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Moving Charges and Magnetism PYQs · MHT CET · JEE Main · NEET

Ampere's Law, Cylinders, Solenoid & Toroid

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61
MHT CET
23
JEE Main
28
NEET
10
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1999–2026
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Q1MHT CET 2026 · 13 MAY · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law

Six very long insulated copper wires are bound together to form a cable. The currents carried by the wires are i1=10i_1 = 10A, i2=−13i_2 = -13A, i3=10i_3 = 10A, i4=7i_4 = 7A, i5=−12i_5 = -12A and i6=18i_6 = 18 A. The magnetic induction at a perpendicular distance of 1010 cm from the cable is (μ0=4π×10−7(\mu_0 = 4\pi \times 10^{-7} SI units))

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Answer: (a)

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Q2MHT CET 2026 · 18 APR · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law

Two wires with current 3A and 1.5A are enclosed in a circular loop P. Third parallel wire with current 1A is situated outside the loop as shown. All the wires are perpendicular to the plane of the circular loop. The value of ∮B⃗⋅dl⃗\oint \vec{B} \cdot \vec{dl} around the loop is (μ0=\mu_0 = permeability of free space)

Figure

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Answer: (c)

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Q3NEET 2026Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

The figure given below shows a long straight solid wire of circular cross-section of radius ' aa ' carrying steady current II. The current II is uniformly distributed across its cross-section. The plot which correctly represents the variation of magnetic field (B)(B) with distance (r)(r) from the axis of the conductor in the region is:

Figure

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Answer: (a)

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Q4JEE Main 2026 · 28 JAN · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A long cylindrical conductor with large cross section carries an electric current distributed uniformly over its cross-section. Magnetic field due to this current is:

A. maximum at either ends of the conductor and minimum at the midpoint

B. maximum at the axis of the conductor

C. minimum at the surface of the conductor

D. minimum at the axis of the conductor

E. same at all points in the cross-section of the conductor

Choose the correct answer from the options given below:

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Answer: (d)

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Q5MHT CET 2026 · 15 MAY · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

The magnitude of the magnetic field inside a long solenoid is increased by

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Answer: (d)

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Q6MHT CET 2026 · 13 MAY · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

The magnitude of the magnetic field inside a long solenoid is increased by

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Answer: (d)

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Q7MHT CET 2026 · 12 MAY · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

Choose the WRONG Statement from the following statements.

(A) A toroid is a solenoid bent in the form of a closed ring.

(B) The magnetic field lines of solenoid are straight lines parallel to the axis inside the solenoid. (C) The magnetic field lines of toroid are circular having common centre.

(D) Inside a solenoid, magnetic field may be made strong by passing small current and using laminated coil of soft iron.

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Answer: (a)

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Q8MHT CET 2026 · 20 APR · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A solenoid of 1000 turns is wound uniformly on a glass tube 4 m long and 0.30.3 m in diameter. The magnetic intensity at the centre of the solenoid when a current of 4 A flows through it is

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Answer: (d)

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Q9MHT CET 2026 · 20 APR · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid carrying a current produces a magnetic field 'BB' along its axis. If the current is tripled and the number of turns per cm is halved then new value of magnetic field will be

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Answer: (c)

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Q10MHT CET 2026 · 19 APR · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

The magnetic induction produced inside an ideal solenoid, depends on which of the following quantities?

(a) number of turns per unit length.

(b) radius of the wire.

(c) current flowing throught it.

(d) permeability of the medium.

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Answer: (d)

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Q11MHT CET 2026 · 16 APR · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

The magnetic field intensity (H) at the centre of a long solenoid having 'n' turns per unit length and carrying a current I, when no material is kept in it is (μ0\mu_0 = permeability of free space)

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Answer: (b)

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Q12JEE Main 2025 · 24 JAN · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A long straight wire of a circular cross-section with radius ' a ' carries a steady current I. The current I is uniformly distributed across this cross-section. The plot of magnitude of magnetic field B with distance rr from the centre of the wire is given by

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Answer: (b)

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Q13MHT CET 2025 · 25 APR · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

The magnetic field intensity H at the centre of a long solenoid having nn turns per unit length and carrying a current I, when no material is kept in it is ( μ0=\mu_0 = permeability of free space)

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Answer: (c)

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Q14JEE Main 2025 · 29 JAN · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

The magnetic field inside a 200 turns solenoid of radius 10 cm is 2.9×10−4 Tesla2.9 \times 10^{-4}\text{ Tesla}. If the solenoid carries a current of 0.29 A, then the length of the solenoid is _______ πcm\pi\text{cm}.

Numerical answer type. Work it out, then open the answer.

