Moving Charges and Magnetism PYQs · MHT CET · JEE Main · NEET
Ampere's Law, Cylinders, Solenoid & Toroid
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61
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Q1MHT CET 2026 · 13 MAY · SHIFT 1Easy
Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law
Six very long insulated copper wires are bound together to form a cable. The currents carried by the wires are i1=10A, i2=−13A, i3=10A, i4=7A, i5=−12A and i6=18 A. The magnetic induction at a perpendicular distance of 10 cm from the cable is (μ0=4π×10−7 SI units)
Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law
Two wires with current 3A and 1.5A are enclosed in a circular loop P. Third parallel wire with current 1A is situated outside the loop as shown. All the wires are perpendicular to the plane of the circular loop. The value of ∮B⋅dl around the loop is (μ0= permeability of free space)
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
The figure given below shows a long straight solid wire of circular cross-section of radius ' a ' carrying steady current I. The current I is uniformly distributed across its cross-section. The plot which correctly represents the variation of magnetic field (B) with distance (r) from the axis of the conductor in the region is:
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A long cylindrical conductor with large cross section carries an electric current distributed uniformly over its cross-section. Magnetic field due to this current is:
A. maximum at either ends of the conductor and minimum at the midpoint
B. maximum at the axis of the conductor
C. minimum at the surface of the conductor
D. minimum at the axis of the conductor
E. same at all points in the cross-section of the conductor
Choose the correct answer from the options given below:
Choose the WRONG Statement from the following statements.
(A) A toroid is a solenoid bent in the form of a closed ring.
(B) The magnetic field lines of solenoid are straight lines parallel to the axis inside the solenoid. (C) The magnetic field lines of toroid are circular having common centre.
(D) Inside a solenoid, magnetic field may be made strong by passing small current and using laminated coil of soft iron.
A solenoid of 1000 turns is wound uniformly on a glass tube 4 m long and 0.3 m in diameter. The magnetic intensity at the centre of the solenoid when a current of 4 A flows through it is
A long solenoid carrying a current produces a magnetic field 'B' along its axis. If the current is tripled and the number of turns per cm is halved then new value of magnetic field will be
The magnetic field intensity (H) at the centre of a long solenoid having 'n' turns per unit length and carrying a current I, when no material is kept in it is (μ0 = permeability of free space)
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A long straight wire of a circular cross-section with radius ' a ' carries a steady current I. The current I is uniformly distributed across this cross-section. The plot of magnitude of magnetic field B with distance r from the centre of the wire is given by
The magnetic field intensity H at the centre of a long solenoid having n turns per unit length and carrying a current I, when no material is kept in it is ( μ0= permeability of free space)
The magnetic field inside a 200 turns solenoid of radius 10 cm is 2.9×10−4 Tesla. If the solenoid carries a current of 0.29 A, then the length of the solenoid is _______ πcm.
Numerical answer type. Work it out, then open the answer.
Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law
N equally spaced charges each of value q, are placed on a circle of radius R. The circle rotates about its axis with an angular velocity ω as shown in the figure. A bigger Amperian loop B encloses the whole circle where as a smaller Amperian loop A encloses a small segment. The difference between enclosed currents, IA−IB, for the given Amperian loops is
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A long straight wire of radius ' r ' carries a steady current ' I '. The current is uniformly distributed over its cross-section. The ratio (B1B) of the magnetic field ' B ' and ' B1 ' at radial distances ' 2r ' and ' 3r ' respectively, from the axis of the wire is
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
Consider a long straight wire of a circular cross-section (radius a) carrying a steady current I. The current is uniformly distributed across this cross-section. The distances from the centre of the wire’s cross-section at which the magnetic field [inside the wire, outside the wire] is half of the maximum possible magnetic field, any where due to the wire, will be:
A tightly wound long solenoid carries a current of 1.5 A. An electron is executing uniform circular motion inside the solenoid with a time period of 75 ns. The number of turns per metre in the solenoid is _________.
[Take mass of electronme=9×10−31 kgA2N,1 ns=10−9 s], charge of electron ∣qe∣=1.6×10−19 C,μ0=4π×10−7
Numerical answer type. Work it out, then open the answer.
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A long straight wire of radius a carries a steady current I. The current is uniformly distributed across its cross section. The ratio of the magnetic field at 2a and 2a from axis of the wire is:
A long solenoid carrying a current produces magnetic field B along its axis. If the number of turns per cm are tripled and the current is made (41)th then the new value of magnetic field will be
The magnetic field intensity inside current carrying solenoid is H=2.4×103 A/m. If length and number of turns of a solenoid is 15 cm and 60 turns respectively. The current flowing in the solenoid is
A solenoid of length 0.5 m has a radius of 1 cm and is made up of 'm' number of turns. It carries a current of 5 A. If the magnitude of the magnetic field inside the solenoid is 6.28×10−3 T then the value of m is __________.
Numerical answer type. Work it out, then open the answer.
