Q1 JEE Main 2026 · 2 APR · SHIFT 2 Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
The binding energy per nucleon of 83 209 B i {}_{83}^{209}Bi 83 209 B i is _______ MeV.
[Take m ( 83 209 B i ) = 208.980388 m({}_{83}^{209}Bi) = 208.980388 m ( 83 209 B i ) = 208.980388 u, m p = 1.007825 m_p = 1.007825 m p = 1.007825 u, m n = 1.008665 m_n = 1.008665 m n = 1.008665 u, 1 1 1 u = 931 = 931 = 931 MeV/ c 2 /c^{2} / c 2 ]
(a) 7.48 (b) 7.84 (c) 8.79 (d) 6.94 Show answer and solution
Answer: (b)
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Q2 JEE Main 2026 · 24 JAN · SHIFT 1 Easy ☆
Mass Defect & Binding Energy · Binding energy curve & stability
Given below are two statements:
Statement I: For all elements, greater the mass of the nucleus, greater is the binding energy per nucleon.
Statement II: For all elements, nuclei with less binding energy per nucleon transforms to nuclei with greater binding energy per nucleon.
In the light of the above statements, choose the correct answer from the options given below
(a) Statement I is false but Statement II is true (b) Both Statement I and Statement II are true (c) Both Statement I and Statement II are false (d) Statement I is true but Statement II is false Show answer and solution
Answer: (a)
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Q3 JEE Main 2026 · 5 APR · SHIFT 2 Medium ☆
Mass Defect & Binding Energy · Mass defect
Assuming the experimental mass of 6 12 C {}_{6}^{12}C 6 12 C as 12 u 12u 12 u , the mass defect of 6 12 C {}_{6}^{12}C 6 12 C atom is _ _ _ _ _ MeV/c 2 \_\_\_\_\_\ \text{MeV/c}^{2} _____ MeV/c 2 . (Mass of proton = 1.00727 u = 1.00727\text{u} = 1.00727 u . mass of neutron = 1.00866 u , 1 u = 931.5 MeV/c 2 = 1.00866\text{u}, 1\text{u} = 931.5\text{MeV/c}^{2} = 1.00866 u , 1 u = 931.5 MeV/c 2 and c is the speed of the light in vacuum).
(a) 127.5 (b) 89.03 (c) 272.0 (d) 92.0 Show answer and solution
Answer: (b)
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Q4 JEE Main 2026 · 24 JAN · SHIFT 2 Medium ☆
Mass Defect & Binding Energy · Binding energy curve & stability
The binding energy for the following nuclear reactions are expressed in MeV.
2 He 3 + 0 n 1 → 2 He 4 + 20 MeV {}_{2}\text{He}^{3} + {}_{0}\text{n}^{1} \rightarrow {}_{2}\text{He}^{4} + 20\text{MeV} 2 He 3 + 0 n 1 → 2 He 4 + 20 MeV
2 He 4 + 0 n 1 → 2 He 5 − 0.9 MeV {}_{2}\text{He}^{4} + {}_{0}\text{n}^{1} \rightarrow {}_{2}\text{He}^{5} - 0.9\text{MeV} 2 He 4 + 0 n 1 → 2 He 5 − 0.9 MeV
If X 3 , X 4 , X 5 \mathrm{X_3, X_4, X_5} X 3 , X 4 , X 5 denote the stability of 2 He 3 , 2 He 4 {}_{2}\text{He}^{3}, {}_{2}\text{He}^{4} 2 He 3 , 2 He 4 and 2 He 5 {}_{2}\text{He}^{5} 2 He 5 , respectively, then the correct order is:
(a) X 4 > X 5 > X 3 X_4 > X_5 > X_3 X 4 > X 5 > X 3 (b) X 4 < X 5 < X 3 X_4 < X_5 < X_3 X 4 < X 5 < X 3 (c) X 4 > X 5 < X 3 X_4 > X_5 < X_3 X 4 > X 5 < X 3 (d) X 4 = X 5 = X 3 X_4 = X_5 = X_3 X 4 = X 5 = X 3 Show answer and solution
Answer: (a)
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Q5 JEE Main 2025 · 23 JAN · SHIFT 2 Easy ☆
Mass Defect & Binding Energy · Binding energy curve & stability
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The binding energy per nucleon is found to be practically independent of the atomic number A, for nuclei with mass numbers between 30 and 170.
