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Rotational Motion PYQs · MHT CET · JEE Main · NEET

Torque, Couple & Equilibrium of Rigid Bodies

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51
MHT CET
9
JEE Main
29
NEET
13
Years
1995–2026
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Q1MHT CET 2026 · 19 APR · SHIFT 2Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

A force of 3i^+2j^−k^3\hat{i}+2\hat{j}-\hat{k} N acts on a particle with position vector i^+j^−k^\hat{i}+\hat{j}-\hat{k} m. The magnitude of torque of given force is

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Answer: (c)

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Q2MHT CET 2026 · 12 MAY · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Couple & torque concepts

In the case of rotational dynamics, which of the following statements is correct? {SS = linear displacement, α\alpha = angular acceleration, rr = radius vector, aa = linear acceleration, LL = angular momentum, pp = linear momentum, θ\theta = angular displacement}

1. S=r×θ,a=r×α,L=p×rS = r \times \theta, a = r \times \alpha, L = p \times r

2. S=θ×r,a=α×r,L=r×pS = \theta \times r, a = \alpha \times r, L = r \times p

3. S=r⋅θ,a=r⋅α,L=p⋅rS = r \cdot \theta, a = r \cdot \alpha, L = p \cdot r

4. S=ω×r,a=r×p,L=r×fS = \omega \times r, a = r \times p, L = r \times f

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Answer: (c)

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Q3MHT CET 2026 · 12 MAY · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Couple & torque concepts

Which of the following sentence is true?

a. Moment of a couple is independent of the axis of rotation or the points of application of forces. b. Moment of a couple produces translational acceleration.

c. Moment of a couple can be balanced by single force.

d. Moment of a couple depends upon the axis of rotation or the points of application of forces.

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Answer: (d)

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Q4MHT CET 2025 · 22 APR · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

If force F⃗=−3i^+j^+5k^\vec{F} = -3\hat{i}+\hat{j}+5\hat{k} acts along r⃗=7i^+3j^+k^\vec{r} = 7\hat{i}+3\hat{j}+\hat{k} then the torque acting at that point is

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Answer: (a)

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Q5MHT CET 2025 · 19 APR · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

If F⃗=(5i^−10j^)\vec{F} = (5\hat{i}-10\hat{j}) and r⃗=(4i^−3j^)\vec{r} = (4\hat{i}-3\hat{j}), then the torque acting on the object will be

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Answer: (d)

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Q6JEE Main 2025 · 22 JAN · SHIFT 2Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

The torque due to the force (2i^+j^+2k^)(2\hat{i}+\hat{j}+2\hat{k}) about the origin, acting on a particle whose position vector is (i^+j^+k^)(\hat{i}+\hat{j}+\hat{k}), would be

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Answer: (b)

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Q7JEE Main 2025 · 29 JAN · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

The coordinates of a particle with respect to origin in a given reference frame is (1, 1, 1) meters. If a force of F⃗=i^−j^+k^\vec{F} = \hat{i} - \hat{j} + \hat{k} acts on the particle, then the magnitude of torque (with respect to origin) in z- direction is __________.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

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Q8JEE Main 2025 · 4 APR · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Couple & torque concepts

Which of the following are correct expression for torque acting on a body?

A. τ⃗=r⃗×L⃗\vec{\tau} = \vec{r} \times \vec{L}

B. τ⃗=ddt(r⃗×p⃗)\vec{\tau} = \frac{d}{dt}(\vec{r} \times \vec{p})

C. τ⃗=r⃗×dp⃗dt\vec{\tau} = \vec{r} \times \frac{d\vec{p}}{dt}

D. τ⃗=Iα⃗\vec{\tau} = I\vec{\alpha}

E. τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F}

( r⃗=\vec{r} = position vector; p⃗=\vec{p} = linear momentum; L⃗=\vec{L} = angular momentum; α⃗=\vec{\alpha} = angular acceleration; I=I = moment of inertia; F⃗=\vec{F} = force; t=t = time)

Choose the correct answer from the options given below:

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Answer: (c)

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Q9JEE Main 2025 · 2 APR · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

A square Lamina OABC of length 10 cm is pivoted at ' O\text{O} '. Forces act at Lamina as shown in figure. If Lamina remains stationary, then the magnitude of F is:

Figure

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Answer: (a)

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Q10JEE Main 2025 · 28 JAN · SHIFT 2Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is

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Answer: (c)

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Q11NEET 2025Medium

Torque, Couple & Equilibrium of Rigid Bodies · Ladder, step & toppling

A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of 60∘60^\circ with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (Take g=10 m/s2g = 10\text{ m/s}^{2})

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Answer: (d)

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Q12MHT CET 2024 · 3 MAY · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Couple & torque concepts

