Nuclear Reactions & Q-value

Which one of the following is possible nuclear reaction?

Consider the following nuclear reaction

${}^{238}\text{U} \longrightarrow {}^{234}\text{Th} + {}^{4}\text{He}$

Take masses of ${}^{238}\text{U}, {}^{234}\text{Th}$ and ${}^{4}\text{He}$ as $238.050\text{u}, 234.043\text{u}$ and 4.003 u, respectively. The $Q$ value for the reaction, in keV, is:

[Given: $1\text{u} = 931.5\text{ MeV c}^{-2}$ ]

The minimum frequency of photon required to break a particle of mass 15.348 amu into $4\alpha$ particles is ______ kHz.

[mass of He nucleus = $4.002\text{ amu}, 1\text{ amu} = 1.66 \times 10^{-27}\text{ kg}, \text{h} = 6.6 \times 10^{-34}\text{ J.s}$ and $\text{c} = 3 \times 10^{8}\text{ m/s}$ ]

Two radioactive substances A and B of mass numbers 200 and 212 respectively, shows spontaneous $\alpha$-decay with same $Q$ value of 1 MeV. The ratio of energies of $\alpha$-rays produced by A and B is ______.

The energy released when $\frac{7}{17.13}\text{ kg}$ of ${}^{7}_{3}\text{Li}$ is converted into ${}^{4}_{2}\text{He}$ by proton bombardment is $\alpha \times 10^{32}\text{ eV}$. The value of $\alpha$ is ______. (Nearest integer) (Mass of ${}^{7}_{3}\text{Li} = 7.0183\text{u}$, mass of ${}^{4}_{2}\text{He} = 4.004\text{u}$, mass of proton $= 1.008\text{u}$ and $1\text{u} = 931\text{ MeV/c}^{2}$ and Avogadro number $= 6.0 \times 10^{23}$)

For the following reaction, the particle ' X ' is

${}_{6}\text{C}^{11} \longrightarrow {}_{5}\text{B}^{11} + \beta + \text{X}$

A nucleus at rest disintegrates into two smaller nuclei with their masses in the ratio of $2 : 1$. After disintegration they will move:

${}^{238}_{92}A \rightarrow {}^{234}_{90}B + {}^{4}_{2}D + Q$

In the given nuclear reaction, the approximate amount of energy released will be: [Given, mass of ${}^{238}_{92}\text{A} = 238.05079 \times 931.5\text{ MeV/c}^{2},$

mass of ${}^{234}_{90}B = 234.04363 \times 931.5\text{ MeV/c}^{2},$

mass of ${}^{4}_{2}D = 4.00260 \times 931.5\text{ MeV/c}^{2}]$

A common example of alpha decay is ${}^{238}_{92}\text{U} \longrightarrow {}^{234}_{90}\text{Th} + {}_{2}\text{He}^{4} + \text{Q}$

Given:

${}^{238}_{92}\text{U} = 238.05060\text{ u}$,

${}^{234}_{90}\text{Th} = 234.04360\text{ u}$,

${}^{4}_{2}\text{He} = 4.00260\text{ u}$ and

$1\text{u} = 931.5\frac{\text{MeV}}{c^{2}}$

The energy released $(Q)$ during the alpha decay of ${}^{238}_{92}\text{U}$ is __________ MeV

In the given nuclear reaction, the element X is

${}_{11}^{22}Na \rightarrow X + e^{+} + \nu$

A nucleus of mass $M$ at rest splits into two parts having masses $\frac{M'}{3}$ and $\frac{2M'}{3}\,(M' < M)$. The ratio of de Broglie wavelength of two parts will be:

The Q-value of a nuclear reaction and kinetic energy of the projectile particle, Kp are related as:

A nucleus with mass number 184 initially at rest emits an $\alpha$-particle. If the Q value of the reaction is 5.5 MeV, calculate the kinetic energy of the $\alpha$-particle.

A nucleus of mass M emits $\gamma$ -ray photon of frequency 'v'. The loss of internal energy by the nucleus is:

[Take 'c' as the speed of electromagnetic wave]

You are given that Mass of ${}^{7}_{3}Li$ = 7.0160u,

Mass of ${}^{4}_{2}He$ = 4.0026u

and Mass of ${}^{1}_{1}H$ = 1.0079u.

When 20 g of ${}^{7}_{3}Li$ is converted into ${}^{4}_{2}He$ by proton capture, the energy liberated, (in kWh), is: [Mass of nucleon = 1 GeV/c2]

A nucleus of uranium decays at rest into nuclei of thorium and helium. Then

The binding energy per nucleon of ${}^{7}_{3}Li$ and ${}^{4}_{2}He$ nuclei are 5.60 MeV and 7.06 MeV respectively. In the nuclear reaction

${}^{7}_{3}Li + {}^{1}_{1}H \rightarrow {}^{4}_{2}He + {}^{4}_{2}He + Q$

the value of energy Q released is

A radioactive nucleus of mass M emits a photon of frequency $v$ and the nucleus recoils. The recoil energy will be

A nucleus of mass $M + \Delta m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $c.$

The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}.$ Then

A nucleus of mass $M + \Delta m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $c.$

The speed of daughter nuclei is

When ${}_{3}Li^{7}$ nuclei are bombarded by protons, and the resultant nuclei are ${}_{4}Be^{8}$, the emitted particles will be

If the binding energy per nucleon in ${}^{7}_{3}Li$ and ${}^{4}_{2}He$ nuclei are $5.60\text{ MeV}$ and $7.06\text{ MeV}$ respectively, then in the reaction

$p + {}^{7}_{3}Li \rightarrow 2\,{}^{4}_{2}He$

energy of proton must be

A nuclear transformation is denoted by $X\,(n, \alpha)\,{}_{3}^{7}Li.$ Which of the following is the nucleus of element $X$?

In the reaction ${}_{1}^{2}$H + ${}_{1}^{3}$H $\rightarrow {}_{2}^{4}$He + ${}_{0}^{1}$n, if the binding

energies of ${}_{1}^{2}$ H, ${}_{1}^{3}$H and ${}_{2}^{4}$He are respectively a, b and c (in MeV),

then the energy (in MeV) released in this reaction is

When a $U^{238}$ nucleus originally at rest, decays by emitting an alpha particle having a speed ${}^{\prime}u^{\prime},$ the recoil speed of the residual nucleus is

A deuteron is bombarded on 8O16 nucleus then $\alpha$-particle is emitted. The product nucleus is

X(n, $\alpha$) ${}_{3}^{7}$Li, then X will be

For the given reaction, the particle X is

${}_{6}C^{11} \rightarrow {}_{5}B^{11} + \beta^{+} + X$