) 2 n h q B π m \frac{2nhqB}{\pi m} πm 2 nh qB Show answer and solution
Answer: (a)
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Q75 JEE Main 2023 · 6 APR · SHIFT 2 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
A small particle of mass m m m moves in such a way that its potential energy U = 1 2 m ω 2 r 2 U = \frac{1}{2} m\omega^2 r^2 U = 2 1 m ω 2 r 2 where ω \omega ω is constant and r r r is the distance of the particle from origin. Assuming Bohr's quantization of momentum and circular orbit, the radius of n n n th orbit will be proportional to,
(a) n \sqrt{n} n (b) n 2 n^2 n 2 (c) 1 n \frac{1}{n} n 1 (d) n n n Show answer and solution
Answer: (a)
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Q76 JEE Main 2022 · 27 JUN · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Given below are two statements:
Statement I: In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit (E1) to higher energy orbit (E2), is given as hf = E1 − - − E2
Statement II: The jumping of electron from higher energy orbit (E2) to lower energy orbit (E1) is associated with frequency of radiation given as f = (E2 − - − E1)/h
This condition is Bohr's frequency condition.
In the light of the above statements, choose the correct answer from the options given below:
(a) Both Statement I and Statement II are true. (b) Both Statement I and Statement II are false. (c) Statement I is correct but Statement II is false. (d) Statement I is incorrect but Statement II is true. Show answer and solution
Answer: (d)
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Q77 NEET 2022 · PHASE 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Let R1 be the radius of the second stationary orbit and R2 be the radius of the fourth stationary orbit of an electron in Bohr's model. The ratio R 1 R 2 \frac{R_1}{R_2} R 2 R 1 is:
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Answer: (b)
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Q78 JEE Main 2022 · 30 JUL · SHIFT 2 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Using Boh'r model of quantization of angular momentum the relation between the radius 'r' of the n n n th allowed orbit of quantum number 'n' for an electron in hydrogen atom is:
(a) r ∝ n 1 2 r \propto n^{\frac{1}{2}} r ∝ n 2 1 (b) r ∝ n 2 r \propto n^2 r ∝ n 2 (c) r ∝ ( 1 n ) 2 r \propto \left(\frac{1}{n}\right)^2 r ∝ ( n 1 ) 2 (d) r ∝ ( 1 n ) 1 2 r \propto \left(\frac{1}{n}\right)^{\frac{1}{2}} r ∝ ( n 1 ) 2 1 Show answer and solution
Answer: (b)
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Q79 JEE Main 2022 · 25 JUN · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The ratio for the speed of the electron in the 3rd orbit of He+ to the speed of the electron in the 3rd orbit of hydrogen atom will be:
(a) 1: 1 (b) 1: 2 (c) 4: 1 (d) 2: 1 Show answer and solution
Answer: (d)
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Q80 JEE Main 2022 · 25 JUL · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The momentum of an electron revolving in n n n th orbit is given by:
(Symbols have their usual meanings)
(a) n h 2 π r \frac{nh}{2\pi r} 2 π r nh (b) n h 2 r \frac{nh}{2r} 2 r nh (c) n h 2 π \frac{nh}{2\pi} 2 π nh (d) 2 π r n h \frac{2\pi r}{nh} nh 2 π r Show answer and solution
Answer: (a)
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Q81 JEE Main 2022 · 25 JUL · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The magnetic moment of an electron (e) revolving in an orbit around nucleus with an orbital angular momentum is given by:
(a) μ ⃗ L = e L ⃗ 2 m \vec{\mu}_L = \frac{e\vec{L}}{2m} μ L = 2 m e L (b) μ ⃗ L = − e L ⃗ 2 m \vec{\mu}_L = -\frac{e\vec{L}}{2m} μ L = − 2 m e L (c) μ ⃗ l = − e L ⃗ m \vec{\mu}_l = -\frac{e\vec{L}}{m} μ l = − m e L (d) μ ⃗ l = 2 e L ⃗ m \vec{\mu}_l = \frac{2e\vec{L}}{m} μ l = m 2 e L Show answer and solution
Answer: (b)
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Q82 JEE Main 2022 · 30 JUN · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
A hydrogen atom in ground state absorbs 12.09 eV of energy. The orbital angular momentum of the electron is increased by:
(a) 1.05 × \times × 10− - − 34 Js (b) 2.11 × \times × 10− - − 34 Js (c) 3.16 × \times × 10− - − 34 Js (d) 4.22 × \times × 10− - − 34 Js Show answer and solution
Answer: (b)
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Q83 JEE Main 2022 · 27 JUN · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
A hydrogen atom in its ground state absorbs 10.2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of:
(Given, Planck's constant = 6.6 × \times × 10− - − 34 Js).