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Answer: 8

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Q15JEE Main 2025 · 24 JAN · SHIFT 2Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law

Figure

N equally spaced charges each of value q, are placed on a circle of radius R. The circle rotates about its axis with an angular velocity ω\omega as shown in the figure. A bigger Amperian loop B encloses the whole circle where as a smaller Amperian loop A encloses a small segment. The difference between enclosed currents, IA−IBI_A - I_B, for the given Amperian loops is

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Answer: (b)

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Q16MHT CET 2025 · 25 APR · SHIFT 1Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A long straight wire of radius ' rr ' carries a steady current ' II '. The current is uniformly distributed over its cross-section. The ratio (BB1)\left(\frac{B}{B_1}\right) of the magnetic field ' B ' and ' B1\mathrm{B}_1 ' at radial distances ' r2\frac{r}{2} ' and ' 3r3r ' respectively, from the axis of the wire is

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Answer: (b)

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Q17JEE Main 2025 · 29 JAN · SHIFT 1Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

Consider a long straight wire of a circular cross-section (radius a) carrying a steady current I. The current is uniformly distributed across this cross-section. The distances from the centre of the wire’s cross-section at which the magnetic field [inside the wire, outside the wire] is half of the maximum possible magnetic field, any where due to the wire, will be:

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Answer: (c)

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Q18JEE Main 2025 · 24 JAN · SHIFT 2Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A tightly wound long solenoid carries a current of 1.5 A. An electron is executing uniform circular motion inside the solenoid with a time period of 75 ns. The number of turns per metre in the solenoid is _________.

[Take mass of electronme=9×10−31 kgNA2,1 ns=10−9 s]\mathrm{m_e} = 9 \times 10^{-31}\text{ kg} \quad \frac{\mathrm{N}}{\mathrm{A}^2}, 1\text{ ns} = 10^{-9}\text{ s}], charge of electron ∣qe∣=1.6×10−19 C,μ0=4π×10−7|\mathrm{q_e}| = 1.6 \times 10^{-19}\text{ C}, \mu_0 = 4\pi \times 10^{-7}

Numerical answer type. Work it out, then open the answer.

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Answer: 250

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Q19JEE Main 2024 · 8 APR · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A long straight wire of radius aa carries a steady current I. The current is uniformly distributed across its cross section. The ratio of the magnetic field at a2\frac{a}{2} and 2a2a from axis of the wire is:

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Answer: (c)

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Q20JEE Main 2024 · 5 APR · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

In a co-axial straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero:

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Answer: (b)

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Q21MHT CET 2024 · 9 MAY · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid carrying a current produces magnetic field B along its axis. If the number of turns per cm are tripled and the current is made (14)\left(\frac{1}{4}\right)th then the new value of magnetic field will be

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Answer: (c)

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Q22MHT CET 2024 · 9 MAY · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

The magnetic induction due to an ideal solenoid is independent of

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Answer: (c)

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Q23MHT CET 2024 · 9 MAY · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

The magnetic field intensity inside current carrying solenoid is H=2.4×103 A/m\mathrm{H} = 2.4 \times 10^{3}\text{ A/m}. If length and number of turns of a solenoid is 15 cm and 60 turns respectively. The current flowing in the solenoid is

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Answer: (b)

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Q24JEE Main 2024 · 5 APR · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A solenoid of length 0.5 m0.5\text{ m} has a radius of 1 cm1\text{ cm} and is made up of 'm\mathrm{m}' number of turns. It carries a current of 5 A5\text{ A}. If the magnitude of the magnetic field inside the solenoid is 6.28×10−3 T6.28 \times 10^{-3}\text{ T} then the value of m\mathrm{m} is __________.

Numerical answer type. Work it out, then open the answer.

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Answer: 500

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Q25MHT CET 2024 · 16 MAY · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Toroid

The magnetic induction along the axis of a toroidal solenoid is independent of

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Answer: (c)

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Q26MHT CET 2024 · 3 MAY · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Toroid

A current of 5 A flows through a toroid having a core of mean radius 20 cm. If 4000 turns of the conducting wire are wound on the core, then the magnetic field inside the core of the toroid is [permeability of free space =4π×10−7= 4\pi \times 10^{-7} SI units]

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Answer: (d)

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Q27JEE Main 2023 · 6 APR · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A long straight wire of circular cross-section (radius a) is carrying steady current I. The current I is uniformly distributed across this cross-section. The magnetic field is

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Answer: (c)

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Q28JEE Main 2023 · 24 JAN · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid is formed by winding 70 turns cm−1{}^{-1}. If 2.0 A current flows, then the magnetic field produced inside the solenoid is ____________ (μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7} TmA −1{}^{-1})

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Answer: (c)

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Q29JEE Main 2023 · 31 JAN · SHIFT 1Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A rod with circular cross-section area 2 cm22\text{ cm}^2 and length 40 cm40\text{ cm} is wound uniformly with 400 turns of an insulated wire. If a current of 0.4 A0.4\text{ A} flows in the wire windings, the total magnetic flux produced inside windings is 4π×10−6 Wb4\pi \times 10^{-6}\text{ Wb}. The relative permeability of the rod is

(Given: Permeability of vacuum μ0=4π×10−7 NA−2\mu_0 = 4\pi \times 10^{-7}\text{ NA}^{-2})

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Answer: (a)

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Q30NEET 2022 · PHASE 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

From Ampere's circuital law for a long straight wire of circular cross-section carrying a steady current, the variation of magnetic field in the inside and outside region of the wire is

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Answer: (c)

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Q31JEE Main 2022 · 28 JUN · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

An infinitely long hollow conducting cylinder with radius R carries a uniform current along its surface.

