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Hydrogen Spectrum & Spectral Series

Questions
60
MHT CET
31
JEE Main
18
NEET
11
Years
1993–2026
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Q1MHT CET 2026 · 20 MAY · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

Which one of the following spectral series of hydrogen atom lies in ultraviolet region?

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Answer: (a)

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Q2MHT CET 2026 · 13 MAY · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The ratio of minimum wavelengths of Lyman and Balmer series will be

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Answer: (b)

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Q3MHT CET 2026 · 12 MAY · SHIFT 2Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In Bohr's theory of hydrogen atom, in any series of spectral lines, wavelength of first line and corresponding series limit is respectively

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Answer: (a)

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Q4MHT CET 2026 · 17 APR · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

For wavelength of visible radiation of Hydrogen spectrum, Balmer gave an equation as λ=xm2m2−4\lambda = \frac{xm^2}{m^2 - 4}, where m is the integer value. The value of x in terms of Rydberg's constant R is

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Answer: (b)

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Q5JEE Main 2026 · 23 JAN · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

In hydrogen atom spectrum, ( R→R \rightarrow Rydberg's constant)

A. the maximum wavelength of the radiation of Lyman series is 43R\frac{4}{3R}

B. the Balmer series lies in the visible region of the spectrum

C. the minimum wavelength of the radiation of Paschen series is 9R\frac{9}{R}

D. the minimum wavelength of Lyman series is 54R\frac{5}{4R}

Choose the correct answer from the options given below:

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Answer: (d)

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Q6MHT CET 2026 · 14 MAY · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

If λ1\lambda_1 and λ2\lambda_2 are the wavelengths of the first members of the Lyman and Paschen series respectively then λ1:λ2\lambda_1 : \lambda_2 is

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Answer: (d)

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Q7MHT CET 2026 · 19 APR · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The shortest wavelength in the Balmer series of hydrogen atom is equal to the shortest wavelength in the Brackett series of a hydrogen like atom of atomic number 'Z'. The value of 'Z' is

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Answer: (d)

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Q8JEE Main 2026 · 22 JAN · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The smallest wavelength of Lyman series is 91 nm. The difference between the largest wavelengths of Paschen and Balmer series is nearly ______ nm.

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Answer: (c)

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Q9MHT CET 2025 · 20 APR · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In hydrogen spectrum, the ratio of wavelengths of the last line of Lyman series and that of the last line of Balmer series is

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Answer: (c)

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Q10MHT CET 2025 · 19 APR · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The ratio of the wavelength of the last line of Paschen series to that of Balmer series is

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Answer: (a)

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Q11JEE Main 2025 · 7 APR · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

For a hydrogen atom, the ratio of the largest wavelength of Lyman series to that of the Balmer series is

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Answer: (a)

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Q12MHT CET 2025 · 26 APR · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The frequencies for series limit of Balmer and Paschen series are ' ν1\nu_1 ' and ' ν3\nu_3 ' respectively. If frequency of first line of Balmer series ' ν2\nu_2 ' then the relation between ν1,ν2\nu_1, \nu_2 and ν3\nu_3 is

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Answer: (c)

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Q13MHT CET 2025 · 26 APR · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In Paschen series, wavelength of first line is ' λ1\lambda_1 ' and for Brackett series, wavelength of first line is ' λ2\lambda_2 ' then ratio λ1λ2\frac{\lambda_1}{\lambda_2} is

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Answer: (c)

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Q14MHT CET 2025 · 19 APR · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

If ' λ1\lambda_1 ' and ' λ2\lambda_2 ' are the wavelengths of the first member of the Balmer and Paschen series, in hydrogen atom respectively, then the ratio of respective frequencies, f1/f2f_1/f_2, is

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Answer: (a)

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Q15MHT CET 2024 · 9 MAY · SHIFT 2Easy

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

The spectral series observed for hydrogen atom found in visible region is

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Answer: (b)

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Q16NEET 2024Easy

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

The spectral series which corresponds to the electronic transition from the levels n2=5,6,…n_2 = 5, 6, \ldots to the level n1=4n_1 = 4 is

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Answer: (b)

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Q17MHT CET 2024 · 16 MAY · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

Frequency of the series limit of Balmer series of hydrogen atom of Rydberg's constant ' RR ' and velocity of light ' CC ' is

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Answer: (a)

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Q18MHT CET 2024 · 9 MAY · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In hydrogen atom, ratio of the shortest wavelength in the Balmer series to that in the Paschen series is

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Answer: (c)

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Q19MHT CET 2024 · 4 MAY · SHIFT 2Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The ratio of minimum wavelengths of Lyman and Balmer series will be

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Answer: (b)