(a) 2.10 × \times × 10− - − 34 Js (b) 1.05 × \times × 10− - − 34 Js (c) 3.15 × \times × 10− - − 34 Js (d) 4.2 × \times × 10− - − 34 Js Show answer and solution
Answer: (b)
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Q84 MHT CET 2022 · 11 AUG · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Using Bohr's model, the orbital period of electron in hydrogen atom in the n n n th orbit is ( ε 0 = (\varepsilon_0 = ( ε 0 = permittivity of vacuum, h = h = h = Planck's constant, m = m = m = mass of electron, e = e = e = electronic charge)
(a) 4 ε 0 n h 3 m e 2 \frac{4\varepsilon_0 n h^3}{m e^2} m e 2 4 ε 0 n h 3 (b) 4 ε 0 n 2 h 2 m e 2 \frac{4\varepsilon_0 n^2 h^2}{m e^2} m e 2 4 ε 0 n 2 h 2 (c) 4 ε 0 2 n 3 h 3 m e 4 \frac{4\varepsilon_0^2 n^3 h^3}{m e^4} m e 4 4 ε 0 2 n 3 h 3 (d) 4 ε 0 2 n 2 h 3 m e 3 \frac{4\varepsilon_0^2 n^2 h^3}{m e^3} m e 3 4 ε 0 2 n 2 h 3 Show answer and solution
Answer: (c)
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Q85 JEE Main 2021 · 17 MAR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
If an electron is moving in the nth orbit of the hydrogen atom, then its velocity (vn) for the nth orbit is given as:
(a) v n ∝ 1 n v_n \propto \frac{1}{n} v n ∝ n 1 (b) vn ∝ \propto ∝ n2 (c) vn ∝ \propto ∝ n (d) v n ∝ 1 n 2 v_n \propto \frac{1}{n^2} v n ∝ n 2 1 Show answer and solution
Answer: (a)
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Q86 MHT CET 2021 · 23 SEP · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The energy of an electron in the excited hydrogen atom is − 3.4 eV -3.4\text{ eV} − 3.4 eV . Then according to Bohr's theory, the angular momentum of the electron in that excited state is (h = h = h = Plank's constant)
(a) 2 π h \frac{2\pi}{h} h 2 π (b) n h 2 π \frac{nh}{2\pi} 2 π nh (c) h π \frac{h}{\pi} π h (d) 3 h 2 π \frac{3h}{2\pi} 2 π 3 h Show answer and solution
Answer: (c)
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Q87 MHT CET 2021 · 21 SEP · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
When an electron in hydrogen atom jumps from third excited state to the ground state, the de- Broglie wavelength associated with the electron becomes
(a) ( 1 2 ) \left(\frac{1}{2}\right) ( 2 1 ) th(b) ( 1 4 ) \left(\frac{1}{4}\right) ( 4 1 ) th(c) ( 1 8 ) \left(\frac{1}{8}\right) ( 8 1 ) th(d) ( 1 6 ) \left(\frac{1}{6}\right) ( 6 1 ) thShow answer and solution
Answer: (b)
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Q88 JEE Main 2021 · 27 JUL · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
In Bohr's atomic model, the electron is assumed to revolve in a circular orbit of radius 0.5 A ˚ \mathring{A} A ˚ . If the speed of electron is 2.2 × \times × 106 m/s, then the current associated with the electron will be _____________ × \times × 10− - − 2 mA. [Take π \pi π as 22 7 \frac{22}{7} 7 22 ]
Numerical answer type. Work it out, then open the answer.