Choose the correct representation of magnetic field (B) as a function of radial distance (r) from the axis of cylinder.

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Answer: (d)

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Q32JEE Main 2022 · 25 JUN · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A long straight wire with a circular cross-section having radius R, is carrying a steady current I. The current I is uniformly distributed across this cross-section. Then the variation of magnetic field due to current I with distance r (r < R) from its centre will be:

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Answer: (b)

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Q33NEET 2022 · PHASE 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid of radius 1 mm has 100 turns per mm. If 1 A current flows in the solenoid, the magnetic field strength at the centre of the solenoid is

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Answer: (b)

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Q34JEE Main 2022 · 25 JUN · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of magnetic field will be equal to

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Answer: (a)

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Q35MHT CET 2021 · 20 SEP · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law

Two wires carrying currents 5 A5\text{ A} and 2 A2\text{ A} are enclosed in a circular loop as shown in the figure. Another wire carrying a current of 3 A3\text{ A} is situated outside the loop. The value of ∮B⃗ dl⃗\oint \vec{B}\,\vec{dl} around the loop is ( μ0=\mu_0 = permeability of free space, dl⃗\vec{dl} is the length of the element on the Amperion loop)

Figure

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Answer: (c)

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Q36NEET 2021Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A thick current carrying cable of radius 'R' carries current 'I' uniformly distributed across its cross section. The variation of magnetic field B(r) due to the cable with the distance 'r' from the axis of the cable is represented by:

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Answer: (d)

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Q37MHT CET 2021 · 23 SEP · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid carrying current I1\mathrm{I}_1 produces magnetic field B1\mathrm{B}_1 along its axis. If the current is reduced to 20%20\% and number of turns per cm\text{cm} are increased five times then new magnetic field B2{}_2 is equal to

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Answer: (a)

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Q38MHT CET 2021 · 21 SEP · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid carrying a current produces a magnetic field B along its axis. If the number of turns per cm\text{cm} is doubled and the current is made (13)\left(\frac{1}{3}\right)rd then the new value of the magnetic field will be

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Answer: (d)

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Q39MHT CET 2021 · 20 SEP · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

The magnetic field intensity 'H' at the centre of a long solenoid having 'n' turns per unit length and carrying a current 'I', when no material is kept in it, is

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Answer: (c)

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Q40JEE Main 2021 · 17 MAR · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A solenoid of 1000 turns per metre has a core with relative permeability 500. Insulated windings of the solenoid carry an electric current of 5A. The magnetic flux density produced by the solenoid is: (permeability of free space = 4π×\pi \times 10−-7 H/m)

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Answer: (a)

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Q41JEE Main 2021 · 27 JUL · SHIFT 2Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

Figures A and B show two long straight wires of circular cross-section (a and b with a < b), carrying current I which is uniformly distributed across the cross-section. The magnitude of magnetic field B varies with radius r and can be represented as:

Figure

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Answer: (c)

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Q42MHT CET 2021 · 24 SEP · SHIFT 2Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A solenoid 2 m long and 4 cm in diameter has 4 layers of windings of 1000 turns each and carries a current of 5 A. What is the magnetic field at its centre along the axis? [μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7} Wb/Am]

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Answer: (c)

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Q43JEE Main 2021 · 31 AUG · SHIFT 2Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid with 1000 turns/m has a core material with relative permeability 500 and volume 103 cm3. If the core material is replaced by another material having relative permeability of 750 with same volume maintaining same current of 0.75 A in the solenoid, the fractional change in the magnetic moment of the core would be approximately (x499)\left(\frac{x}{499}\right). Find the value of x.

Numerical answer type. Work it out, then open the answer.

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Answer: 250

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Q44MHT CET 2021 · 22 SEP · SHIFT 2Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Toroid

The magnetic field inside a current carrying toroidal solenoid is 0.2 mT0.2\text{ mT}. What is the magnetic field inside the toroid if the current through it is tripled and radius is made 13\frac{1}{3}rd?