Reason (R): Nuclear force is long range. In the light of the above statements, choose the correct answer from the options given below:
(a) (A) is true but (R) is false (b) Both (A) and (R) are true and (R) is the correct explanation of (A) (c) (A) is false but (R) is true (d) Both (A) and (R) are true but (R) is NOT the correct explanation of (A) Show answer and solution
Answer: (a)
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Q6 JEE Main 2024 · 9 APR · SHIFT 1 Easy ☆
Mass Defect & Binding Energy · Mass-energy equivalence & atomic mass unit
The energy equivalent of 1 g 1\text{ g} 1 g of substance is:
(a) 5.6 × 1 0 26 MeV 5.6 \times 10^{26}\text{ MeV} 5.6 × 1 0 26 MeV (b) 5.6 × 1 0 12 MeV 5.6 \times 10^{12}\text{ MeV} 5.6 × 1 0 12 MeV (c) 5.6 eV 5.6\text{ eV} 5.6 eV (d) 11.2 × 1 0 24 MeV 11.2 \times 10^{24}\text{ MeV} 11.2 × 1 0 24 MeV Show answer and solution
Answer: (a)
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Q7 JEE Main 2024 · 8 APR · SHIFT 1 Easy ☆
Mass Defect & Binding Energy · Mass-energy equivalence & atomic mass unit
Binding energy of a certain nucleus is 18 × 1 0 8 J 18 \times 10^{8}\text{ J} 18 × 1 0 8 J . How much is the difference between total mass of all the nucleons and nuclear mass of the given nucleus:
(a) 20 μ \mu μ g (b) 2 μ \mu μ g (c) 10 μ \mu μ g (d) 0.2 μ \mu μ g Show answer and solution
Answer: (a)
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Q8 JEE Main 2024 · 31 JAN · SHIFT 1 Easy ☆
Mass Defect & Binding Energy · Mass-energy equivalence & atomic mass unit
The mass defect in a particular reaction is 0.4 g 0.4\text{ g} 0.4 g . The amount of energy liberated is n × 1 0 7 kWh n \times 10^{7}\text{ kWh} n × 1 0 7 kWh , where n = n = n = __________. (speed of light = 3 × 1 0 8 m/s ) = 3 \times 10^{8}\text{ m/s}) = 3 × 1 0 8 m/s )
Numerical answer type. Work it out, then open the answer.
Show answer and solution
Answer: 1
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Q9 MHT CET 2024 · 16 MAY · SHIFT 1 Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
If M O \mathrm{M_O} M O is the mass of an oxygen isotope 8 O 17 {}_{8}\text{O}^{17} 8 O 17 and M p \mathrm{M_p} M p and M N \mathrm{M_N} M N are the mass of proton and mass of neutron respectively, then the nucleus binding energy of the isotope is
(a) M o C 2 \mathrm{M_o C^2} M o C 2 (b) ( M o − 8 M P ) C 2 (\mathrm{M_o} - 8\mathrm{M_P})\mathrm{C}^2 ( M o − 8 M P ) C 2 (c) ( M o − 17 M N ) C 2 (\mathrm{M_o} - 17\mathrm{M_N})\mathrm{C}^2 ( M o − 17 M N ) C 2 (d) ( M o − 8 M P − 9 M N ) C 2 (\mathrm{M_o} - 8\mathrm{M_P} - 9\mathrm{M_N})\mathrm{C}^2 ( M o − 8 M P − 9 M N ) C 2 Show answer and solution
Answer: (d)
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Q10 JEE Main 2024 · 8 APR · SHIFT 2 Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
If M 0 M_0 M 0 is the mass of isotope 5 12 B , M p {}_{5}^{12}B, M_p 5 12 B , M p and M n M_n M n are the masses of proton and neutron, then nuclear binding energy of isotope is:
(a) ( 5 M p + 7 M n − M 0 ) C 2 (5M_p + 7M_n - M_0)C^{2} ( 5 M p + 7 M n − M 0 ) C 2 (b) ( M 0 − 5 M p − 7 M n ) C 2 (M_0 - 5M_p - 7M_n)C^{2} ( M 0 − 5 M p − 7 M n ) C 2 (c) ( M 0 − 5 M p ) C 2 (M_0 - 5M_p)C^{2} ( M 0 − 5 M p ) C 2 (d) ( M 0 − 12 M n ) C 2 (M_0 - 12M_n)C^{2} ( M 0 − 12 M n ) C 2 Show answer and solution
Answer: (a)
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Q11 JEE Main 2024 · 27 JAN · SHIFT 2 Medium ☆
Mass Defect & Binding Energy · Binding energy from masses
The atomic mass of 6 C 12 {}_{6}\text{C}^{12} 6 C 12 is 12.000000 u 12.000000\text{ u} 12.000000 u and that of 6 C 13 {}_{6}\text{C}^{13} 6 C 13 is 13.003354 u 13.003354\text{ u} 13.003354 u . The required energy to remove a neutron from 6 C 13 {}_{6}\text{C}^{13} 6 C 13 , if mass of neutron is 1.008665 u 1.008665\text{ u} 1.008665 u , will be:
(a) 62.5 MeV (b) 6.25 MeV (c) 4.95 MeV (d) 49.5 MeV Show answer and solution
Answer: (c)
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Q12 JEE Main 2023 · 1 FEB · SHIFT 1 Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
The mass of proton, neutron and helium nucleus are respectively 1.0073 u , 1.0087 u 1.0073\,u, 1.0087\,u 1.0073 u , 1.0087 u and 4.0015 u 4.0015\,u 4.0015 u . The binding energy of helium nucleus is:
(a) 28.4 MeV 28.4\text{ MeV} 28.4 MeV (b) 56.8 MeV 56.8\text{ MeV} 56.8 MeV (c) 7.1 MeV 7.1\text{ MeV} 7.1 MeV (d) 14.2 MeV 14.2\text{ MeV} 14.2 MeV Show answer and solution
Answer: (a)
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Q13 JEE Main 2023 · 13 APR · SHIFT 2 Easy Old syllabus ☆
Mass Defect & Binding Energy · Binding energy curve & stability
Given below are two statements: one is labelled as Assertion A \mathbf{A} A and the other is labelled as Reason R \mathbf{R} R
Assertion A: The binding energy per nucleon is practically independent of the atomic number for nuclei of mass number in the range 30 to 170.
Reason R: Nuclear force is short ranged.
In the light of the above statements, choose the correct answer from the options given below
(a) A \mathrm{A} A is false but R \mathbf{R} R is true(b) A \mathrm{A} A is true but R \mathbf{R} R is false(c) Both A \mathbf{A} A and R \mathbf{R} R are true and R \mathbf{R} R is the correct explanation of A \mathbf{A} A (d) Both A \mathbf{A} A and R \mathbf{R} R are true but R \mathbf{R} R is NOT the correct explanation of A \mathbf{A} A Show answer and solution
Answer: (c)
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Q14 JEE Main 2023 · 1 FEB · SHIFT 2 Medium ☆
Mass Defect & Binding Energy · Binding energy from masses
Nucleus A having Z = 17 Z = 17 Z = 17 and equal number of protons and neutrons has 1.2 MeV 1.2\text{ MeV} 1.2 MeV binding energy per nucleon.
Another nucleus B \text{B} B of Z = 12 Z = 12 Z = 12 has total 26 nucleons and 1.8 MeV 1.8\text{ MeV} 1.8 MeV binding energy per nucleons. The difference of binding energy of B \text{B} B and A \text{A} A will be _____________ MeV \text{MeV} MeV .
Numerical answer type. Work it out, then open the answer.