Show answer and solution
Answer: 112
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Q89 MHT CET 2021 · 23 SEP · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
In the Bohr model, an electron moves in a circular orbit around the nucleus. Considering an orbiting electron to be a circular current loop, the magnetic moment of the hydrogen atom, when the electron is in nth excited state, is
(e = electronic charge, me {}_{e} e = mass of the electron, h = Planck's constant)
(a) ( e m e ) n h 2 π \left(\frac{e}{m_e}\right)\frac{nh}{2\pi} ( m e e ) 2 π nh (b) ( e m e ) n 2 h 2 π \left(\frac{e}{m_e}\right)\frac{n^2 h}{2\pi} ( m e e ) 2 π n 2 h (c) ( e 2 m e ) n 2 h 2 π \left(\frac{e}{2m_e}\right)\frac{n^2 h}{2\pi} ( 2 m e e ) 2 π n 2 h (d) ( e 2 m e ) n h 2 π \left(\frac{e}{2m_e}\right)\frac{nh}{2\pi} ( 2 m e e ) 2 π nh Show answer and solution
Answer: (d)
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Q90 MHT CET 2021 · 20 SEP · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The gyromagnetic ratio of an electron in an hydrogen atom, according to Bohr model is
(a) decreases with the quantum number 'n'. (b) independent of which orbit it is in. (c) negative (d) positive Show answer and solution
Answer: (b)
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Q91 MHT CET 2021 · 21 SEP · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Ratio centripetal acceleration for an electron revolving in 3rd and 5th Bohr orbit of hydrogen atom is
(a) 425: 18 (b) 625: 81 (c) 125: 27 (d) 221: 36 Show answer and solution
Answer: (b)
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Q92 JEE Main 2021 · 18 MAR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Imagine that the electron in a hydrogen atom is replaced by a muon (μ \mu μ ). The mass of muon particle is 207 times that of an electron and charge is equal to the charge of an electron. The ionization potential of this hydrogen atom will be:
(a) 13.6 eV (b) 2815.2 eV (c) 331.2 eV (d) 27.2 eV Show answer and solution
Answer: (b)
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Q93 JEE Main 2021 · 17 MAR · SHIFT 2 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
A particle of mass m moves in a circular orbit in a
central potential field U(r) = U0r4. If Bohr's quantization conditions
are applied, radii of possible
orbitals rn vary with n α n^{\alpha} n α , where α \alpha α is ____________.
Numerical answer type. Work it out, then open the answer.
Show answer and solution
Answer: 3
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Q94 NEET 2020 · PHASE 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
For which one of the following, Bohr model is not valid?
(a) Singly ionised helium atom (He+) (b) Deuteron atom (c) Singly ionised neon atom (Ne+) (d) Hydrogen atom Show answer and solution
Answer: (c)
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Q95 MHT CET 2020 · 16 OCT · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The force acting on the electrons in hydrogen atom (Bohr's theory) is related to the principle quantum number n n n as
(a) n − 4 n^{-4} n − 4 (b) n 4 n^4 n 4 (c) n − 2 n^{-2} n − 2 (d) n 2 n^2 n 2 Show answer and solution
Answer: (a)