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Answer: (b)

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Q45JEE Main 2021 · 27 AUG · SHIFT 2Difficult

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A coaxial cable consists of an inner wire of radius 'a' surrounded by an outer shell of inner and outer radii 'b' and 'c' respectively. The inner wire carries an electric current i0, which is distributed uniformly across cross-sectional area. The outer shell carries an equal current in opposite direction and distributed uniformly. What will be the ratio of the magnetic field at a distance x from the axis when (i) x < a and (ii) a < x < b?

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Answer: (a)

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Q46JEE Main 2021 · 18 MAR · SHIFT 1Difficult

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

Four identical long solenoids A, B, C and D are connected to each other as shown in the figure. If the magnetic field at the center of A is 3T, the field at the center of C would be: (Assume that the magnetic field is confined with in the volume of respective solenoid).

Figure

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Answer: (d)

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Q47JEE Main 2020 · 9 JAN · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A long, straight wire of radius a carries a current distributed uniformly over its cross-section. The ratio of the magnetic fields due to the wire at distance a3\frac{a}{3} and 2aa, respectively from the axis of the wire is:

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Answer: (d)

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Q48NEET 2020 · PHASE 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is:

(μ0=4π×10−7 TmA−1)\left(\mu_0 = 4\pi \times 10^{-7}\, TmA^{-1}\right)

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Answer: (d)

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Q49JEE Main 2020 · 5 SEP · SHIFT 2Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

An iron rod of volume 10–3 m3 and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be:

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Answer: (a)

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Q50MHT CET 2019 · 3 MAY · SHIFT 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Ampere's circuital law

Six very long insulated copper wires are bound together to form a cable. The currents carried by the wires are I1=+10 A,I2=−13 A,I3=+10 A,I4=+7 A,I5=−12 AI_1 = +10\text{ A}, I_2 = -13\text{ A}, I_3 = +10\text{ A}, I_4 = +7\text{ A}, I_5 = -12\text{ A} and I6=+18 AI_6 = +18\text{ A}. The magnetic induction at a perpendicular distance of 10 cm from the cable is

(μ0=4π×10−7 Wb/A-m)\left(\mu_0 = 4\pi \times 10^{-7}\text{ Wb/A-m}\right)

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Answer: (a)

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Q51NEET 2019Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A cylindrical conductor of radius R is carrying a constant current. The plot of the magnitude of the magnetic field B with the distance d from the centre of the conductor, is correctly represented by the figure:

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Answer: (c)

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Q52NEET 2019Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Toroid

Two toroids 1 and 2 have total no. of turns 200 and 100 respectively with average radii 40 cm and 20 cm respectively. If they carry same current ii, the ratio of the magnetic fields along the two loops is,

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Answer: (b)

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Q53NEET 2016 · PHASE 1Easy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A long straight wire of radius aa carries a steady current II. The current is uniformly distributed over its cross-section. The ratio of the magnetic fields B and B', at radial distance a2\frac{a}{2} and 2aa respectively, from the axis of the wire is

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Answer: (a)

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Q54JEE Main 2015 · 10 APR · SHIFT 1Medium

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A 25 cm long solenoid has radius 2 cm and 500 total number of turns. It carries a current of 15 A. If it is equivalent to a magnet of the same size and magnetization M⃗\vec{M} (magnetic moment/volume), then ∣M∣→\overrightarrow{|M|} is:

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Answer: (b)

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Q55JEE Main 2011 · AIEEEDifficult

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A current II flows in an infinitely long wire with cross section in the form of a semi-circular ring of radius R.R. The magnitude of the magnetic induction along its axis is:

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Answer: (d)

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Q56JEE Main 2007 · AIEEEEasy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A long straight wire of radius aa carries a steady current i.i. The current is uniformly distributed across its cross section. The ratio of the magnetic field at a/2a/2 and 2a2a is

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Answer: (d)

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Q57JEE Main 2007 · AIEEEEasy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A current II flows along the length of an infinitely long, straight, thin walled pipe. Then

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Answer: (d)

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Q58JEE Main 2006 · AIEEEEasy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid has 200200 turns per cmcm and carries a current i.i. The magnetic field at its center is 6.28×10−2 Weber/m2.6.28 \times 10^{-2}\ Weber/m^2. Another long solenoid has 100100 turns per cmcm and it carries a current i3\frac{i}{3}. The value of the magnetic field at its center is

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Answer: (a)

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Q59JEE Main 2004 · AIEEEEasy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

A current ii ampere flows along an infinitely long straight thin walled tube, then the magnetic induction at any point inside the tube is

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Answer: (b)

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Q60NEET 2003 · AIPMTEasy

Ampere's Law, Cylinders, Solenoid & Toroid · Solenoid

A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is

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Answer: (b)

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Q61NEET 1999 · AIPMTEasy

Ampere's Law, Cylinders, Solenoid & Toroid · Field of solid & hollow cylinders

If a long hollow copper pipe carries a current, then magnetic field is produced

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Answer: (b)

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