Show answer and solution
Answer: 6
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Q15 JEE Main 2023 · 8 APR · SHIFT 1 Difficult ☆
Mass Defect & Binding Energy · Binding energy curve & stability
For a nucleus Z A X {}_{\text{Z}}^{\text{A}}\text{X} Z A X having mass number A \text{A} A and atomic number Z \text{Z} Z
A. The surface energy per nucleon ( b s ) = − a 1 A 2 / 3 (b_{\text{s}}) = -a_1 A^{2/3} ( b s ) = − a 1 A 2/3 .
B. The Coulomb contribution to the binding energy b c = − a 2 Z ( Z − 1 ) A 4 / 3 \text{b}_{\text{c}} = -a_2 \frac{Z(Z-1)}{A^{4/3}} b c = − a 2 A 4/3 Z ( Z − 1 )
C. The volume energy b v = a 3 A \text{b}_{\text{v}} = a_3 A b v = a 3 A
D. Decrease in the binding energy is proportional to surface area.
E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons. ( a 1 , a 2 a_1, a_2 a 1 , a 2 and a 3 a_3 a 3 are constants)
Choose the most appropriate answer from the options given below:
(a) C, D only (b) B, C, E only (c) B, C only (d) A, B, C, D only Show answer and solution
Answer: (a)
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Q16 JEE Main 2021 · 25 JUL · SHIFT 2 Medium ☆
Mass Defect & Binding Energy · Binding energy from masses
From the given data, the amount of energy required to break the nucleus of aluminium 13 27 {}_{13}^{27} 13 27 Al is __________ x × \times × 10− - − 3 J.
Mass of neutron = 1.00866 u
Mass of proton = 1.00726 u
Mass of Aluminium nucleus = 27.18846 u
(Assume 1 u corresponds to x J of energy)
(Round off to the nearest integer)
Numerical answer type. Work it out, then open the answer.
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Answer: 27
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Q17 NEET 2020 · PHASE 1 Easy ☆
Mass Defect & Binding Energy · Mass-energy equivalence & atomic mass unit
The energy equivalent of 0.5 g of a substance is:
(a) 4.5 × 1 0 13 J 4.5 \times 10^{13}\text{ J} 4.5 × 1 0 13 J (b) 1.5 × 1 0 13 J 1.5 \times 10^{13}\text{ J} 1.5 × 1 0 13 J (c) 0.5 × 1 0 13 J 0.5 \times 10^{13}\text{ J} 0.5 × 1 0 13 J (d) 4.5 × 1 0 16 J 4.5 \times 10^{16}\text{ J} 4.5 × 1 0 16 J Show answer and solution
Answer: (a)
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Q18 JEE Main 2020 · 4 SEP · SHIFT 2 Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
Find the Binding energy per nucleon for 50 120 S n {}_{50}^{120}Sn 50 120 S n . Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U and mass of tin nucleus mSn = 119.902199 U. (take 1U = 931 MeV)
(a) 9.0 MeV (b) 8.5 MeV (c) 8.0 MeV (d) 7.5 MeV Show answer and solution
Answer: (b)
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Q19 JEE Main 2017 · 9 APR · SHIFT 1 Easy ☆
Mass Defect & Binding Energy · Mass-energy equivalence & atomic mass unit
Imagine that a reactor converts all given mass into energy and that it operates at a power level of 109 watt. The mass of the fuel consumed per hour in the reactor will be: (velocity of light, c is 3×108 m/s)
(a) 0.96 gm (b) 0.8 gm (c) 4 × \times × 10− - − 2 gm (d) 6.6 × \times × 10− - − 5 gm Show answer and solution
Answer: (c)
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Q20 NEET 2013 Easy ☆
Mass Defect & Binding Energy · Binding energy curve & stability
How does the Binding Energy per nucleon vary with the increase in the number of nucleons?
(a) Decrease continuously with mass number. (b) First decreases and then increases with increase in mass number. (c) First increases and then decreases with increase in mass number. (d) increases continuously with mass number. Show answer and solution
Answer: (c)
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Q21 NEET 2010 · AIPMT · PRELIMS Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
The mass of a 3 7 L i {}_{3}^{7}Li 3 7 L i Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of 3 7 L i {}_{3}^{7}Li 3 7 L i nucleus is nearly
(a) 46 MeV (b) 5.6 MeV (c) 3.9 MeV (d) 23 MeV Show answer and solution
Answer: (b)
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Q22 JEE Main 2009 · AIEEE Difficult ☆
Mass Defect & Binding Energy · Binding energy curve & stability
The above is a plot of binding energy per nucleon E b , E_b, E b , against the nuclear mass M ; A , B , C , D , E , F M; A, B, C, D, E, F M ; A , B , C , D , E , F correspond to different nuclei. Consider four reactions:
( i ) A + B → C + ε ( i i ) C → A + B + ε (i)\ \ A + B \rightarrow C + \varepsilon \quad (ii)\ \ C \rightarrow A + B + \varepsilon ( i ) A + B → C + ε ( ii ) C → A + B + ε
( i i i ) D + E → F + ε ( i v ) F → D + E + ε , (iii)\ \ D + E \rightarrow F + \varepsilon \quad (iv)\ \ F \rightarrow D + E + \varepsilon, ( iii ) D + E → F + ε ( i v ) F → D + E + ε ,
where ε \varepsilon ε is the energy released? In which reactions is ε \varepsilon ε positive?