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Q96 MHT CET 2020 · 16 OCT · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The ratio of speed of an electron in the ground state in the Bohr's first orbit of hydrogen atom to velocity of light ( c ) (c) ( c ) is ( h = h = h = Planck's constant, ε 0 = \varepsilon_0 = ε 0 = permittivity of free space, e = e = e = charge on electron)
(a) 2 e 2 ε 0 h c \frac{2e^2\varepsilon_0}{hc} h c 2 e 2 ε 0 (b) e 3 2 ε 0 h c \frac{e^3}{2\varepsilon_0 hc} 2 ε 0 h c e 3 (c) e 2 2 ε 0 h c \frac{e^2}{2\varepsilon_0 hc} 2 ε 0 h c e 2 (d) 2 ε 0 h c e 2 \frac{2\varepsilon_0 hc}{e^2} e 2 2 ε 0 h c Show answer and solution
Answer: (c)
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Q97 MHT CET 2020 · 19 OCT · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Using Bohr's model, the orbital period of electron in hydrogen atom in n n n th orbit is ( ε 0 = \varepsilon_0 = ε 0 = permittivity of free space, h = h = h = Planck's constant, m = m = m = mass of electron and e = e = e = electronic charge)
(a) 2 ε 0 2 n 3 h 3 m e 4 \frac{2\varepsilon_0^2 n^3 h^3}{m e^4} m e 4 2 ε 0 2 n 3 h 3 (b) 8 ε 0 2 n 3 h 3 m e 4 \frac{8\varepsilon_0^2 n^3 h^3}{m e^4} m e 4 8 ε 0 2 n 3 h 3 (c) 2 ε 0 n 2 h 2 m e 4 \frac{2\varepsilon_0 n^2 h^2}{m e^4} m e 4 2 ε 0 n 2 h 2 (d) 4 ε 0 2 n 3 h 3 m e 4 \frac{4\varepsilon_0^2 n^3 h^3}{m e^4} m e 4 4 ε 0 2 n 3 h 3 Show answer and solution
Answer: (d)
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Q98 JEE Main 2020 · 7 JAN · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6 × \times × 10-16 s. The frequency of revolution of the electron in its first excited state (in s-1) is:
(a) 5.6 × \times × 1012 (b) 1.6 × \times × 1014 (c) 7.8 × \times × 1014 (d) 6.2 × \times × 1015 Show answer and solution
Answer: (c)
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Q99 MHT CET 2020 · 16 OCT · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Using Bohr's quantisation condition, what is the rotational energy in the second orbit for a diatomic molecule? (I = I = I = moment of inertia of diatomic molecule and, h = h = h = Planck's constant)
(a) h 2 I π 2 \frac{h}{2I\pi^2} 2 I π 2 h (b) h 2 2 I π 2 \frac{h^2}{2I\pi^2} 2 I π 2 h 2 (c) h 2 2 I 2 π 2 \frac{h^2}{2I^2\pi^2} 2 I 2 π 2 h 2 (d) h 2 I 2 π \frac{h}{2I^2\pi} 2 I 2 π h Show answer and solution
Answer: (b)
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Q100 MHT CET 2019 · 3 MAY · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
If the speed of an electron of hydrogen atom in the ground state is 2.2 × 1 0 6 m/s 2.2 \times 10^{6}\text{ m/s} 2.2 × 1 0 6 m/s , then its speed in the third excited state will be
(a) 5.5 × 1 0 6 m/s 5.5 \times 10^{6}\text{ m/s} 5.5 × 1 0 6 m/s (b) 5.5 × 1 0 5 m/s 5.5 \times 10^{5}\text{ m/s} 5.5 × 1 0 5 m/s (c) 8.8 × 1 0 5 m/s 8.8 \times 10^{5}\text{ m/s} 8.8 × 1 0 5 m/s (d) 6.8 × 1 0 6 m/s 6.8 \times 10^{6}\text{ m/s} 6.8 × 1 0 6 m/s Show answer and solution
Answer: (b)
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Q101 MHT CET 2019 · 2 MAY · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The angle made by orbital angular momentum of electron with the direction of the orbital magnetic moment is
(a) 12 0 ∘ 120^\circ 12 0 ∘ (b) 6 0 ∘ 60^\circ 6 0 ∘ (c) 18 0 ∘ 180^\circ 18 0 ∘ (d) 9 0 ∘ 90^\circ 9 0 ∘ Show answer and solution
Answer: (c)