In case of rotational dynamics, which one of the following statements is correct? [ω⃗=\vec{\omega} = angular velocity,v⃗=\vec{v} = linear velocity

r⃗=\vec{r} = radius vector, α⃗=\vec{\alpha} = angular acceleration

a⃗=\vec{a} = linear acceleration,L⃗=\vec{L} = angular momentum

p⃗=\vec{p} = linear momentum, τ⃗=\vec{\tau} = torque,

f⃗=\vec{f} = centripetal force]

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Answer: (c)

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Q13JEE Main 2024 · 9 APR · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Ladder, step & toppling

A heavy iron bar, of weight WW is having its one end on the ground and the other on the shoulder of a person. The bar makes an angle θ\theta with the horizontal. The weight experienced by the person is:

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Answer: (c)

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Q14JEE Main 2024 · 27 JAN · SHIFT 2Medium

Torque, Couple & Equilibrium of Rigid Bodies · Ladder, step & toppling

A heavy iron bar of weight 12 kg12\text{ kg} is having its one end on the ground and the other on the shoulder of a man. The rod makes an angle 60∘60^\circ with the horizontal, the weight experienced by the man is:

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Answer: (a)

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Q15JEE Main 2023 · 10 APR · SHIFT 2Easy

Torque, Couple & Equilibrium of Rigid Bodies · Couple & torque concepts

Given below are two statements: one is labelled as Assertion A\mathbf{A} and the other is labelled as Reason R\mathbf{R}

Assertion A: An electric fan continues to rotate for some time after the current is switched off. Reason R: Fan continues to rotate due to inertia of motion.

In the light of above statements, choose the most appropriate answer from the options given below.

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Answer: (c)

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Q16JEE Main 2023 · 10 APR · SHIFT 2Medium

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

A force of −Pk^-P\hat{k} acts on the origin of the coordinate system. The torque about the point (2,−3)(2, -3) is P(ai^+bj^)P(a\hat{i} + b\hat{j}). The ratio of ab\frac{a}{b} is x2\frac{x}{2}. The value of xx is ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 3

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Q17JEE Main 2023 · 25 JAN · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

An object of mass 8 kg is hanging from one end of a uniform rod CD of mass 2 kg and length 1 m pivoted at its end C on a vertical wall as shown in figure. It is supported by a cable AB such that the system is in equilibrium. The tension in the cable is (Take g = 10 m/s22)

Figure

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Answer: (d)

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Q18JEE Main 2022 · 29 JUL · SHIFT 2Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

The torque of a force 5i^+3j^−7k^5\hat{i}+3\hat{j}-7\hat{k} about the origin is τ\tau. If the force acts on a particle whose position vector is 2i^+2j^+k^2\hat{i}+2\hat{j}+\hat{k}, then the value of τ\tau will be

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Answer: (c)

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Q19JEE Main 2022 · 25 JUN · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

If force F⃗=3i^+4j^−2k^\vec{F} = 3\hat{i}+4\hat{j}-2\hat{k} acts on a particle position vector 2i^+j^+2k^2\hat{i}+\hat{j}+2\hat{k} then, the torque about the origin will be:

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Answer: (b)

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Q20JEE Main 2022 · 24 JUN · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

A metre scale is balanced on a knife edge at its centre. When two coins, each of mass 10 g are put one on the top of the other at the 10.0 cm mark the scale is found to be balanced at 40.0 cm mark. The mass of the metre scale is found to be x ×\times 10−-2 kg. The value of x is ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 6

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Q21JEE Main 2022 · 28 JUN · SHIFT 2Medium

Torque, Couple & Equilibrium of Rigid Bodies · Ladder, step & toppling

A 34\sqrt{34} m long ladder weighing 10 kg leans on a frictionless wall. Its feet rest on the floor 3 m away from the wall as shown in the figure. If Ff and Fw are the reaction forces of the floor and the wall, then ratio of Fw/FfF_w/F_f will be:

(Use g = 10 m/s2.)

Figure

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Answer: (c)

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Q22JEE Main 2021 · 17 MAR · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

A triangular plate is shown. A force F⃗\vec{F}= 4i^−\hat{i} - 3j^\hat{j} is applied at point P. The torque at point P with respect to point 'O' and 'Q' are:

Figure

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Answer: (d)

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Q23JEE Main 2021 · 16 MAR · SHIFT 2Medium

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

A force F⃗=4i^+3j^+4k^\vec{F} = 4\hat{i} + 3\hat{j} + 4\hat{k} is applied on an intersection point of x = 2 plane and x-axis. The magnitude of torque of this force about a point (2, 3, 4) is ___________. (Round off to the Nearest Integer)

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Answer: 20

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Q24MHT CET 2021 · 23 SEP · SHIFT 2Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