(a) ( i ) (i) ( i ) and ( i i i ) (iii) ( iii ) (b) ( i i ) (ii) ( ii ) and ( i v ) (iv) ( i v ) (c) ( i i ) (ii) ( ii ) and ( i i i ) (iii) ( iii ) (d) ( i ) (i) ( i ) and ( i v ) (iv) ( i v ) Show answer and solution
Answer: (d)
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Q23 NEET 2008 · AIPMT Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
If M(A; Z), Mp and Mn denote the masses of the nucleus Z A X , {}_{Z}^{A}X, Z A X , proton and neutron respectively in units of u (1 u = 931.5 MeV/c2) and BE represents its bonding energy in MeV, then
(a) M(A, Z) = ZMp + (A − - − Z)Mn − - − BE (b) M(A, Z) = ZMp + (A − - − Z)Mn + BE/c2 (c) M(A, Z) = ZMp + (A − - − Z)Mn − - − BE/c2 (d) M(A, Z) = ZMp + (A − - − Z)Mn + BE Show answer and solution
Answer: (c)
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Q24 JEE Main 2008 · AIEEE Easy ☆
Mass Defect & Binding Energy · Binding energy curve & stability
This question contains Statement- 1 and Statement- 2. Of the four choices given after the statements, choose the one that best describes the two statements:
Statement- 1:
Energy is released when heavy nuclei undergo fission or light nuclei undergo fusion. Statement- 2:
For heavy nuclei, binding energy per nucleon increases with increasing Z Z Z while for light nuclei it decreases with increasing Z . Z. Z .
(a) Statement - 1 1 1 is false, Statement - 2 2 2 is true (b) Statement - 1 1 1 is true, Statement - 2 2 2 is true; Statement - 2 2 2 is a correct explanation for Statement - 1 1 1 (c) Statement - 1 1 1 is true, Statement - 2 2 2 is true; Statement - 2 2 2 is not a correct explanation for Statement - 1 1 1 (d) Statement - 1 1 1 is true, Statement - 2 2 2 is false Show answer and solution
Answer: (d)
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Q25 NEET 2007 · AIPMT Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
A nucleus Z A X {}_{Z}^{A}X Z A X has mass represented by M(A, Z). If Mp and Mn denote the mass of proton and neutron respectively and B.E. the binding energy in MeV, then
(a) B.E. = [ZMp + (A − - − Z)Mn − - − M(A, Z)]c2 (b) B.E. = [ZMp + AMp − - − M(A, Z)]c2 (c) B.E. = M(A, Z) − - − ZMp − - − (A − - − Z)Mn (d) B.E. = [M(A, Z) − - − ZMp − - − (A − - − Z)Mn]c2 Show answer and solution
Answer: (a)
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Q26 JEE Main 2007 · AIEEE Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
If M O M_O M O is the mass of an oxygen isotope 8 O 17 , M p {}_{8}O^{17}, M_p 8 O 17 , M p and M N M_N M N are the masses of a proton and neutron respectively, the nuclear binding energy of the isotope is
(a) ( M O − 17 M N ) C 2 (M_O - 17M_N)C^{2} ( M O − 17 M N ) C 2 (b) ( M O − 8 M P ) C 2 (M_O - 8M_P)C^{2} ( M O − 8 M P ) C 2 (c) ( M O − 8 M P − 9 M N ) C 2 (M_O - 8M_P - 9M_N)C^{2} ( M O − 8 M P − 9 M N ) C 2 (d) M O c 2 M_O c^{2} M O c 2 Show answer and solution
Answer: (c)
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Q27 NEET 2004 · AIPMT Easy ☆
Mass Defect & Binding Energy · Binding energy from masses
If M(A; Z), Mp and Mn denote the masses of the nucleus Z A X , {}_{Z}^{A}X, Z A X , proton and neutron respectively in units of u (1 u = 931.5 MeV/c2) and BE represents its bonding energy in MeV, then