A current of 5 A flows through a toroid having a core of mean radius 20 cm. If 4000 turns of the conducting wire are wound on the core, then the magnetic field inside the core of the toroid is [permeability of free space =4π×10−7 SI units]
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A long straight wire of circular cross-section (radius a) is carrying steady current I. The current I is uniformly distributed across this cross-section. The magnetic field is
A long solenoid is formed by winding 70 turns cm−1. If 2.0 A current flows, then the magnetic field produced inside the solenoid is ____________ (μ0=4π×10−7 TmA −1)
A rod with circular cross-section area 2 cm2 and length 40 cm is wound uniformly with 400 turns of an insulated wire. If a current of 0.4 A flows in the wire windings, the total magnetic flux produced inside windings is 4π×10−6 Wb. The relative permeability of the rod is
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
From Ampere's circuital law for a long straight wire of circular cross-section carrying a steady current, the variation of magnetic field in the inside and outside region of the wire is
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A long straight wire with a circular cross-section having radius R, is carrying a steady current I. The current I is uniformly distributed across this cross-section. Then the variation of magnetic field due to current I with distance r (r < R) from its centre will be:
A long solenoid of radius 1 mm has 100 turns per mm. If 1 A current flows in the solenoid, the magnetic field strength at the centre of the solenoid is
A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of magnetic field will be equal to
Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law
Two wires carrying currents 5 A and 2 A are enclosed in a circular loop as shown in the figure. Another wire carrying a current of 3 A is situated outside the loop. The value of ∮Bdl around the loop is ( μ0= permeability of free space, dl is the length of the element on the Amperion loop)
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A thick current carrying cable of radius 'R' carries current 'I' uniformly distributed across its cross section. The variation of magnetic field B(r) due to the cable with the distance 'r' from the axis of the cable is represented by:
A long solenoid carrying current I1 produces magnetic field B1 along its axis. If the current is reduced to 20% and number of turns per cm are increased five times then new magnetic field B2 is equal to
A long solenoid carrying a current produces a magnetic field B along its axis. If the number of turns per cm is doubled and the current is made (31)rd then the new value of the magnetic field will be
The magnetic field intensity 'H' at the centre of a long solenoid having 'n' turns per unit length and carrying a current 'I', when no material is kept in it, is
A solenoid of 1000 turns per metre has a core with relative permeability 500. Insulated windings of the solenoid carry an electric current of 5A. The magnetic flux density produced by the solenoid is: (permeability of free space = 4π× 10−7 H/m)
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
Figures A and B show two long straight wires of circular cross-section (a and b with a < b), carrying current I which is uniformly distributed across the cross-section. The magnitude of magnetic field B varies with radius r and can be represented as:
A solenoid 2 m long and 4 cm in diameter has 4 layers of windings of 1000 turns each and carries a current of 5 A. What is the magnetic field at its centre along the axis? [μ0=4π×10−7 Wb/Am]
A long solenoid with 1000 turns/m has a core material with relative permeability 500 and volume 103 cm3. If the core material is replaced by another material having relative permeability of 750 with same volume maintaining same current of 0.75 A in the solenoid, the fractional change in the magnetic moment of the core would be approximately (499x). Find the value of x.
Numerical answer type. Work it out, then open the answer.
The magnetic field inside a current carrying toroidal solenoid is 0.2 mT. What is the magnetic field inside the toroid if the current through it is tripled and radius is made 31rd?
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A coaxial cable consists of an inner wire of radius 'a' surrounded by an outer shell of inner and outer radii 'b' and 'c' respectively. The inner wire carries an electric current i0, which is distributed uniformly across cross-sectional area. The outer shell carries an equal current in opposite direction and distributed uniformly. What will be the ratio of the magnetic field at a distance x from the axis when (i) x < a and (ii) a < x < b?
Four identical long solenoids A, B, C and D are connected to each other as shown in the figure. If the magnetic field at the center of A is 3T, the field at the center of C would be: (Assume that the magnetic field is confined with in the volume of respective solenoid).
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A long, straight wire of radius a carries a current distributed uniformly over its cross-section. The ratio of the magnetic fields due to the wire at distance 3a and 2a, respectively from the axis of the wire is:
An iron rod of volume 10–3 m3 and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be:
Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law
Six very long insulated copper wires are bound together to form a cable. The currents carried by the wires are I1=+10 A,I2=−13 A,I3=+10 A,I4=+7 A,I5=−12 A and I6=+18 A. The magnetic induction at a perpendicular distance of 10 cm from the cable is
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A cylindrical conductor of radius R is carrying a constant current. The plot of the magnitude of the magnetic field B with the distance d from the centre of the conductor, is correctly represented by the figure:
Two toroids 1 and 2 have total no. of turns 200 and 100 respectively with average radii 40 cm and 20 cm respectively. If they carry same current i, the ratio of the magnetic fields along the two loops is,
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A long straight wire of radius a carries a steady current I. The current is uniformly distributed over its cross-section. The ratio of the magnetic fields B and B', at radial distance 2a and 2a respectively, from the axis of the wire is
A 25 cm long solenoid has radius 2 cm and 500 total number of turns. It carries a current of 15 A. If it is equivalent to a magnet of the same size and magnetization M (magnetic moment/volume), then ∣M∣ is:
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A current I flows in an infinitely long wire with cross section in the form of a semi-circular ring of radius R. The magnitude of the magnetic induction along its axis is:
Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders
A long straight wire of radius a carries a steady current i. The current is uniformly distributed across its cross section. The ratio of the magnetic field at a/2 and 2a is
A long solenoid has 200 turns per cm and carries a current i. The magnetic field at its center is 6.28×10−2Weber/m2. Another long solenoid has 100 turns per cm and it carries a current 3i. The value of the magnetic field at its center is
A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is