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Q102 JEE Main 2019 · 12 APR · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Consider an electron in a hydrogen atom revolving in its second excited state (having radius 4.65 A ˚ \mathring{A} A ˚ ). The de-Broglie wavelength of this electron is:
(a) 6.6 A ˚ \mathring{A} A ˚ (b) 3.5 A ˚ \mathring{A} A ˚ (c) 9.7 A ˚ \mathring{A} A ˚ (d) 12.9 A ˚ \mathring{A} A ˚ Show answer and solution
Answer: (c)
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Q103 NEET 2019 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The radius of the first permitted Bohr orbit, for the electron, in a hydrogen atom equals 0.51 Å and its ground state energy equals − 13.6 eV -13.6\text{ eV} − 13.6 eV . If the electron in the hydrogen atom is replaced by muon (μ − \mu^- μ − ) [charge same as electron and mass 207 m e 207\, m_e 207 m e ], the first Bohr radius and ground state energy will be,
(a) 2.56 × 1 0 − 13 m , − 13.6 eV 2.56 \times 10^{-13}\text{ m}, -13.6\text{ eV} 2.56 × 1 0 − 13 m , − 13.6 eV (b) 0.53 × 1 0 − 13 m , − 3.6 eV 0.53 \times 10^{-13}\text{ m}, -3.6\text{ eV} 0.53 × 1 0 − 13 m , − 3.6 eV (c) 25.6 × 1 0 − 13 m , − 2.8 eV 25.6 \times 10^{-13}\text{ m}, -2.8\text{ eV} 25.6 × 1 0 − 13 m , − 2.8 eV (d) 2.56 × 1 0 − 13 m , − 2.8 keV 2.56 \times 10^{-13}\text{ m}, -2.8\text{ keV} 2.56 × 1 0 − 13 m , − 2.8 keV Show answer and solution
Answer: (d)
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Q104 MHT CET 2019 · 2 MAY · SHIFT 1 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
Bohr model is applied to a particle of mass ' m m m ' and charge ' q q q ' is moving in a plane under the influence of a transverse magnetic field ' B B B '. The energy of the charged particle in the n n n th level will be ( h = h = h = Planck's constant)
(a) 2 n h q B / π m 2nhqB/\pi m 2 nh qB / πm (b) n h q B / 2 π m nhqB/2\pi m nh qB /2 πm (c) n h q B / 4 π m nhqB/4\pi m nh qB /4 πm (d) n h q B / π m nhqB/\pi m nh qB / πm Show answer and solution
Answer: (c)
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Q105 JEE Main 2019 · 12 JAN · SHIFT 1 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
A particle of mass m moves in a circular orbit in a central potential field U(r) = 1 2 \frac{1}{2} 2 1 kr2. If Bohr 's quantization conditions are applied, radii of possible orbitls and energy levels vary with quantum number n as:
(a) rn ∝ n \propto \sqrt{n} ∝ n , En ∝ \propto ∝ n (b) rn ∝ n \propto \sqrt{n} ∝ n , En ∝ 1 n \propto \frac{1}{n} ∝ n 1 (c) rn ∝ \propto ∝ n, En ∝ \propto ∝ n (d) rn ∝ \propto ∝ n2, En ∝ 1 n 2 \propto \frac{1}{n^2} ∝ n 2 1 Show answer and solution
Answer: (a)
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Q106 JEE Main 2018 · 15 APR · SHIFT 2 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Muon (μ − \mu^- μ − ) is a negatively charged (|q| = |e|) particle with a mass mμ \mu μ = 200 me, where me is the mass of the electron and e is the electronic charge. If μ − \mu^- μ − is bound to a proton to form a hydrogen like atom, identify the correct statements.
(A) Radius of the muonic orbit is 200 times smaller than that of the electron.
(B) The speed of the μ − \mu^- μ − in the nth orbit is 1 200 \frac{1}{200} 200 1 times that of the electron in the nth orbit. (C) The ionization energy of muonic atom is 200 times more than that of a hydrogen atom. (D) The momentum of the muon in the nth orbit is 200 times more than that of the electron.