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Q20JEE Main 2024 · 6 APR · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is:

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Answer: (d)

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Q21MHT CET 2024 · 9 MAY · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

According to Bohr's theory of hydrogen atom, the ratio of the maximum and minimum wavelength of Lyman series will be

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Answer: (b)

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Q22MHT CET 2024 · 3 MAY · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

If ' λ1\lambda_1 ' and ' λ2\lambda_2 ' are the wavelengths of the first line of the Lyman and Paschen series respectively, then λ2:λ1\lambda_2 : \lambda_1 is

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Answer: (d)

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Q23JEE Main 2024 · 6 APR · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The longest wavelength associated with Paschen series is: (Given RH=1.097×107 SIR_H = 1.097 \times 10^{7}\text{ SI} unit)

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Answer: (b)

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Q24JEE Main 2024 · 31 JAN · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

If the wavelength of the first member of Lyman series of hydrogen is λ\lambda. The wavelength of the second member will be

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Answer: (c)

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Q25JEE Main 2024 · 5 APR · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The shortest wavelength of the spectral lines in the Lyman series of hydrogen spectrum is 915 A˚915\text{ Å}. The longest wavelength of spectral lines in the Balmer series will be _______ A˚\text{Å}.

Numerical answer type. Work it out, then open the answer.

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Answer: 6588

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Q26JEE Main 2024 · 27 JAN · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

If Rydberg's constant is RR, the longest wavelength of radiation in Paschen series will be α7R\frac{\alpha}{7R}, where α=\alpha = ________.

Numerical answer type. Work it out, then open the answer.

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Answer: 144

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Q27NEET 2024Difficult

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

Match List I with List II:

Choose the correct answer from the options given below:

List I (Spectral Lines of Hydrogen for transitions from)List II (Wavelengths (nm))
A.n2=3n_2 = 3 to n1=2n_1 = 2I.410.2
B.n2=4n_2 = 4 to n1=2n_1 = 2II.434.1
C.n2=5n_2 = 5 to n1=2n_1 = 2III.656.3
D.n2=6n_2 = 6 to n1=2n_1 = 2IV.486.1
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Answer: (b)

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Q28NEET 2023Easy

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

The wavelength of Lyman series of hydrogen atom appears in:

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Answer: (c)

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Q29MHT CET 2023 · 14 MAY · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

Frequency of the series limit of Balmer series of hydrogen atom in terms of Rydberg's constant (R) and velocity of light (c) is

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Answer: (d)

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Q30MHT CET 2023 · 14 MAY · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

Ratio of longest wavelength corresponding to Lyman and Balmer series in hydrogen spectrum is

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Answer: (c)

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Q31MHT CET 2023 · 12 MAY · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In Balmer series, wavelength of the 22nd line is 'λ1\lambda_1' and for Paschen series, wavelength of the 11st line is 'λ2\lambda_2', then the ratio 'λ1\lambda_1 ' to 'λ2\lambda_2' is

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Answer: (c)

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Q32MHT CET 2023 · 12 MAY · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In Lyman series, series limit of wavelength is λ1\lambda_1. The wavelength of first line of Lyman series is λ2\lambda_2 and in Balmer series, the series limit of wavelength is λ3\lambda_3. Then the relation between λ1,λ2\lambda_1, \lambda_2 and λ3\lambda_3 is

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Answer: (d)

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Q33MHT CET 2023 · 10 MAY · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The shortest wavelength in the Balmer series of hydrogen atom is equal to the shortest wavelength in the Brackett series of a hydrogen like atom of atomic number zz. The value of zz is

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Answer: (a)

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Q34MHT CET 2023 · 10 MAY · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The ratio of longest to shortest wavelength emitted in Paschen series of hydrogen atom is

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Answer: (a)

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Q35NEET 2023Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In hydrogen spectrum, the shortest wavelength in the Balmer series is λ\lambda. The shortest wavelength in the Brackett series is:

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Answer: (a)

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Q36JEE Main 2023 · 10 APR · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

If 917 A˚\text{Å} be the lowest wavelength of Lyman series then the lowest wavelength of Balmer series will be ___________ A˚\text{Å}.

Numerical answer type. Work it out, then open the answer.