A metre scale is supported on a wedge at its centre of gravity. A body of weight 'w' is suspended from the 20 cm20\text{ cm} mark and another weight of 25 gram is suspended from 74 cm74\text{ cm} mark to balance it and the metre scale remains perfectly horizontal. Neglecting the weight of the metre scale, the weight of the body is

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Answer: (a)

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Q25NEET 2021Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

A uniform rod of length 200 cm and mass 500 g is balanced on a wedge placed at 40 cm mark. A mass of 2 kg is suspended from the rod at 20 cm and another unknown mass 'm' is suspended from the rod at 160 cm mark as shown in the figure. Find the value of 'm' such that the rod is in equilibrium. (g = 10 m/s2)

Figure

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Answer: (a)

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Q26JEE Main 2021 · 16 MAR · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Ladder, step & toppling

Consider a frame that is made up of two thin massless rods AB and AC as shown in the figure. A vertical force P⃗\vec{P}of magnitude 100 N is applied at point A of the frame.

Figure

Suppose the force P⃗\vec{P}is resolved parallel to the arms AB and AC of the frame.

The magnitude of the resolved component along the arm AC is xN.

The value of x, to the nearest integer, is ___________.

[Given: sin(35∘^\circ) = 0.573, cos(35∘^\circ) = 0.819

sin(110∘^\circ) = 0.939, cos(110∘^\circ) = −- 0.342]

Numerical answer type. Work it out, then open the answer.

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Answer: 82

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Q27NEET 2020 · PHASE 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

Find the torque about the origin when a force of 3 j^\hat{j} N acts on a particle whose position vector is 2 k^\hat{k} m.

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Answer: (b)

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Q28JEE Main 2020 · 5 SEP · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

A force F⃗=(i^+2j^+3k^)\vec{F} = \left(\hat{i} + 2\hat{j} + 3\hat{k}\right) N acts at a point

(4i^+3j^−k^)\left(4\hat{i} + 3\hat{j} - \hat{k}\right) m. Then the magnitude of torque

about the point (i^+2j^+k^)\left(\hat{i} + 2\hat{j} + \hat{k}\right) m will be x\sqrt{x} N m.

The value of x is _______.

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Answer: 195

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Q29JEE Main 2020 · 2 SEP · SHIFT 1Difficult

Torque, Couple & Equilibrium of Rigid Bodies · Ladder, step & toppling

A uniform cylinder of mass M and radius R is to be pulled over a step of height a (a < R) by applying a force F at its centre ‘O’ perpendicular to the plane through the axes of the cylinder on the edge of the step (see figure). The minimum value of F required is:

Figure

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Answer: (a)

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Q30JEE Main 2020 · 7 JAN · SHIFT 2Difficult

Torque, Couple & Equilibrium of Rigid Bodies · Ladder, step & toppling

Figure

Consider a uniform cubical box of side a on a rough floor that is to be moved by applying minimum possible force F at a point b above its centre of mass (see figure). If the coefficient of friction is μ\mu = 0.4, the maximum possible value of 100 × ba\frac{b}{a} for box not to topple before moving is .......

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Answer: 50

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Q31JEE Main 2019 · 11 JAN · SHIFT 2Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians):

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Answer: (b)

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Q32MHT CET 2019 · 3 MAY · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Couple & torque concepts

A rod l ml\text{ m} long is acted upon by a couple as shown in the figure. The moment of couple is τ N m\tau\text{ N m}. If the force acts at each end of the rod, then magnitude of each force is

(sin⁡30∘=cos⁡60∘=0.5)(\sin 30^\circ = \cos 60^\circ = 0.5)

Figure

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Answer: (c)

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Q33MHT CET 2019 · 2 MAY · SHIFT 1Easy

Torque, Couple & Equilibrium of Rigid Bodies · Couple & torque concepts

The dimensions of torque are same as that of

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Answer: (a)

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Q34JEE Main 2019 · 11 JAN · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

A slab is subjected to two forces F1⃗\vec{F_1} and F2⃗\vec{F_2} of same magnitude F as shown in the figure. Force F2⃗\vec{F_2} is in XY-plane while force F1⃗\vec{F_1} acts along z = axis at the point (2i⃗+3j⃗).\left(2\vec{i} + 3\vec{j}\right).. The moment of these forces about point O will be:

Figure

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Answer: (d)

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Q35JEE Main 2019 · 9 JAN · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

An L-shaped object, made of thin rods of uniform mass density, is suspended with a string as shown in figure. If AB = BC, and the angle made by AB with downward vertical is θ\theta, then:

Figure

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Answer: (d)

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Q36NEET 2018Easy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

The moment of the force, F⃗=4i^+5j^−6k^\vec{F} = 4\hat{i}+5\hat{j}-6\hat{k} at

(2, 0, –3), about the point (2, –2, –2), is given by

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Answer: (d)