(a) (A), (B), (D) (b) (A), (C), (D) (c) (B), (D) (d) (C), (D) Show answer and solution
Answer: (b)
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Q107 JEE Main 2018 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
An electron from various excited states of hydrogen atom emit radiation to come to the ground state. Let λ n , λ g \lambda_n, \lambda_g λ n , λ g be the de Broglie wavelength of the electron in the nth state and the ground state respectively. Let Λ n \Lambda_n Λ n be the wavelength of the emitted photon in the transition from the nth state to the ground state. For large n, (A, B are constants)
(a) Λ n ≈ A + B λ n 2 \Lambda_n \approx A + \frac{B}{\lambda_n^2} Λ n ≈ A + λ n 2 B (b) Λ n ≈ A + B λ n \Lambda_n \approx A + B\lambda_n Λ n ≈ A + B λ n (c) Λ n 2 ≈ A + B λ n 2 \Lambda_n^2 \approx A + B\lambda_n^2 Λ n 2 ≈ A + B λ n 2 (d) Λ n 2 ≈ λ \Lambda_n^2 \approx \lambda Λ n 2 ≈ λ Show answer and solution
Answer: (a)
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Q108 JEE Main 2017 · 8 APR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
According to Bohr’s theory, the time averaged magnetic field at the centre (i.e. nucleus) of a hydrogen atom due to the motion of electrons in the nth orbit is proportional to: (n = principal quantum number)
(a) n − 4 n^{-4} n − 4 (b) n − 5 n^{-5} n − 5 (c) n− 3 {}^{-3} − 3 (d) n− 2 {}^{-2} − 2 Show answer and solution
Answer: (b)
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Q109 JEE Main 2017 · 9 APR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
The acceleration of an electron in the first orbit of the hydrogen atom (n = 1) is:
(a) h 2 π 2 m 2 r 3 \frac{h^2}{\pi^2 m^2 r^3} π 2 m 2 r 3 h 2 (b) h 2 8 π 2 m 2 r 3 \frac{h^2}{8\pi^2 m^2 r^3} 8 π 2 m 2 r 3 h 2 (c) h 2 4 π 2 m 2 r 3 \frac{h^2}{4\pi^2 m^2 r^3} 4 π 2 m 2 r 3 h 2 (d) h 2 4 π m 2 r 3 \frac{h^2}{4\pi m^2 r^3} 4 π m 2 r 3 h 2 Show answer and solution
Answer: (c)
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Q110 JEE Main 2015 · 11 APR · SHIFT 1 Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
The de - Broglie wavelength associated with the electron in the n = 4 level is:
(a) two times the de-Broglie wavelength of the electron in the ground state (b) four times the de -Broglie wavelength of the electron in the ground state (c) half of the de-Broglie wavelength of the electron in the ground state (d) 1/4th of the de-Broglie wavelength of the electron in the ground state Show answer and solution
Answer: (b)
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Q111 NEET 2015 · AIPMT · CANCELLED PAPER Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
Consider 3rd orbit of He+ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K = 9 × \times × 109 constant, Z = 2 and h (Planck's Constant) = 6.6 × \times × 10− - − 34 J s]
(a) 0.73 × \times × 106 m/s (b) 3.0 × \times × 108 m/s (c) 2.92 × \times × 106 m/s (d) 1.46 × \times × 106 m/s Show answer and solution
Answer: (d)
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Q112 JEE Main 2015 · 10 APR · SHIFT 1 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
If one were to apply Bohr model to a particle of mass 'm' and charge 'q' moving in a plane under the influence of a magnetic field 'B', the energy of the charged particle in the nth level will be:
(a) n ( h q B 2 π m ) n\left(\frac{hqB}{2\pi m}\right) n ( 2 πm h qB ) (b) n ( h q B 4 π m ) n\left(\frac{hqB}{4\pi m}\right) n ( 4 πm h qB ) (c) n ( h q B 8 π m ) n\left(\frac{hqB}{8\pi m}\right) n ( 8 πm h qB ) (d) n ( h q B π m ) n\left(\frac{hqB}{\pi m}\right) n ( πm h qB ) Show answer and solution
Answer: (b)
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Q113 NEET 2013 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
An electron in hydrogen atom makes a transition n1 → \to → n2 where n1 and n2 are principal quantum numbers of the two states. Assuming Bohr's model to be valid, the time period of the electron in the initial state is eight times that in the final state. The possible values of n1 and n2 are
(a) n1 = 6 and n2 = 2 (b) n1 = 8 and n2 = 1 (c) n1 = 8 and n2 = 2 (d) n1 = 4 and n2 = 2 Show answer and solution