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Answer: 3668

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Q37JEE Main 2023 · 8 APR · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The ratio of wavelength of spectral lines Hα\text{H}_\alpha and Hβ\text{H}_\beta in the Balmer series is x20\frac{x}{20}. The value of xx is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 27

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Q38MHT CET 2022 · 11 AUG · SHIFT 2Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The wave number of the last line of the Balmer series in hydrogen spectrum will be (Rydberg's constant =107 m−1= 10^{7}\text{ m}^{-1})

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Answer: (b)

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Q39JEE Main 2022 · 26 JUL · SHIFT 1Difficult

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In the hydrogen spectrum, λ\lambda be the wavelength of first transition line of Lyman series. The wavelength difference will be "aλ\lambda'' between the wavelength of 33rd transition line of Paschen series and that of 22nd transition line of Balmer series where a=a = ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 5

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Q40JEE Main 2021 · 17 MAR · SHIFT 2Easy

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

The atomic hydrogen emits a line spectrum consisting of various series. Which series of hydrogen atomic spectra is lying in the visible region?

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Answer: (b)

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Q41MHT CET 2021 · 24 SEP · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The ratio of maximum to minimum wavelength in Balmer series of hydrogen atom is

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Answer: (c)

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Q42MHT CET 2021 · 23 SEP · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The shortest wavelength for Lyman series is 912 A˚\text{Å}. The longest wavelength in Paschen series is

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Answer: (c)

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Q43MHT CET 2021 · 21 SEP · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

'λ1\lambda_1' is the wavelength of series limit of Lyman series, 'λ2\lambda_2 ' is the wavelength of the first line line of Lyman series and 'λ3\lambda_3' is the series limit of the Balmer series. Then the relation between λ1,λ2\lambda_1, \lambda_2 and λ3\lambda_3 is

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Answer: (a)

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Q44JEE Main 2021 · 26 FEB · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

If λ\lambda1 and λ\lambda2 are the wavelengths of the third member of Lyman and first member of the Paschen series respectively, then the value of λ\lambda1: λ\lambda2 is:

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Answer: (a)

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Q45JEE Main 2021 · 16 MAR · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The first three spectral lines of H-atom in the Balmer series are

given λ\lambda1, λ\lambda2, λ\lambda3 considering the Bohr atomic model, the wave lengths of first and third spectral lines (λ1λ3)\left(\frac{\lambda_1}{\lambda_3}\right) are related by a factor of approximately 'x' ×\times 10−-1.

The value of x, to the nearest integer, is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 15

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Q46JEE Main 2020 · 4 SEP · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In the line spectra of hydrogen atoms, difference between the largest and the shortest wavelengths {} of the Lyman series is 304 A˚\text{Å}. The corresponding difference for the Paschan series in A˚\text{Å} is: ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 10553

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Q47JEE Main 2020 · 8 JAN · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The first member of the Balmer series of hydrogen atom has a wavelength of 6561 Å. The wavelength of the second member of the Balmer series (in nm) is:

Numerical answer type. Work it out, then open the answer.

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Answer: 486

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Q48MHT CET 2019 · 2 MAY · SHIFT 2Easy

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the

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Answer: (a)

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Q49MHT CET 2019 · 3 MAY · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In hydrogen emission spectrum, for any series, the principal quantum number is nn. Corresponding maximum wavelength λ\lambda is ( R=R = Rydberg's constant)

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Answer: (b)

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Q50MHT CET 2019 · 2 MAY · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In Balmer series, wavelength of first line is ' λ1\lambda_1 ' and in Brackett series wavelength of first line is ' λ2\lambda_2 ' then λ1λ2\frac{\lambda_1}{\lambda_2} is

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Answer: (a)

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Q51MHT CET 2019 · 2 MAY · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The wavelength of the first line in Balmer series in the hydrogen spectrum is ' λ\lambda '. What is the wavelength of the second line in the same series?

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Answer: (a)

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Q52JEE Main 2019 · 9 APR · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be:

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Answer: (b)

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Q53JEE Main 2018Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

If the series limit frequency of the Lyman series is νL\nu_L, then the series limit frequency of the Pfund series is:

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Answer: (a)

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Q54NEET 2017Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is

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Answer: (b)

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Q55NEET 2016 · PHASE 1Easy

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

Given the value of Rydberg constant is 107 m−1{}^{-1}, the wave number of the last line of the Balmer series in hydrogen spectrum will be

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Answer: (a)

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Q56NEET 2015 · AIPMTMedium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is

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Answer: (b)

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Q57NEET 2013Medium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

Ratio of longest wave lengths corresponding to Lyman and Balmer series in hydrogen spectrum is

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Answer: (c)

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Q58NEET 2011 · AIPMT · PRELIMSMedium

Hydrogen Spectrum & Spectral Series · Series limit, first line & wavelength ratios

The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is

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Answer: (d)

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Q59NEET 2000 · AIPMTEasy

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

When an electron does transition from n = 4 to n = 2, then emitted line spectrum will be

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Answer: (b)

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Q60NEET 1993 · AIPMTEasy

Hydrogen Spectrum & Spectral Series · Spectral series & their regions

Which source is associated with a line emission spectrum?

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Answer: (b)

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