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Q37JEE Main 2018 · 15 APR · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

A force of 40 N40\text{ N} acts on a point BB at the end of an LL-shaped object, as shown in the figure. The angle θ\theta that will produce maximum moment of the force about point AA is given by:

Figure

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Answer: (a)

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Q38JEE Main 2018 · 15 APR · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

Figure

A uniform rod ABAB is suspended from a point X,X, at a variable distance xx from AA, as shown. To make the rod horizontal, a mass mm is suspended from its end A.A. A set of (m,x)(m, x) values is recorded. The appropriate variables that give a straight line, when plotted, are:

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Answer: (b)

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Q39JEE Main 2017 · 8 APR · SHIFT 1Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

In a physical balance working on the principle of moments, when 5 mg weight is placed on the left pan, the beam becomes horizontal. Both the empty pans of the balance are of equal mass. Which of the following statements is correct?

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Answer: (c)

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Q40JEE Main 2017 · 9 APR · SHIFT 1Difficult

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

The machine as shown has 2 rods of length1 m connected by a pivot at the top. The end of one rod is connected to the floor by a stationary pivot and the end of the other rod has a roller that rolls along the floor in a slot. As the roller goes back and forth, a 2 kg weight moves up and down. If the roller is moving towards right at a constant speed, the weight moves up with a:

Figure

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Answer: (b)

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Q41NEET 2015 · AIPMT · CANCELLED PAPERMedium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

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Answer: (b)

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Q42NEET 2013Medium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

A rod PQ of mass M and length L is hinged at end P. The rod is kept horizontal by a massless string tied to point Q as shown in figure. When string is cut, the initial angular acceleration of the rod is

Figure

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Answer: (c)

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Q43NEET 2012 · AIPMT · PRELIMSMedium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

ABC is an equilateral triangle with O as its centre. F1⃗,F2⃗\vec{F_1}, \vec{F_2} and F3⃗\vec{F_3} represent three forces acting along the sides AB, BC and AC respectively. If the total torque about O is zero then magnitude of F3⃗\vec{F_3} is

Figure

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Answer: (a)

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Q44NEET 2009 · AIPMTEasy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

If F⃗\vec{F}is the force acting on a particle having position vectorr⃗\vec{r}and τ⃗\vec{\tau}be the torque of this force about the origin, then

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Answer: (b)

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Q45JEE Main 2006 · AIEEEEasy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

A force of −Fk^-F\hat{k} acts on O,O, the origin of the coordinate system. The torque about the point (1,−1)(1,-1) is

Figure

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Answer: (b)

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Q46JEE Main 2003 · AIEEEEasy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

Let F⃗\vec{F}be the force acting on a particle having position vectorr⃗,\vec{r}, andτ⃗\vec{\tau}be the torque of this force about the origin. Then

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Answer: (d)

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Q47NEET 1998 · AIPMTMedium

Torque, Couple & Equilibrium of Rigid Bodies · Equilibrium: rods, scales & beams

OO is the centre of an equilateral triangle ABC. F1, F2ABC.\ F_1,\ F_2 and F3F_3 are three forces acting along the sides AB, BCAB,\ BC and ACAC as shown in figure. What should be the magnitude of F3F_3 so that the total torque about OO is zero?

Figure

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Answer: (c)

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Q48NEET 1998 · AIPMTMedium

Torque, Couple & Equilibrium of Rigid Bodies · Ladder, step & toppling

A weightless ladder 20 ft20\text{ ft} long rests against a frictionless wall at an angle of 60∘60^\circ from the horizontal. A 150150 pound man is 4 ft4\text{ ft} from the top of the ladder. A horizontal force is needed to keep it from slipping. Choose the correct magnitude of force from the following:

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Answer:

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Q49NEET 1997 · AIPMTEasy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

Find the torque of a force F⃗=−3i^+j^+5k^\vec{F} = -3\hat{i}+\hat{j}+5\hat{k} acting at the point r⃗=7i^+3j^+k^\vec{r} = 7\hat{i}+3\hat{j}+\hat{k}.

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Answer: (c)

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Q50NEET 1997 · AIPMTEasy

Torque, Couple & Equilibrium of Rigid Bodies · Couple & torque concepts

A couple produces

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Answer: (d)

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Q51NEET 1995 · AIPMTEasy

Torque, Couple & Equilibrium of Rigid Bodies · Torque as a vector (r × F)

What is the torque of the force F⃗=2i^−3j^+4k^ N\vec{F} = 2\hat{i}-3\hat{j}+4\hat{k}\text{ N} acting at the point r⃗=3i^+2j^+3k^ m\vec{r} = 3\hat{i}+2\hat{j}+3\hat{k}\text{ m} about origin?

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Answer: (d)

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