Answer: (d)
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Q114 JEE Main 2013 · 9 APR · SHIFT 1 Medium ☆
Bohr Model: Orbits, Speed & Angular Momentum
In the Bohr model an electron moves in a circular orbit around the proton. Considering the orbiting electron to be a circular current loop, the magnetic moment of the hydrogen atom, when the electron is in n t h n^{th} n t h excited state, is:
(a) ( e 2 m ) n 2 h 2 π \left(\frac{e}{2m}\right)\frac{n^2 h}{2\pi} ( 2 m e ) 2 π n 2 h (b) ( e m ) n h 2 π \left(\frac{e}{m}\right)\frac{nh}{2\pi} ( m e ) 2 π nh (c) ( e 2 m ) n h 2 π \left(\frac{e}{2m}\right)\frac{nh}{2\pi} ( 2 m e ) 2 π nh (d) ( e m ) n 2 h 2 π \left(\frac{e}{m}\right)\frac{n^2 h}{2\pi} ( m e ) 2 π n 2 h Show answer and solution
Answer: (c)
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Q115 JEE Main 2013 · 23 APR · SHIFT 1 Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
In the Bohr's model of hydrogen-like atom the force between the nucleus and the electron is modified as F = e 2 4 π ϵ 0 ( 1 r 2 + β r 3 ) F = \frac{e^2}{4\pi\epsilon_0}\left(\frac{1}{r^2} + \frac{\beta}{r^3}\right) F = 4 π ϵ 0 e 2 ( r 2 1 + r 3 β ) , where β \beta β is a constant. For this atom, the radius of the n t h n^{th} n t h orbit in terms of the Bohr radius ( a 0 = ϵ 0 h 2 m π e 2 ) \left(a_0 = \frac{\epsilon_0 h^2}{m\pi e^2}\right) ( a 0 = mπ e 2 ϵ 0 h 2 ) is:
(a) r n = a 0 n − β r_n = a_0 n - \beta r n = a 0 n − β (b) r n = a 0 n 2 + β r_n = a_0 n^2 + \beta r n = a 0 n 2 + β (c) r n = a 0 n 2 − β r_n = a_0 n^2 - \beta r n = a 0 n 2 − β (d) r n = a 0 n + β r_n = a_0 n + \beta r n = a 0 n + β Show answer and solution
Answer: (c)
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Q116 JEE Main 2012 · AIEEE Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
A diatomic molecule is made of two masses m 1 m_1 m 1 and m 2 m_2 m 2 which are separated by a distance r . r. r . If we calculate its rotational energy by applying Bohr's rule of angular momentum quantization, its energy will be given by: (n n n is an integer)
(a) ( m 1 + m 2 ) 2 n 2 h 2 2 m 1 2 m 2 2 r 2 \frac{(m_1+m_2)^2 n^2 h^2}{2m_1^2 m_2^2 r^2} 2 m 1 2 m 2 2 r 2 ( m 1 + m 2 ) 2 n 2 h 2 (b) n 2 h 2 2 ( m 1 + m 2 ) r 2 \frac{n^2 h^2}{2(m_1+m_2) r^2} 2 ( m 1 + m 2 ) r 2 n 2 h 2 (c) 2 n 2 h 2 ( m 1 + m 2 ) r 2 \frac{2n^2 h^2}{(m_1+m_2) r^2} ( m 1 + m 2 ) r 2 2 n 2 h 2 (d) ( m 1 + m 2 ) n 2 h 2 2 m 1 m 2 r 2 \frac{(m_1+m_2) n^2 h^2}{2m_1 m_2 r^2} 2 m 1 m 2 r 2 ( m 1 + m 2 ) n 2 h 2 Show answer and solution
Answer: (d)
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Q117 JEE Main 2008 · AIEEE Difficult ☆
Bohr Model: Orbits, Speed & Angular Momentum
Suppose an electron is attracted towards the origin by a force k r \frac{k}{r} r k where ′ k ′ 'k' ′ k ′ is a constant and ′ r ′ 'r' ′ r ′ is the distance of the electron from the origin. By applying Bohr model to this system, the radius of the n t h n^{th} n t h orbital of the electron is found to be ′ r n ′ 'r_n' ′ r n ′ and the kinetic energy of the electron to be ′ T n ′ . 'T_n'. ′ T n ′ . Then which of the following is true?
(a) T n ∝ 1 n 2 , r n ∝ n 2 T_n \propto \frac{1}{n^2},\ r_n \propto n^2 T n ∝ n 2 1 , r n ∝ n 2 (b) T n T_n T n independent of n , r n ∝ n n,\ r_n \propto n n , r n ∝ n (c) T n ∝ 1 n , r n ∝ n T_n \propto \frac{1}{n},\ r_n \propto n T n ∝ n 1 , r n ∝ n (d) T n ∝ 1 n , r n ∝ n 2 T_n \propto \frac{1}{n},\ r_n \propto n^2 T n ∝ n 1 , r n ∝ n 2 Show answer and solution
Answer: (b)
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Q118 NEET 2004 · AIPMT Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
(a) Assumes that the angular momentum of electrons is quantized. (b) Uses Einstein's photoelectric equation. (c) Predicts continuous emission spectra fror atoms. (d) Predicts the same emission spectra for all types of atoms. Show answer and solution
Answer: (a)
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Q119 NEET 2003 · AIPMT Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
In which of the following systems will the radius of the first orbit (n = 1) be minimum?