(a) M(A, Z) = ZMp + (A − - − Z)Mn − - − BE (b) M(A, Z) = ZMp + (A − - − Z)Mn + BE/c2 (c) M(A, Z) = ZMp + (A − - − Z)Mn − - − BE/c2 (d) M(A, Z) = ZMp + (A − - − Z)Mn + BE Show answer and solution
Answer: (c)
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Q28 NEET 2003 · AIPMT Medium ☆
Mass Defect & Binding Energy · Binding energy from masses
The mass of proton is 1.0073 u and that of neutron is 1.0087 u (u = atomic mass unit). The binding energy of 2 4 {}_{2}^{4} 2 4 He is
(Given helium nucleus mass ≈ \approx ≈ 4.0015 u.)
(a) 0.0305 J (b) 0.0305 erg (c) 28.4 MeV (d) 0.061 u Show answer and solution
Answer: (c)
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Q29 JEE Main 2002 · AIEEE Easy ☆
Mass Defect & Binding Energy · Mass-energy equivalence & atomic mass unit
If mass-energy equivalence is taken into account, when water is cooled to form ice, the mass of water should
(a) increase (b) remain unchanged (c) decrease (d) first increase then decrease Show answer and solution
Answer: (c)
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Q30 NEET 2001 · AIPMT Easy ☆
Mass Defect & Binding Energy · Mass defect
Mn and Mp represent the mass of neutron and proton respectively. An element having mass M has N neutrons and Z protons, then the correct relation will be
(a) M < {N ⋅ \cdot ⋅ Mn + Z ⋅ \cdot ⋅ Mp} (b) M > {N ⋅ \cdot ⋅ Mn + Z ⋅ \cdot ⋅ Mp} (c) M = {N ⋅ \cdot ⋅ Mn + Z ⋅ \cdot ⋅ Mp} (d) M = N {Mn + Mp} Show answer and solution
Answer: (a)
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Q31 NEET 1993 · AIPMT Easy ☆
Mass Defect & Binding Energy · Binding energy curve & stability
The binding energy per nucleon is maximum in case of
(a) 2 4 He {}_{2}^{4}\text{He} 2 4 He (b) 26 56 Fe {}_{26}^{56}\text{Fe} 26 56 Fe (c) 56 141 Ba {}_{56}^{141}\text{Ba} 56 141 Ba (d) 92 235 U {}_{92}^{235}\text{U} 92 235 U Show answer and solution
Answer: (b)
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Q32 NEET 1992 · AIPMT Easy ☆
Mass Defect & Binding Energy · Mass-energy equivalence & atomic mass unit
The energy equivalent of one atomic mass unit is
(a) 1.6 × 1 0 − 19 J 1.6 \times 10^{-19}\text{ J} 1.6 × 1 0 − 19 J (b) 6.02 × 1 0 23 J 6.02 \times 10^{23}\text{ J} 6.02 × 1 0 23 J (c) 931 MeV (d) 9.31 MeV Show answer and solution
Answer: (c)
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Q33 NEET 1992 · AIPMT Easy ☆
Mass Defect & Binding Energy · Mass defect
The mass of α \alpha α -particle is
(a) less than the sum of masses of two protons and two neutrons (b) equal to mass of four protons (c) equal to mass of four neutrons (d) equal to sum of masses of two protons and two neutrons Show answer and solution
Answer: (a)
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Q34 NEET 1989 · AIPMT Easy ☆
Mass Defect & Binding Energy · Binding energy curve & stability
The average binding energy of a nucleon inside an atomic nucleus is about
(a) 8 MeV (b) 8 eV (c) 8 J (d) 8 erg Show answer and solution
Answer: (a)
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