(a) doubly ionized lithium (b) singly ionized helium (c) deuterium atom (d) hydrogen atom Show answer and solution
Answer: (a)
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Q120 NEET 2003 · AIPMT Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius r. The Coulomb force F ⃗ \vec{F} F between the two is
(a) K e 2 r 2 r ^ K\frac{e^2}{r^2}\hat{r} K r 2 e 2 r ^ (b) − K e 2 r 3 r ^ -K\frac{e^2}{r^3}\hat{r} − K r 3 e 2 r ^ (c) K e 2 r 3 r ^ K\frac{e^2}{r^3}\hat{r} K r 3 e 2 r ^ (d) − K e 2 r 2 r ^ -K\frac{e^2}{r^2}\hat{r} − K r 2 e 2 r ^ Show answer and solution
Answer: (d)
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Q121 NEET 1998 · AIPMT Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
In the Bohr's model of a hydrogen atom, the centripetal force is furnished by the Coulomb attraction between the proton and the electron. If a 0 a_0 a 0 is the radius of the ground state orbit, m m m is the mass and e e e is the charge on the electron, ε 0 \varepsilon_0 ε 0 is the vacuum permittivity, the speed of the electron is
(a) zero (b) e ε 0 a 0 m \frac{e}{\sqrt{\varepsilon_0 a_0 m}} ε 0 a 0 m e (c) e 4 π ε 0 a 0 m \frac{e}{\sqrt{4\pi\varepsilon_0 a_0 m}} 4 π ε 0 a 0 m e (d) 4 π ε 0 a 0 m e \frac{\sqrt{4\pi\varepsilon_0 a_0 m}}{e} e 4 π ε 0 a 0 m Show answer and solution
Answer: (c)
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Q122 NEET 1997 · AIPMT Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
When hydrogen atom is in its first excited level, its radius is .......... of the Bohr radius.
(a) twice (b) 4 times (c) same (d) half. Show answer and solution
Answer: (b)
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Q123 NEET 1996 · AIPMT Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
According to Bohr's principle, the relation between principal quantum number (n n n ) and radius of orbit (r r r ) is
(a) r ∝ 1 n r \propto \frac{1}{n} r ∝ n 1 (b) r ∝ 1 n 2 r \propto \frac{1}{n^2} r ∝ n 2 1 (c) r ∝ n r \propto n r ∝ n (d) r ∝ n 2 r \propto n^2 r ∝ n 2 Show answer and solution
Answer: (d)
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Q124 NEET 1992 · AIPMT Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
In terms of Bohr radius a 0 a_0 a 0 , the radius of the second Bohr orbit of a hydrogen atom is given by
(a) 4 a 0 4a_0 4 a 0 (b) 8 a 0 8a_0 8 a 0 (c) 2 a 0 \sqrt{2}\,a_0 2 a 0 (d) 2 a 0 2a_0 2 a 0 Show answer and solution
Answer: (a)
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Q125 NEET 1990 · AIPMT Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
Consider an electron in the n n n th orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of de Broglie wavelength λ \lambda λ of that electron as
(a) ( 0.529 ) n λ (0.529)n\lambda ( 0.529 ) nλ (b) n λ \sqrt{n}\,\lambda n λ (c) ( 13.6 ) λ (13.6)\lambda ( 13.6 ) λ (d) n λ n\lambda nλ Show answer and solution
Answer: (d)
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Q126 NEET 1989 · AIPMT Easy ☆
Bohr Model: Orbits, Speed & Angular Momentum
To explain his theory, Bohr used
(a) conservation of linear momentum (b) quantisation of angular momentum (c) conservation of quantum frequency (d) none of these Show answer and solution
Answer: (b)
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